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Data Interpretation- 3 - SSC MTS/GD Quant Aptitude Free MCQ Test with solutions


MCQ Practice Test & Solutions: Test: Data Interpretation- 3 (20 Questions)

You can prepare effectively for SSC MTS / SSC GD Quantitative Aptitude for Competitive Exams with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Data Interpretation- 3". These 20 questions have been designed by the experts with the latest curriculum of SSC MTS / SSC GD 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 15 minutes
  • - Number of Questions: 20

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Test: Data Interpretation- 3 - Question 1

Study the following graph carefully to answer the given questions

If the ratio of number of boys & girls are in the ratio 3:2 in N and P, find the average number of boys in N and P together ?

Detailed Solution: Question 1

N:675 =>Boys = 675*3/5 = 405
P:650 =>Boys = 650*3/5 = 390
Avg = 405+390/2 = 397.5

Test: Data Interpretation- 3 - Question 2

Study the following graph carefully to answer the given questions

Find the total no of failed students in M, O and Q together ?

Detailed Solution: Question 2

M =768*25%= 192
O= 460*15% = 69
Q = 320*25% = 80
Total = 341

Test: Data Interpretation- 3 - Question 3

Study the following graph carefully to answer the given questions

What will be the ratio of number of boys passed in N to number of girls failed in N, if the number of girls and boys in the ratio 16:11 ?

Detailed Solution: Question 3

675 => 400:275 => 16:11 = G:B
G:400*12% =48
B:275*88% =242
242:48 = 121: 24

Test: Data Interpretation- 3 - Question 4

Study the following graph carefully to answer the given questions

Find the difference between the number of passed students in Q to number of failed students in M ?

Detailed Solution: Question 4

Q passed => 75% of 320 = 240
M failed => 192
Difference = 240-192 = 48

Test: Data Interpretation- 3 - Question 5

Study the following graph carefully to answer the given questions

Which centre has the second least number of failed student ?

Detailed Solution: Question 5

M=192
N=81
O=69
P=130
Q=80

Test: Data Interpretation- 3 - Question 6

Study the following table carefully to answer the given questions

Classification of 50 Students based on the marks obtained by them in Quants & Reasoning in Prelim exam

The number of students scoring less than 30% marks in aggregate is?

Detailed Solution: Question 6

We have 30% of 100 = (30/100)x100 = 30
Therefore Required number
= Number of students scoring less than 30 marks in aggreagate
= 50 – Number of students scoring 30 and above marks in aggregate
= 50 – 40 = 10.

Test: Data Interpretation- 3 - Question 7

Study the following table carefully to answer the given questions

Classification of 50 Students based on the marks obtained by them in Quants & Reasoning in Prelim exam

If it is known that at least 20 students were eligible for main exam, then the minimum qualifying marks in Reasoning for eligibility to attend the main exam(Top 20 students only can attend main exam )?

Detailed Solution: Question 7

12 students secured above 80 then remaining 8 student will scored in the range 70-80

Test: Data Interpretation- 3 - Question 8

Study the following table carefully to answer the given questions

Classification of 50 Students based on the marks obtained by them in Quants & Reasoning in Prelim exam

The percentage of number of students scored 70% marks in Quants is what percentage of number of students scored 30% marks in aggregate ?

Detailed Solution: Question 8

Number of students scored 70% marks or 70 in Quants  = 28
Number of students scored 30% marks or 30 in aggregate= 40
% = 28/40 * 100 = 70%

Test: Data Interpretation- 3 - Question 9

Study the following table carefully to answer the given questions

Classification of 50 Students based on the marks obtained by them in Quants & Reasoning in Prelim exam

If at least 50% marks in aggregate are required for interview, how many students will be eligible to attend interview?

Detailed Solution: Question 9

50% of 100 = 50*100/100 = 50
No of students scored 50 aggregate = 38

Test: Data Interpretation- 3 - Question 10

Study the following table carefully to answer the given questions

Classification of 50 Students based on the marks obtained by them in Quants & Reasoning in Prelim exam

What is the different between the number of students passed with 80 as cut-off marks in Quants and 30 as cut-off marks in aggregate together to no of students passed with 70 as cut-off marks in aggregate and 50 as cut off in Reasoning?

Detailed Solution: Question 10

Difference = (23+40 ) – ( 22+35) =6

Test: Data Interpretation- 3 - Question 11

(Q.no: 11-15). Refer to the following Line Graph and answer the given questions.

 

The number of students who could pass the exam in the year 2016 were 10% more than that in the previous year. Only 75% of those who appeared in the year 2016 could pass the exam that year. How many students appeared for the exam in the year 2016?

Detailed Solution: Question 11

Number of students who could pass the exam in the year 2016 = 110% of 240 = 264
75% of x = 264
x = 264 * 100/75 = 352

Test: Data Interpretation- 3 - Question 12

(Q.no: 11-15). Refer to the following Line Graph and answer the given questions.

 

Number of students who had passed the exam in the year 2012 are what percent less than that in the year 2013?

Detailed Solution: Question 12

Required % = (70/210) * 100 = 100/3 %

Test: Data Interpretation- 3 - Question 13

(Q.no: 11-15). Refer to the following Line Graph and answer the given questions.

 

What percent of students who appeared for the exam in the year 2011 could pass the exam?

Detailed Solution: Question 13

% = 180/240 * 100 = 75%

Test: Data Interpretation- 3 - Question 14

(Q.no: 11-15). Refer to the following Line Graph and answer the given questions.

 

What is the respective ratio of total number of students who appeared for the exam in the years 2014 and 2015 together and the total number of students who could pass the exam in the same years together?

Detailed Solution: Question 14

Total number of appeared candidates in the years 2014 and 2015 together = 620
Total number of passed candidates in the years 2014 and 2015 together = 520
= 620 : 500
= 31 : 25

Test: Data Interpretation- 3 - Question 15

(Q.no: 11-15). Refer to the following Line Graph and answer the given questions.

 

What is the average number of students who passed for the exam in all the years together?

Detailed Solution: Question 15

Average number of students who passed in all the years together =[180 + 140 + 210 + 260 +240]/5 = 206

Test: Data Interpretation- 3 - Question 16

 (Q.no: 16-20). Refer to the following table and answer the given questions.

If the number of male post graduate employees in company W is 1488, what percent of the female employees in that particular company are post graduate?

Detailed Solution: Question 16

Number of Females in Company W = 3360 *(5/14) = 1200
Number of Post graduate employees in Company W = 3360 *(80/100) = 2688
Number of female post graduate employees in Company W = 2688 – 1488 = 1200
Required Percentage = (1200 * 100)/1200 = 100%

Test: Data Interpretation- 3 - Question 17

 (Q.no: 16-20). Refer to the following table and answer the given questions.

In which of the given companies is the percentage of women employees with respect to the total number of employees(both males and females) in that company the third lowest?

Detailed Solution: Question 17

Company P : ([7/12 * (2568)] / 2568)*100 = 58.33%
Company Q : ([5/16 * (2880)] / 2880)*100 = 31.25%
Company R : ([11/21 * (2310)] / 2310)*100 = 52.38%
Company S : ([2/5 * (3575)] / 3575)*100 = 40%
Company T : ([6/13 * (2054)] / 2054)*100 = 46.15%
Company U : ([21/41 * (2788)] / 2788)*100 = 51.21%
Company V : ([7/15 * (3720)] / 3720)*100 = 46.66%
Company W : ([5/14 * (3360)] / 3360)*100 = 35.71%

Test: Data Interpretation- 3 - Question 18

 (Q.no: 16-20). Refer to the following table and answer the given questions.

What is the ratio of the total number of male employees in companies Q and W together to the total number of female employees in Companies R and S together?

Detailed Solution: Question 18

= [2880 * (11/16)/ 2310 * (11/21) + 3360 * (9/14)/ 3575 * (2/5)] = (1980 + 2160)/(1210 + 1430) = 414/264 = 69:44

Test: Data Interpretation- 3 - Question 19

 (Q.no: 16-20). Refer to the following table and answer the given questions.

What is the sum of the average number of post graduate employees in companies P, Q and S together and the average number of post graduate employees in companies U, V and W?

Detailed Solution: Question 19

Average number of post graduate employees in companies P, Q and S = (1926 + 1872 + 2145)/3 = 5943/3 = 1981
Average number of post graduate employees in companies U, V and W = (2091 + 2046 + 2688)/3 = 6875/3 = 2275
Difference = 2275 + 1981 = 4256

Test: Data Interpretation- 3 - Question 20

 (Q.no: 16-20). Refer to the following table and answer the given questions.

Which of the given companies has the second highest number of average employees per office?

Detailed Solution: Question 20

Company P – 2568/16 = 160.5 ; Company Q – 2880/18 = 160
Company R – 2310/14 = 165 ; Company S – 3575/22 = 162.5
Company T – 2054/13 = 158 ; Company U – 2788/17 = 164
Company V – 3720/24 = 155 ; Company W – 3360/21 = 160

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