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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Test  >  GATE Mock Test Series 2027  >  Test: Time Response - Electrical Engineering (EE) MCQ

GATE Electrical Engineering (EE) Test: Time Response Free Online Test 2026


MCQ Practice Test & Solutions: Test: Time Response (20 Questions)

You can prepare effectively for Electrical Engineering (EE) GATE Electrical Engineering (EE) Mock Test Series 2027 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Time Response". These 20 questions have been designed by the experts with the latest curriculum of Electrical Engineering (EE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 60 minutes
  • - Number of Questions: 20

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Test: Time Response - Question 1
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The open-loop transfer function of a ufb control system is

The position, velocity and acceleration error constants are respectively

Detailed Solution: Question 1

Test: Time Response - Question 2
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The open-loop transfer function of a unit feedback system is

The position, velocity and acceleration errorconstants are respectively

Detailed Solution: Question 2

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Test: Time Response - Question 3
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If a type 0 system is subjected to step input, what is its effect on steady state error?

Test: Time Response - Question 4
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The forward-path transfer function of a unity negative feedback system is given by:

The value of K which will place both the poles of the closed-loop system at the same location is.​​​​

Detailed Solution: Question 4

Concept:

Poles of closed-loop system = zeroes of the characteristic equation.

Characteristic equation is given by:

1 + G(s) H(s) = 0

(s + 2) (s – 1) + K = 0

s2 + s – 2 + k = 0

s2 + s + (k – 2) = 0

Given that the poles of closed system ‘or’ we can say zeroes of the characteristic equation are at same location. This indicates that the roots of the characteristic equation will be real, i.e.

b2 – 4ac = 0

Here, b = 1, a = 1 and c = k – 2

b2 – 4ac = 1 – 4(1) (k -2) = 0

1 – 4 (k - 2) = 0

1 – 4k + 8 = 0

4k = 9

K = 2.25 

Test: Time Response - Question 5
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For the system shown in fig.the steady state error component due to unit step disturbance is 0.000012 and steady state error component due to unit ramp input is 0.003. The values of K1 and K2 are respectively

Detailed Solution: Question 5

If R (s) = 0


Error in output due to disturbance



Error due to ramp input

Test: Time Response - Question 6
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The transfer function for a single loop nonunity feedback control system is

The steady state error due to unit step input is

Detailed Solution: Question 6

E(s) = R(s) - C(s) H(s)


Test: Time Response - Question 7
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For the system of fig. the total steady state error due to a unit step input and a unit step disturbance is

Detailed Solution: Question 7

Option A is correct; the total steady-state error equals -5.

Given G1(s) = 1/(s+5) and G2(s) = 100/[s(s+2)], with unity negative feedback. The input and disturbance are unit steps: R(s)=1/s and D(s)=1/s.

From the block diagram algebra, the error is E(s) = (R(s) - G2(s)D(s)) / (1 + G1(s)G2(s)).

Multiplying by s to get the steady-state value, we have sE(s) = (1 - G2(s)) / (1 + G1(s)G2(s)), because E(s) = (1 - G2(s)) / [s(1 + G1(s)G2(s))].

Multiply numerator and denominator by (s+5) to simplify the term with G1(s): sE(s) = (s+5)(1 - G2(s)) / (s+5 + G2(s)).

Substitute G2(s) = 100/[s(s+2)] and multiply numerator and denominator by s(s+2) to clear fractions. This gives sE(s) = (s+5)(s(s+2) - 100) / (s(s+2)(s+5) + 100).

Now take the limit s → 0. The numerator tends to 5 × (0 - 100) = -500, and the denominator tends to 0 + 100 = 100. Therefore ess = -500/100 = -5.

Hence the correct steady-state error is -5, so option A is the correct choice after using the correct form of G2(s).




Test: Time Response - Question 8
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The forward path transfer function of a ufb system is

If a unit ramp is applied, the minimum possiblesteady-state error is

Detailed Solution: Question 8

Using Routh-Hurwitz Criterion, system is stable for 0 < K < 2000

Test: Time Response - Question 9
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The forward-path transfer function of a ufb system is

The system has r(t) = t3 applied to its input. Thesteady state error is

Detailed Solution: Question 9




Test: Time Response - Question 10
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Consider a unity feedback system with forward transfer function given by

The steady-state error in the output of the system for a unit-step input is _________ (up to 2 decimal places).

Detailed Solution: Question 10

Test: Time Response - Question 11
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A system has position error constant Kp  = 3. The steady state error for input of 8tu(t) is

Detailed Solution: Question 11

System is zero type 

Test: Time Response - Question 12
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The forward path transfer function of a unity feedback system is

For input of 60u(t) steady state error is

Detailed Solution: Question 12


Test: Time Response - Question 13
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For ufb system shown in fig. the transfer function is

If input is 30t2 , then steady state error is

Detailed Solution: Question 13

Test: Time Response - Question 14
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The forward-path transfer function of a ufb control system is

The steady state errors for the test input 37tu(t) is

Detailed Solution: Question 14

Test: Time Response - Question 15
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In the system shown in fig. r(t) =  1 + 2t , t > 0. The steady state error e(t) is equal to

Detailed Solution: Question 15

The system is type 2. Thus to step and ramp input error will be zero.
 

Test: Time Response - Question 16
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A ufb control system has a forward path transfer function

If the system is subjected to an input r(t) = 1 + t + 1/2 t2 , t > 0the steady state error of the system will be

Detailed Solution: Question 16

Correct Answer :- C

Explanation : R(s) = (1/s)+(1/s2) + (1/s3)

E(s) = R(s) / {1 + G(s)} = 1/10s

ess = lim sE(s) = 0.1

Test: Time Response - Question 17
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The system shown in fig. has steady-state error 0.1 to unit step input. The value of K is

Detailed Solution: Question 17


Test: Time Response - Question 18
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Block diagram of a position control system is shown in fig.

If Kt = 0 and Ka= 5, then the steady state error tounit ramp input is

Detailed Solution: Question 18



Test: Time Response - Question 19
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Block diagram of a position control system is shown in fig.

If the damping ratio of the system is increased to 0.7 without affecting the steady state error, then thevalue of Ka and Kt are

Detailed Solution: Question 19

The equivalent open-loop transfer function





Test: Time Response - Question 20
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A system has the following transfer function

The type and order of the system are respectively

Detailed Solution: Question 20

The s has power of 4 and denominator has order of 7. So Type 4 and Order 7.

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About this Electrical Engineering (EE) Practice Test

This test contains 20 MCQs on Time Response with detailed solutions for each question. It is part of the GATE Electrical Engineering (EE) Mock Test Series 2027 course on EduRev, designed to align with the current Electrical Engineering (EE) syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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