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GATE Biotechnology Mock Test - 1 - GATE Biotechnology MCQ


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30 Questions MCQ Test - GATE Biotechnology Mock Test - 1

GATE Biotechnology Mock Test - 1 for GATE Biotechnology 2025 is part of GATE Biotechnology preparation. The GATE Biotechnology Mock Test - 1 questions and answers have been prepared according to the GATE Biotechnology exam syllabus.The GATE Biotechnology Mock Test - 1 MCQs are made for GATE Biotechnology 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Biotechnology Mock Test - 1 below.
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GATE Biotechnology Mock Test - 1 - Question 1

References : ______ : : Guidelines : Execute
(By definition)

GATE Biotechnology Mock Test - 1 - Question 2

In the figure provided, PQRS is a parallelogram where PS measures 7 cm, PT is 4 cm, and PV equals 5 cm. Determine the length of RS in centimeters. (The diagram is representative.)

GATE Biotechnology Mock Test - 1 - Question 3

The dimensions of a room, specifically length, breadth, and height, are in the ratio of 3:2:1. If the breadth and height are reduced by half while the length is increased twofold, what will be the total surface area of the four walls of the room?

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 3

A = 2( l + b)h
A = 2(3 + 2) × 1 = 10
New area = 2(6 + 1) × 1/2 = 7
Decrease = (3/10) × 100
= 30%

GATE Biotechnology Mock Test - 1 - Question 4

The World Bank has announced that it will not provide any new financial assistance to Sri Lanka, which is currently facing its most significant economic crisis in decades, until an appropriate macroeconomic policy framework is established. According to a statement from the World Bank, Sri Lanka must implement structural reforms aimed at economic stabilization and address the fundamental causes of its crisis. This situation has led to a depletion of foreign exchange reserves and caused shortages of food, fuel, and medicines. The bank is reallocating resources from existing loans to help mitigate shortages of essential goods such as medicines, cooking gas, fertilizers, meals for children, and cash for at-risk households.
Based solely on the information in the above passage, which of the following statements can be inferred with certainty?

GATE Biotechnology Mock Test - 1 - Question 5

Deepika offers her products at a price that is 10% lower than Nidhi's prices and 10% higher than Gurpreet's prices. If a customer buys items from Nidhi for Rs. 100, how much would he have saved if he had purchased the same items from Gurpreet?

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 5

Selling price of goods sold by Nidhi = Rs. 100
Selling price of goods sold by Deepika = Rs. 90
Now, according to the question:
110% of selling price of goods sold by Gurpreet = Rs. 90
Selling price of goods sold by Gurpreet = (100/110) x 90 = Rs. 900/11
So, Gurpreet's goods are cheaper than Nidhi's goods by

Therefore, the customer would have saved 18.18%, if he bought the goods from Gurpreet instead of buying them from Nidhi.

GATE Biotechnology Mock Test - 1 - Question 6

The ages of Meena and Leena are currently in the ratio of 4 to 3. Their combined ages total 28 years. What will be the ratio of their ages after a period of 8 years?

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 6

Ratio of ages of Meena and Leena = 4 : 3
Let the present age of Meena be 4x.
Present age of Leena = 3x
According to the question:
4x + 3x = 28
7x = 28
x = 4
Therefore, the present age of Meena = 4 × 4 = 16 years
Age of Leena = 3 × 4 = 12 years
After 8 years,
Age of Meena = 16 + 8 = 24 years
Age of Leena = 12 + 8 = 20 years
Therefore, required ratio = 24 : 20 or 6 : 5

GATE Biotechnology Mock Test - 1 - Question 7

Three containers, A, B, and C, contain mixtures of milk and water in the ratios of 1 : 5, 3 : 5, and 5 : 7, respectively, and are filled to their maximum capacity. The capacities of these containers are in the ratio of 5 : 4 : 5. Determine the ratio of milk to water when the contents of all three containers are combined.

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 7

Ratio of milk and water

GATE Biotechnology Mock Test - 1 - Question 8

Which of the following is essential for the maturation of B-cells within the bone marrow?

GATE Biotechnology Mock Test - 1 - Question 9

In the process of hybridoma technology, which enzyme is not present in the myeloma cells utilized for the production of monoclonal antibodies?

GATE Biotechnology Mock Test - 1 - Question 10

The eigenvalues associated with a skew-symmetric matrix are

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 10

Eigen values of a skew-symmetric matrix are either zero or pure imaginary, occuring in conjugate pairs.

GATE Biotechnology Mock Test - 1 - Question 11

The phospholipid found in the plasma membrane of human cells but absent in E. coli is

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 11

PC is present in the plasma membranes of human cells such as the RBCs and neurons, but it is totally absent from that of the E. coli. The major phospholipids present in the membrane of E. coli are PE and PS that collectively account for 85% of its weight.

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 12

For the function f(x) = x2e-x, the maximum value is attained when x is equal to ____.(Round your answer to the nearest integer)


Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 12

f(x) = x2e-x
Or f'(x) = 2xe-x - x2e-x
= xe-x (2 - x)
f''(x) = (x2 - 4x+ 2) e-x
Now for maxima and minima, f'(x) = 0
xe-x (2 - x) = 0
or x = 0, 2
at x = 0   f''(0) = 2 (+ ve)
at x = 2   f''(2) = - 2e-2(- ve)
Now f''(0) = 2 and f''(2) = - 2e-2 < 0. Thus, x = 2 is the point of maxima. 

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 13

What is the distance between the two points where the equations x 2 y = 7 and x y = 7 intersect, rounded to two decimal places?


*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 14

If 73x equals 216, what is the value of 7− x when rounded to three decimal places?  ____________.


GATE Biotechnology Mock Test - 1 - Question 15

The point where the function sin x 2 cos x achieves its maximum value over the interval [0, x] is

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 15

We have 
f(x) = sin x + 2cos x
f'(x) = cos x - 2 sin x ....(i)
f"(x) = - sin x - 2 cos x ....(ii)
For maxima and minima, put f'(x) = 0
cos x = 2 sin x
tan x= 1/2 
x = 26.56° 
At x = 26.56° 
f''(x) = - 2.236(-ve)
Thus f(x) is maximum at x = 26.56° 

GATE Biotechnology Mock Test - 1 - Question 16

If the convergence region of x1 [n] x2 [n] is then the convergence region of x1 [n] - x2 [n] encompasses

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 16

The ROC of addition or subtraction of two functions x1(n) and x2(n) is R1 ∩ R2.
We have been given ROC of addition of two function and has been asked ROC of subtraction of two function. It will be same.

GATE Biotechnology Mock Test - 1 - Question 17

A fair coin is tossed n times, and let X represent the number of heads that appear. If the probabilities P(X = 4), P(X = 5), and P(X = 6) form an arithmetic progression, what is the value of n?

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 17

Given: 2P (X = 5) = P (X = 4) + P (X = 6)

⇒ 2 nC5 = nC4 + nC6
⇒ n = 7 or 14.

GATE Biotechnology Mock Test - 1 - Question 18

Identify the total number of bonds that can be hydrolyzed by trypsin and chymotrypsin in the subsequent oligopeptide sequence:

Tyr-Gly-Gly-Phe-Met-Lys-Lys-Tyr

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 18

Trypsin cleaves carboxyl side of basic residues, Lys and Arg, while chymotrypsin cleaves the carboxyl sides of aromatic amino acids Phe, Trp and Tyr.

GATE Biotechnology Mock Test - 1 - Question 19

Associate the cofactors in Group I with their corresponding enzymes in Group II.

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 19

Many enzymes need a cofactor for their activity. A specific enzyme is functional in association to a specific metal ion cofactor.
A carboxypeptidase is a protease enzyme that hydrolyzes (cleaves) a peptide bond at the carboxy-terminal (C-terminal) end of a protein or peptide. Carboxypeptidase needs Zn ions for its activity.
Superoxide dismutase is an enzyme that helps break down potentially harmful oxygen molecules in cells. Superoxide dismutase requires Cu ions as a co factor.
Enolase, also known as phosphopyruvate hydratase, is a metalloenzyme responsible for the catalysis of the conversion of 2-phosphoglycerate (2-PG) to phosphoenolpyruvate (PEP). Enolase requires Mg ions as a cofactor.
Urease is an enzyme that catalyzes the hydrolysis of urea, forming ammonia and carbon dioxide. Urease needs Ni ions for its activity and functionality.

GATE Biotechnology Mock Test - 1 - Question 20

A culture of bacteria has grown to 32 × 106 cells after 2.5 hours of exponential growth. If the bacteria have a doubling time of 30 minutes, what was the initial count of bacteria?

Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 20

The number of generations, n = Total time passed/doubling time
n = 2.5/0.5 = 5
No = N/2n = 32 × 106/25 = 10 × 105 cells

GATE Biotechnology Mock Test - 1 - Question 21

Pair the immune tolerance mechanisms listed in Group I with their corresponding outcomes found in Group II.

*Multiple options can be correct
GATE Biotechnology Mock Test - 1 - Question 22

The event(s) responsible for the inactivation of tumor suppressor genes in cancer cells is(are)

*Multiple options can be correct
GATE Biotechnology Mock Test - 1 - Question 23

Which of the following vector(s) can be utilized to replicate a DNA fragment measuring 220 kb?

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 24

What is the recombination frequency for the genes A and B?
(Provide your answer to one decimal place.)


Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 24

The map distance between the genes is equal to the recombination frequency of the genes.
Recombination frequency = Number of recombinant offsprings/Total number of offsprings.
Recombination frequency = (36 + 39)/(36 + 39 + 160 + 165) = 0.1875 or 18.75%
Hence, the genes A and B are 18.8 map units apart.

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 25

What is the value of the rate constant kd for this process?
(Provide your answer rounded to 3 decimal places.)


Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 25

2.303 log (N/N0) = -kdt
Or
kd = - (2.303/t) log (N/No)
Putting the values, we get
kd = - (2.303/1) log (104/106) = 4.606 hr-1

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 26

A species with a diploid chromosome number of 48 during the M phase of the cell cycle will have how many chromosomes in the G1 phase?


Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 26

During the M phase, the number of chromosomes(48) in a cell is double that of the actual number so as to ensure equal distribution of chromosomes in the daughter cells. The cell enters the G1 phase after cell division in the M phase is over. So, the number of chromosomes in the G1 phase would be half of what was in the M phase i.e 24.

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 27

In a demographic investigation, a random selection of 1000 individuals was made, and their genotypes for a specific trait were analyzed. The distribution of genotypes was observed as follows:
AA = 800
Aa = 185
aa = 15

Calculate the frequency of the allele "a" within this population.
(Provide your answer rounded to 3 decimal places.)


Detailed Solution for GATE Biotechnology Mock Test - 1 - Question 27

Frequency of allele a = q = [f(Aa) + (2 × f(aa))]/(2 × total number of individuals)
q = [185 + (2 × 15)]/2000
= 0.1075

*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 28

If a double-stranded DNA segment of 1000 base pairs has a mass of 1x10-18 grams and the distance separating each base pair is 0.34 nm, what is the total mass of DNA (in mg, rounded to one decimal place) needed to extend from the Earth to the Moon, given that the distance between the Earth and the Moon is 3,74,000 km?


*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 29

The consistency index 'K' and the flow behavior index 'n' for a dilatant fluid are given as 0.415 (in CGS units) and 1.23, respectively. Calculate the apparent viscosity (in g. cm−1. s−1) of this fluid at a shear rate of 60 s−1, rounding the result to the nearest integer. The value is ___________.


*Answer can only contain numeric values
GATE Biotechnology Mock Test - 1 - Question 30

A protein contains three identical binding sites located at the corners of an equilateral triangle. When one of these sites is occupied by a dye (donor), the observed quantum yield (ØD) is 0.5. If one site is occupied by a donor dye and another by an acceptor dye, the resultant ØD is 0.25. What is the measured ØD for a scenario where one site is occupied by a donor and the remaining two are filled with acceptor dye (rounded to three decimal places)?


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