Which of the following is not a periodic function -
[AIEEE 2002]
The period of sin2 x is-
[AIEEE 2002]
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The function f : R → R defined by f(x) = sin x is-
[AIEEE-2002]
The range of the function f(x)
[AIEEE-2002]
Domain of definition of the function
[AIEEE 2003]
A function f from the set of natural numbers to integers defined by
[AIEEE 2003]
The range of the function f(x) = 7– xPx–3 is-
[AIEEE 2004]
If f : R → S, defined by f(x) = sin x – √3 cos x+ 1, is onto, then the interval of S is-
[AIEEE 2004]
The graph of the function y = f(x) is symmetrical about the line x = 2, then-
[AIEEE 2004]
The domain of the function
Let f : (–1, 1) → B, be a function defined by then f is both one-one and onto when B is the interval -
[AIEEE-2005]
A real valued function f(x) satisfies the functional equation f(x – y) = f(x) f(y)– f (a–x) f(a + y) where a is a given constant and f(0)=1, then f(2a – x) is equal to -
[AIEEE-2005]
The largest interval lying in for which the function is defined, is -
[AIEEE 2007]
t f : N → Y be a function defined as f(x) = 4x + 3 where Y = |y ∈ N : y = 4x + 3 for some x ∈ N|. Show that f is invertible and its inverse is
[AIEEE 2008]
For real x, let f(x) = x3 + 5x + 1, then -
[AIEEE 2009]
Let f(x) = (x + 1)2 –1, x > –1
Statement – 1 : The set {x : f(x) = f–1(x)} = {0, –1}.
Statement – 2 : f is a bijection.
[AIEEE 2009]
The domain of the function f(x)
[AIEEE 2011]
If the function f : [1, ∞) → [1, ∞) is defined by f(x) = 2x(x – 1), then f–1(x) is
The domain of definition of the function, y(x) given by the equation, 2x + 2y = 2 is
[JEE 2000(Scr.), 1]
The domain of definition of f(x) =
Let E = {1, 2, 3, 4} & F = {1, 2}. Then the number of onto functions from E to F is
Then for what value of a is f(f(x)) = x ?
(a) Suppose f(x) = (x + 1)2 for x ≥– 1. If g(x) is the function whose graph is the reflection of the graph of f(x) with respect to the line y = x, then g(x) equals
[JEE. 2002 (Scr.)]
(b) Let function f : R → R be defined by f(x) = 2x + sinx for x ∈ R. Then f is
Range of the function
Let f(x) = sinx + cosx, g (x) = x2 – 1. Thus g(f(x)) is invertible for x ∈
[JEE 2004 (Scr.)]