Numerical Ability Test - 2 - Bank Exams MCQ

Concept:

Follow BODMAS rule to solve this question, as per the order given below.
Step - 1: Parts of an equation enclosed in 'Brackets' must be solved first, and following the BODMAS rule in the bracket -
Step - 2: Any mathematical 'Of' or 'Exponent' must be solved next.
Step - 3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated.
Step - 4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.
Calculation:

Given expression is

40% × 550 - 15% × 320 + 80 ÷ 4 = ? × 60

⇒ 0.4 × 550 - 0.15 × 320 + 20 = ? × 60

⇒ 220 - 48 + 20 = ? × 60

⇒ 240 - 48 = ? × 60

⇒ 192 = ? × 60

⇒ ? = 192/60

⇒ ? = 3.2

Hence, 3.2 will come in the place of (?).

Given:

1324 - 1089 + 990 = ? × 5 + 40 × 4 + 10

Follow the BODMAS rule to solve this question, as per the order given below:

Calculation:

1324 - 1089 + 990 = ? × 5 + 40 × 4 + 10

⇒ 1324 - 1089 + 990 = ? × 5 + 160 + 10

⇒ 2314 - 1089 = ? × 5 + 170

⇒ 1225 = ? × 5 + 170

⇒ 1225 - 170 = ? × 5

⇒ 1055 = ? × 5

⇒ ? = 1055 / 5

⇒ ? = 211

Hence, 211 will come in the place of '?'.

Given:

(3/7) × 343 - 25% of 160 + 62 = ? - 1

Concept used:

Follow the BODMAS rule according to the table given below:

Calculation:
(3/7) × 343 - 25% of 160 + 62 = ? - 1
⇒ 147 - (25/100) × 160 + 36 = ? - 1
⇒ ? = 147 - 40 + 36 + 1
⇒ ? = 184 - 40
⇒ ? = 144
∴ 144 should come in place of the question mark (?).

Total number of 3-Wheelers in Bangalore = 4000

Total number of 3-Wheelers in Goa = 1500

∴ Percentage of more 3-Wheelers in Bangalore as compared to Goa

⇒ (4000 – 1500) /1500 × 100 = 166.666%

Total number of 3-Wheelers in Pune = 2500

Total number of 4-Wheelers in Pune = 6000

⇒ Sum = 2500 + 6000 = 8500

Total number of 2-Wheelers in Goa = 2500

∴ Required Ratio = 8500/2500 = 17 ∶ 5

Total number of 2-Wheelers in Bangalore = 6000

Total number of 3-Wheelers in Bangalore = 4000

Total number of 4-Wheelers in Bangalore = 4500

⇒ Total vehicles of all types in Bangalore = 6000 + 4000 + 4500 = 14500

⇒ Percentage of 2-Wheelers in Bangalore = 6000/14500 × 100 = 41.379%

∴ The answer is 41.379%

For Delhi

Total number of 4-Wheelers = 8500

Total number of 2-Wheelers = 7500

Ratio = 8500/7500 = 17/15

For Mumbai

Total number of 4-Wheelers = 9000

Total number of 2-Wheelers = 4500

Ratio = 9000/4500 = 2/1

For Goa

Total number of 4-Wheelers = 3000

Total number of 2-Wheelers = 2500

Ratio = 3000/2500 = 6/5

For Bangalore

Total number of 4-Wheelers = 4500

Total number of 2-Wheelers = 6000

Ratio = 4500/6000 = 3/4

For Pune

Total number of 4-Wheelers = 6000

Total number of 2-Wheelers = 5000

Ratio = 6000/5000 = 6/5

∴ For Mumbai the ratio of 4-Wheelers to the 2-Wheelers is the highest.

Total number of 2-Wheelers in Goa = 2500

Total number of 3-Wheelers in Goa = 1500

Total number of 4-Wheelers in Goa = 3000

⇒ Total number of vehicles of all types = 2500 + 1500 + 3000 = 7000

Total number of 2-Wheelers in Pune = 5000

Total number of 3-Wheelers in Pune = 2500

Total number of 4-Wheelers in Pune = 6000

⇒ Total number of vehicles of all types = 5000 + 2500 + 6000 = 13500

∴ Required Ratio = 7000/13500 = 14 ∶ 27

Given:

84 is divided into two parts in such a way that the fourth part of the first part and the fifth part of the second are in the ratio 1 : 2

Calculation:

First part = x and second part = 84 – x

(x/4)/((84 – x)/5) = 1/2

⇒ x/4 × 5/(84 – x) = 1/2

⇒ 10x = 336 – 4x

⇒ 14x = 336

⇒ x = 24

Second part will be 84 – 24 = 60

Required percentage = 24/60 × 100 = 40%

Therefore the correct answer is 40%

⇒ Let the speed of the train be xm /sec

⇒ Length of platform = 2 x 640 = 1280

⇒ Total length = 1280 + 640 = 1920

⇒ (1920 / x) – (640 / x) = 160

⇒ 1280 / x = 160

⇒ x = 1280 / 160

∴ x = 8 m/sec

Given:

I. x² – 19x + 84 = 0

II. y² – 13y + 42 = 0

Calculation:

I. x² – 19x + 84 = 0

⇒ x² – 12x – 7x + 84 = 0

⇒ x(x – 12) – 7(x – 12) = 0

⇒ (x – 12)(x – 7) = 0

Then, x = 12 or x = 7

Now,

II. y² – 13y + 42 = 0

⇒ y² – 7y – 6y + 42 = 0

⇒ y(y – 7) – 6(y – 7) = 0

⇒ (y – 7)(y – 6) = 0

Then, y = 7 or y = 6

Now,

Comparison between x and y (via Tabulation):

∴ We can clearly see that x ≥ y

Given:

A does 1/4th as much work as B in 1/2^th of the time as B

A and B can do the work together in 30 days

Concept used:

Work done = Time taken × Efficiency

Calculation:

Let 1/a be the work per day by A

And, 1/b be the work per day by B

Hence, (1/a) + (1/b) = 1/30 ----(i)

A does 1/4 as much work as B in 1/2 of the time

Which means, A does as much work as B in 4 times of 1/2 of the time, i.e 2 of the time.

So, 1/a = 1/2b ----(ii)

Putting value of equation (ii) in (i)

(1/2b) + (1/b) = 1/30

⇒ b = 45

∴ B shall do the work alone in 45 days

Alternate Method

Let work done by B in 1 day be 8 units

So, work done by A in 1/2^th of 1 day = 2 units

So, A will do 4 work in 1 day

Ratio of efficiency of A and B = 1 : 2

So, B will take = 30 ÷ (2/3)

⇒ 45 days

Given:
(1200 - 870 + 31) ÷ (1400 - 678) = ?
Concept Used:

Calculation:
Given expression is,
⇒ (1200 – 870 + 31) ÷ (1400 – 678) = ?
⇒ ? = (1200 – 839) ÷ (1400 – 678)
⇒ ? = (361) ÷ (722)
∴ ? = 0.5

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

105 + 35 – 23 × 5 = √?

⇒ 140 – 115 = √?

⇒ 25 = √?

∴ ? = 625

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

252 ÷ 9 × 5 – 131 = √?

⇒ 28 × 5 – 131 = √?

⇒ 140 – 131 = √?

⇒ 9 = √?

∴ ? = 81

Given:

Distance between jerry and tom is 400m

Speed of jerry is 20kmph

Speed of tom is 21kmph

Formula used:

When two bodies A and B are moving with speed ‘a’ kmph and ‘b’ kmph respectively, then the relative speed of two bodies is

(i) (a + b) kmph if they are moving in opposite direction

(ii) (a - b) kmph if they are moving in same direction

Time taken to meet each other = distance between them / relative speed

Calculation:

Relative speed of jerrry and tom = speed of tom - speed of jerry

⇒ 21- 20 = 1kmph

Conversion of 1 kmph to metre/sec = 1 × 1000/3600 = 5/18 m/s

Time taken by tom to catch the jerry = 400/5 × 18 = 1440 sec

Converting 1440 sec into mins = 1440/60 = 24 mins.

Hence, the tom will catch the jerry after 24mins.

As per the given data,

From I)

⇒ x² - 4 = 0

⇒ x = ±2

From II)

⇒ y² + 4y + 3 = 0

⇒ y²+ 3y + y + 3 = 0

⇒ y (y + 3) + 1 (y + 3) = 0

⇒ (y + 1)(y + 3) = 0

∴ y = -1 and y = -3

When x = 2 and y = -1, then x > y

x = 2 and y = -3, then x > y

x = -2 and y = -1, then x < y

x = -2 and y = -3, then x > y

From the data given in the table, we get:

Total number of Guava sold by all five shops together = (180 + 216 + 432 + 172 + 365) = 1365
Required average = (1365/5) = 273
Hence, the correct answer is option B.

From the data given in the table, we get:

Clearly, Shop B sold 216 Guavas and Shop C sold 216 Apples.
Hence, the correct answer is option D.

From the data given in the table, we get:

Total number of Mangoes sold by Shops A, B, and C together = (240 + 144 + 216) = 600
Total number of Guavas sold by Shops B, D, and E together = (216 + 172 + 365) = 753
Required difference = (753 - 600) = 153, Less
Hence, the correct answer is option B.

Follow BODMAS rule to solve this question, as per the order given below,

Step-1- Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2- Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3- Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4- Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

(121)³ × 11 ÷ (1331)³ = (11)^?

⇒ 11⁶ × 11 ÷ 11⁹ = 11^?

⇒ 11^? = 11^-2

Follow BODMAS rule to solve this question, as per the order given below,

Step–1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step–2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step–3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step–4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

{(50% of 224 – 24) × 24% of 25} + 227 = ? – 24

⇒ {(50/100 × 224 – 24) × 24/100 × 25} + 227 = ? – 24

⇒ {(112 – 24) × 6} + 227 = ? – 24

⇒ ? – 24 = 88 × 6 + 227

⇒ ? = 528 + 227 + 24

⇒ ? = 779

Follow BODMAS rule to solve this question, as per the order given below,

Step–1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step–2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step–3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step–4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

67% of ? + 31% of 1500 = 800

⇒ 67/100 × ? + 31/100 × 1500 = 800

⇒ 67/100 × ? + 31 × 15 = 800

⇒ 67/100 × ? = 800 – 465

⇒ ? = 335 × 100/67

∴ ? = 500

7% of 140 + 27% of 1300 = ?% of 190 – 34% of 850

⇒ 9.8 + 351 = ? × 1.9 – 289

⇒ 360.8 + 289 = ? × 1.9

⇒ ? = 649.8/1.9

Convert the data into mathematical form,

⇒ 630 × (4/7) × (60/100) = ?

⇒ 90 × 4 × 0.6 = ?

⇒ ? = 216

GIVEN:

A coin is tossed 5 times.

CONCEPT:

Probability of having at least one = 1 – Probability of having none

FORMULA USED:

Probability = Total favourable events/Total events

CALCULATION:

Probability of having no tail in 5 times = 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 1/32

As 1/2 is probability of head so we have considered case where every toss displays head.

Probability that at least one toss results in a tail = 1- Probability of having no tail in 5 times

= 1 – (1/32) = 31/32.

Given:

The length of the train is 300 meters.

The train can pass 450 meters long platforms in 30 seconds.

Formula used:

The speed of the train = {(the length of the train + the length of the platform or bridge or another train)/time}

Distance = Time × Speed

Calculation:

The speed of the train = {(300 + 450)/30} m/s

⇒ The speed of the train = {750/30} m/s

⇒ The speed of the train = 25 m/s

Now, to cross the 700-meter long bridge the train has to be travelled (700 + 300) meters = 1000 meters

So, required time = 1000/25 sec = 40 sec

∴ The train will pass the 700 meters long bridge in 40 seconds.

Given:

34.93 × 64.01 - ? = 13

Concept Used:

Follow the BODMAS rule according to the table given below:

Calculation:

34.93 × 64.01 - ? = 13

Taking approximate values as,

⇒ 35 × 64 - ? = 13

⇒ ? = 2240 - 13

⇒ ? = 2227

∴ The value of (?) is 2227.

Concept Used

Using BODMAS rule

Calculation:

Taking the approximate values, we get:

⇒ 12 of (14.72/0.9) ÷ ? = 16.24

⇒ [12 × (15/1)] ÷ ? = 16

⇒ 180 ÷ ? = 16

⇒ ? = 180/16 = 11.25

⇒ ? ≈ 11

Concept:

Calculation:

Giving expression is,

?³ + 27.19 = 152 + 145.26

Taking approximate values as,

⇒ ?³ + 27 = 225 + 145

⇒ ?³ + 27 = 370

⇒ ?³ = 370 – 27

⇒ ?³ = 343

⇒ ? = 7

∴ The value of ? is 7