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Test: Principal Stress & Strain - 1 - Mechanical Engineering MCQ


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20 Questions MCQ Test - Test: Principal Stress & Strain - 1

Test: Principal Stress & Strain - 1 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Principal Stress & Strain - 1 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Principal Stress & Strain - 1 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Principal Stress & Strain - 1 below.
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Test: Principal Stress & Strain - 1 - Question 1

A block of steel is loaded by a tangential force on its top surface while the bottom surface is held rigidly. The deformation of the block is due to

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 1

It is the definition of shear stress. The force is applied tangentially it is not a point load so you cannot compare it with a cantilever with a point load at its free end.

Test: Principal Stress & Strain - 1 - Question 2

The figure shows the state of stress at certain point in a stresses body. The magnitudes of normal stresses in x and y direction are 100 MPa and 20 MPa respectively. The radius of Mohr’s stress circle representing this state of stress is

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 2

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Test: Principal Stress & Strain - 1 - Question 3

The state of stress at a point in a loaded member is shown in the figure. The magnitude of maximum shear stress is [1MPa = 10 kg/cm2]

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 3

Test: Principal Stress & Strain - 1 - Question 4

In a bi-axial stress problem, the stresses in x and y directions are (σ x = 200 MPa and σy =100 MPa. The maximum principal stress in MPa, is:

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Test: Principal Stress & Strain - 1 - Question 5

The normal stresses at a point are σx = 10 MPa and, σy = 2 MPa; the shear stress at this point is 4MPa. The maximum principal stress at this point is:

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 5

Test: Principal Stress & Strain - 1 - Question 6

The state of stress at a point under plane stress condition is

σxx = 40 MPa , σyy = 100 MPa and τxy = 40 MPa .

The radius of the Mohr‟s circle representing the given state of stress in MPa is

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 6

Test: Principal Stress & Strain - 1 - Question 7

When a component is subjected to axial stress the normal stress σn is maximum, if cos θ is _______ . (σnxCos2θ)

1. maximum
2. minimum
3. always one
4. always zero

Test: Principal Stress & Strain - 1 - Question 8

If the two principal strains at a point are 1000 × 10-6 and -600 × 10-6, then the maximum shear strain is:

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 8

Shear strain 

Test: Principal Stress & Strain - 1 - Question 9

In the case of bi-axial state of normal stresses, the normal stress on 45° plane is equal to

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Test: Principal Stress & Strain - 1 - Question 10

In a two-dimensional problem, the state of pure shear at a point is characterized by

Test: Principal Stress & Strain - 1 - Question 11

For the state of stress of pure shear τ the strain energy stored per unit volume in the elastic, homogeneous isotropic material having elastic constants E and ν will be:

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 11

Test: Principal Stress & Strain - 1 - Question 12

Assertion (A): Circular shafts made of brittle material fail along a helicoidally surface inclined at 45° to the axis (artery point) when subjected to twisting moment.

Reason (R): The state of pure shear caused by torsion of the shaft is equivalent to one of tension at 45° to the shaft axis and equal compression in the perpendicular direction.

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 12

Both A and R are true and R is correct explanation for A.

Test: Principal Stress & Strain - 1 - Question 13

The state of plane stress in a plate of 100 mm thickness is given as σxx = 100 N/mm2, σyy = 200 N/mm2, Young's modulus = 300 N/mm2, Poisson's ratio = 0.3. The stress developed in the direction of thickness is:

Test: Principal Stress & Strain - 1 - Question 14

Consider the following statements:

State of stress in two dimensions at a point in a loaded component can be completely specified by indicating the normal and shear stresses on

1. A plane containing the point

2. Any two planes passing through the point

3. Two mutually perpendicular planes passing through the point

Of these statements

Test: Principal Stress & Strain - 1 - Question 15

In a strained material one of the principal stresses is twice the other. The maximum shear stress in the same case is tmax . Then, what is the value of the maximum principle stress?

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Test: Principal Stress & Strain - 1 - Question 16

The principal stresses σ1, σ2 and σ3 at a point respectively are 80 MPa, 30 MPa and –40 MPa. The maximum shear stress is:

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Test: Principal Stress & Strain - 1 - Question 17

Plane stress at a point in a body is defined by principal stresses 3σ and σ. The ratio of the normal stress to the maximum shear stresses on the plane of maximum shear stress is:

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 17

Major principal stress on the plane of maximum shear 

Test: Principal Stress & Strain - 1 - Question 18

For the state of plane stress.
Shown the maximum and minimum principal stresses are:

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 18

Test: Principal Stress & Strain - 1 - Question 19

Maximum shear stress in a Mohr's Circle

Detailed Solution for Test: Principal Stress & Strain - 1 - Question 19

Test: Principal Stress & Strain - 1 - Question 20

Two-dimensional state of stress at a point in a plane stressed element is represented by a Mohr circle of zero radius. Then both principal stresses

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