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RRB JE Electrical (CBT II) Mock Test- 7 - Electrical Engineering (EE) MCQ


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30 Questions MCQ Test - RRB JE Electrical (CBT II) Mock Test- 7

RRB JE Electrical (CBT II) Mock Test- 7 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The RRB JE Electrical (CBT II) Mock Test- 7 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The RRB JE Electrical (CBT II) Mock Test- 7 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE Electrical (CBT II) Mock Test- 7 below.
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RRB JE Electrical (CBT II) Mock Test- 7 - Question 1

How does energy travel from the sun to the earth?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 1

Radiation is the transfer of heat energy through space by electromagnetic radiation.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 2

What will be the skin effect when the the frequency is increased?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 2

Skin effect is the tendency of an alternating electric current (AC) to become distributed within a conductor such that the current density is largest near the surface of the conductor, and decreases with greater depths in the conductor.

If frequency is increased, skin effect will increases.

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RRB JE Electrical (CBT II) Mock Test- 7 - Question 3

......... connection can be used in a transformer to intoduce a phase difference of 30 degrees between its output and corresponding input time voltages.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 3

Star - delta connection can be used in a transformer to intoduce a phase difference of 30 degrees between its output and corresponding input time voltages.

It can be noted that in a star - delta connection the phase shift of 30° between primary line voltage and secondary line voltage as leading.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 4

In Microsoft Word, File, edit, view etc. are provided in _______________.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 4

A menu bar is a graphical control element which has drop-down menus. Its purpose is to supply a common housing for window-or application-specific menus which provide access to such functions as opening files, interacting with an application, or displaying help documentation or manuals.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 5

The minimum clearance between the ground and a 220 KV line is about-

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 5

minimum ground clearance of 33KV uninsulated electrical conductor is 5.2 meter and 0.3 meter for every 33KV above 33KV.
So, for first 33 kv, 5.2 metres and for next (220-33) = 187kv, 187/33 = 5.66 for which 5.66*0.3mt = 1.7 mt
In total 5.2 + 1.7 = 6.9 metres for 220 kv

RRB JE Electrical (CBT II) Mock Test- 7 - Question 6

What is the process taking place in a fluorescent tube called ?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 6

A fluorescent lamp tube is filled with a gas containing low-pressure mercury vapor and argon, xenon, neon, or krypton. The pressure inside the lamp is around 0.3% of atmospheric pressure.The inner surface of the lamp is coated with a fluorescent coating made of varying blends of metallic and rare-earth phosphor salts. The lamp's electrodes are typically made of coiled tungsten and usually referred to as cathodes because of their prime function of emitting electrons. For this, they are coated with a mixture of barium, strontium and calcium oxides chosen to have a low thermionic emission. temperature.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 7

Ferrite cores are used in high frequency transformer because it has:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 7

Ferrite core is a type of magnetic core made of ferrite on which the windings of electric transformers and other wound components such as inductors are formed.

It is used for its properties of high magnetic permeability coupled with low electrical conductivity (high resistance)

It helps in preventing eddy currents

RRB JE Electrical (CBT II) Mock Test- 7 - Question 8
Which type of machine is used in tape recorder ?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 8
Hysteresis motor is used in tape recorder Because it develops very steady torque.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 9
The distribution transformer is generally connected in__________.
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 9
Distribution transformers are connected in delta-star. This arrangement requires 3 conductors in the high voltage side and 4 in the low voltage side, as well as it provides the star point conductor as a neutral point. This can serve single phase as well as three phase loads.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 10
What is the approximate value of average resistance of a human body?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 10
Under dry conditions, the resistance offered by the human body may be as high as one megaohm. Wet or broken skin may drop the body's resistance to 1000 ohms. Adding that, high-voltage electrical energy quickly breaks down human skin, reducing the human body's resistance to 500 ohms.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 11
Where has the second India-Myanmar bilateral Army exercise named 'IMBEX 2018-19' commenced on 14 January 2019?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 11
  • The second India-Myanmar bilateral Army exercise named 'IMBEX 2018-19' commenced at Chandimandir military station in Haryana on 14 January 2019.
  • The aim of this joint training event is to train the Myanmar delegation for participation in UN peacekeeping operations.
  • The exercise includes participation of 15 officers from Myanmar Army and 15 officers from Indian Army
RRB JE Electrical (CBT II) Mock Test- 7 - Question 12

The power dissipation in a transistor is the product of

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 12

The power dissipated by a transistor is equal to the product (multiplication) of collector current and collector-emitter voltage.
P = VCE × IC

RRB JE Electrical (CBT II) Mock Test- 7 - Question 13
Least suitable transducer for static pressure measurement is-
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 13

A pressure transducer is used to convert a certain value of pressure into its corresponding mechanical or electrical output.

The transducers used for static pressure measurement are

  • Semi-conductor strain gauge
  • Variable capacitor for transducer
  • Piezoelectric transducer
Metal wire strain gauge is least suitable for static pressure measurement.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 14

In series RL circuit, the voltage across the resistance is 40 V and voltage across the inductance is 40 V. Then the total voltage across the series circuit is

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 14

Voltage across resistor (VR) = 40 V
Voltage across (VL) = 40 V

RRB JE Electrical (CBT II) Mock Test- 7 - Question 15

An RL series AC circuit has R = 10 ohm and XL = 10 ohms. It is connected to an AC voltage source, the phase angle between voltage and current is

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 15

R = 10 ohm and XL = 10 ohm
Impedance of RL circuit is, Z = √R2 + X2L
⇒ Z = √102 + 102 = 10√2Ω
Power factor ø = R/Z = 10/10√2 = 0.707
⇒ Phase difference (ϕ) = 45°

RRB JE Electrical (CBT II) Mock Test- 7 - Question 16

The source of a magnetic field is

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 16

According to Faraday's law, the current flowing through a coil produces the magnetic field. Hence the source of a magnetic field is the current loop.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 17
An LC circuit resonant at 1000 kHz has a Q of 100. The band width between half power points equals:
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 17

We know that

Band width = resonant frequency/Quality factor = 1000/100 = 10 kHz

Half power point = ω1 = ω0 + Δω/2 = 1000 + 10/2 = 1005 kHz

Half power point = ω2 = ω0 + Δω/2 = 1000 - 10/2 = 995 kHz
RRB JE Electrical (CBT II) Mock Test- 7 - Question 18
The resistance of a wire is 2 Ω. If the diameter of the wire is reduced to half, keeping the same length, the resistance will be
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 18

1) Resistance is proportional to length: When wire length becomes half, the resistance becomes half

2) Resistance is inversely proportional to the cross-sectional area: Diameter, becomes half, area reduces by the square of diameter i.e. 1/4 times; Therefore, resistance becomes 4 times more

Keeping points 1 and 2 together, the resistance becomes 4 times.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 19

Ferromagnetism is:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 19

Ferromagnetism is the phenomenon in which on application of a magnetising force, the domains become aligned to produce a strong magnetic field within the part which is shown in figure

RRB JE Electrical (CBT II) Mock Test- 7 - Question 20
An irregular surface with various landforms such as mountains, plateaus, plants, valleys, etc is
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 20

The surface of the earth is a complex zone in which three main components of the environment meet, overlap and interact.

  • The solid portion of the earth on which we live is called the Lithosphere
  • The gaseous layers that surround the earth, is the Atmosphere, where oxygen, nitrogen, carbon dioxide and other gases are found
  • Water covers a very big area of the earth’s surface and this area is called the Hydrosphere; The Hydrosphere comprises water in all its forms, that is, ice, water and water vapour
  • The Biosphere is the narrow zone where we find land, water and air together, which contains all forms of life

Lithosphere

The lithosphere is the solid crust or the hard top layer of the earth. It is made up of rocks and minerals and covered by a thin layer of soil. It is an irregular surface with various landforms such as mountains, plateaus, plains, valleys, etc.

The lithosphere is the domain that provides us with forests, grasslands for grazing, land for agriculture and human settlements. It is also a source of mineral wealth.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 21

According to Maximum Power Transfer Theorem, maximum power is transferred from an AC network to a load when ________.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 21

According to maximum power transfer theorem, in AC circuits the load impedance should be the complex conjugate of the internal impedance of the active network
Z L = Z* th 

RRB JE Electrical (CBT II) Mock Test- 7 - Question 22

For the network shown in the figure, the value of current in 8 Ω resistor is

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 22

Current drawn from the source
I = 48/20||(12 + 8) 
⇒ I = 4/10 = 4.8A
Current in 8 Ω resistor
I 8 Ω = 4.8/20 + 20 x 20 
I 8 Ω = 2.4 A

RRB JE Electrical (CBT II) Mock Test- 7 - Question 23
What will be the produced mmf (in Amp-turns) in a magnetic circuit, if it has 100 number of turns and carrying a current of 0.2 A?
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 23

Given that, number of turns (N) = 100

Current (I) = 0.2 A

Mmf = NI = 100 × 0.2 = 20 Amp-turns
RRB JE Electrical (CBT II) Mock Test- 7 - Question 24

A shunt resistor is connected across the contacts of a circuit breaker in order to:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 24

Resistance switching:

  • It is a method adopted for dampening the over-voltage transients due to current chopping.
  • In this method, a shunt resistance is connected across the contacts of the circuit breaker.
  • It reduces the rate of rising of re-striking voltage and the peak value of re-striking voltage.
  • It helps to reduce the voltage transient surge during current chopping and capacitive current breaking.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 25
To reverse the direction of rotation of a capacitor start motor while it is running, we should
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 25

The direction of rotation of a capacitor start motor can be reversed by reversing the connection of the main winding or auxiliary winding.

To reverse the direction of rotation of a capacitor start motor while it is running, we should disconnect the motor from the supply till it stops then reconnect it to supply with the reversed connection of main or auxiliary winding.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 26

Determine the quality factor for Maxwell’s inductance capacitance bridge given below when the bridge is supplied by a frequency of 50 Hz.

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 26

Z1 Z4 =Z2 Z


(R + jwLx) (1/ 60wC ) = 35/4 (1 + 60²ω²C²)
Rx + 60ω²C Lx+ j(ωLx- 60RxωC) = 35/4 (1+60²ω²C²)
Compare real parts of the above equation,
Rx + 60ω²CLx = 35/4 (1 + 60²ω²C²)
Rx = 35/4 Ω
And, 60ω²CLx = 35/4 ×60²ω²C²
⇒ Lx = 35/4 × 60 × C = 35/4 × 60 × 25 × 10-6 = 13.125 mH
Quality factor, Q = ωLx /Rx = 2πfL/Rx = 2π × 50 × 13.125 × 10-3 / 35/4 = 0.47

RRB JE Electrical (CBT II) Mock Test- 7 - Question 27

Approximate quantity of CO2 in the atmosphere in PPM (parts per million) is:

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 27

Approximate quantities of different gases in the atmosphere in PPM are given below.

RRB JE Electrical (CBT II) Mock Test- 7 - Question 28
The starting torque and power factor of shaded pole induction motor
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 28
  • The power losses are very high in the shaded pole induction motor
  • The power factor of the motor is low
  • The starting torque induces in the induction motor are also very low
  • The efficiency is also very low

Important Point:

  • The shaded pole induction motor is simply a self-starting single-phase induction motor whose one of the poles is shaded by the copper ring
  • The copper ring is also called the shaded ring
  • This copper ring act as a secondary winding for the motor
  • The shaded pole motor rotates only in one particular direction, and the reverse movement of the motor is not possible
  • The direction of rotation of the magnetic field is from nonshaded pole to shaded pole
RRB JE Electrical (CBT II) Mock Test- 7 - Question 29
Five limb core construction is preferred over three limb construction because in this type of construction:
Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 29
  • Five limb core construction is preferred over three limb construction because in this type of construction magnetic reluctance of the three phase can be balanced.
  • 5 limbed transformer core offers low impedance to the flow of unbalanced load between the line and neutral.
  • This is because the flux finds its path from 4th and 5th limb. So, tertiary winding will not be needed in a star connected transformer operating in an unbalanced load.
RRB JE Electrical (CBT II) Mock Test- 7 - Question 30

Protection of life and personal liberty is given in which article of Indian constitution?

Detailed Solution for RRB JE Electrical (CBT II) Mock Test- 7 - Question 30

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