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MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - JEE MCQ


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12 Questions MCQ Test - MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1)

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) for JEE 2025 is part of JEE preparation. The MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) questions and answers have been prepared according to the JEE exam syllabus.The MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) below.
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MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 1

Find the no. of roots of the equation  tan x + sec x = 2 cos x in the interval [0, 2 π]-

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 1

tan x + sec x = 2 cos x
⇒ 1 + sin x = 2 (1 – sin2x)
⇒ 2 sin2 x + sin x – 1 = 0
⇒ sin x = –1, –1/2
∴ In interval [0, 2π)
Total number of solution is 3

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 2

General solution of tan 5θ = cot 2θ is-

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 2


⇒ cos 5θ . cos 2θ - sin 5θ sin 2θ = 0
⇒ cos (7θ) = 0

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 3

The number of values of x in the interval  [0, 3π]satisfying the equation 2 sin2 x + 5 sin x – 3 = 0 is –

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 3


⇒ sin x = -3 (impossible)and sin x = 1/2 
For sin x = 1/2
Total number of solution in interval [0, 3π] = 4

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 4

If 0 < x < π, and cos x + sin x =1/2 , then tan x is –

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 4





MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 5

The number of integral values of k for which the equation 7 cos x + 5 sin x = 2k + 1 has a solution is

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 5

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 6

cos(α – β) = 1 and cos(α + β) = 1/e, where α,β ∈ [–π, π], number of pairs of a, b which satisfy both the equations is

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 6




number of points of (α, β) are 4

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 7

If 0 < θ < 2π, then the intervals of values of θ for which 2 sin2θ – 5sinθ + 2 > 0, is

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 7


⇒ 2 sinθ - 1 < 0


MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 8

The number of solutions of the pair of equations 2sin2θ – cos 2θ = 0 and 2cos2θ– 3 sin θ = 0 in the interval [0, 2π] is

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 8



 n ∈ I


∴ sin θ = 1/2

from (i) & (ii)common sol.
 
∴ 2 solution

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 9

For 0 < θ < π/2, then solution(s) of (θ + (m - 1)π/4) cosec(θ + mπ/4) = 4,√2 is(are)

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 9






MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 10

The number of values of θ in the interval  such that  for n= 0, ±1, ±2 and tanθ = cot 5θ as well as sin2θ = cos4θ is

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 10











MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 11

The number of all possible values of θ when θ ∈(0, π) for which the system of equation   (y + z) cos 3θ = (xyz) sin 3θ(xyz) sin 3θ = (y + 2z)cos 3θ + y sin 3θ have a solution (x0, y0, z0) with y0,z0 ≠ 0 is

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 11

Number of solution are 3
(y0 +z0) cos 3θ = x0y0z0 sin 3θ ....(i) y0. z0 ≠ 0
x0y0z0 sin 3θ = 2z0cos3θ + 2y0 sin 3θ ....(ii)   
x0y0z0 sin 3θ = (y0 + 2z0) cos 3θ +y0sin 3θ ....(iii)
subtracting (ii) from (iii) y0 cos 3θ = y0 sin3θ ; y0 ≠ 0 

From (i) & (ii)
(y0 - z0) cos 3θ = 2y0 sin3θ & (i) (ii)
- 2z0 cos3θ = 2y0 sin 3θ (y + z) = 0 & from (i) x0 = 0 

satisfies all the given equation
∴ number of values of θ is 3

MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 12

Let P = {θ : sin θ – cos θ = √2 cos θ} and Q = {θ : sin θ + cos θ = 2 sin θ} be two sets. Then

Detailed Solution for MCQ (Previous Year Questions) - Trigonometry Equation (Competition Level 1) - Question 12

for P ⇒ tan θ = 1 + √2 ⇒ θ = nπ + 3π/8
for Q ⇒ tan θ = √2 + 1 ⇒ θ = nπ + 3π/8 so p = Q

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