Bank Exams Exam  >  Bank Exams Tests  >   Probability - MCQ 2 - Bank Exams MCQ

Probability - MCQ 2 - Bank Exams MCQ


Test Description

20 Questions MCQ Test - Probability - MCQ 2

Probability - MCQ 2 for Bank Exams 2024 is part of Bank Exams preparation. The Probability - MCQ 2 questions and answers have been prepared according to the Bank Exams exam syllabus.The Probability - MCQ 2 MCQs are made for Bank Exams 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Probability - MCQ 2 below.
Solutions of Probability - MCQ 2 questions in English are available as part of our course for Bank Exams & Probability - MCQ 2 solutions in Hindi for Bank Exams course. Download more important topics, notes, lectures and mock test series for Bank Exams Exam by signing up for free. Attempt Probability - MCQ 2 | 20 questions in 15 minutes | Mock test for Bank Exams preparation | Free important questions MCQ to study for Bank Exams Exam | Download free PDF with solutions
Probability - MCQ 2 - Question 1

A bag contains 5 red and 7 white balls. Four balls are drawn out one by one and not replaced. What is the probability that they are alternatively of different colours?

Detailed Solution for Probability - MCQ 2 - Question 1

Balls are picked in two manners – RWRW or WRWR
So probability = (5/12)*(7/11)*(4/10)*(6/9) + (7/12)*(5/11)*(6/10)*(4/9) = 14/99

Probability - MCQ 2 - Question 2

P and Q are sitting in a ring with 11 other persons. If the arrangement of 11 persons is at random, then the probability that there are exactly 4 persons between them?

Detailed Solution for Probability - MCQ 2 - Question 2

Fix the position of P, then Q can be sit in 12 positions, so total possible outcome = 12
Now, exactly 4 persons are sitting between them. This can be done in two ways as
shown in figure, so favourable outcomes = 2
So, probability = 2/12 = 1/6

1 Crore+ students have signed up on EduRev. Have you? Download the App
Probability - MCQ 2 - Question 3

10 persons are seated around a round table. What is the probability that 4 particular persons are always seated together?

Detailed Solution for Probability - MCQ 2 - Question 3

Total outcomes = (10 -1)! = 9!
Favourable outcomes = 6!*4! (4 person seated together and 6 other persons seated randomly, so they will sit in (7-1)! Ways and those 4 persons can be arranged in 4! ways)
So probability = 1/21

Probability - MCQ 2 - Question 4

A box contains 4 red, 5 black and 6 green balls. 3 balls are drawn at random. What is the probability that all the balls are of same colour?

Detailed Solution for Probability - MCQ 2 - Question 4

(4c3 + 5c3 + 6c3)/15c3 = 34/455

Probability - MCQ 2 - Question 5

An apartment has 8 floors. An elevator starts with 4 passengers and stops at 8 floors of the apartment. What is the probability that all passengers travels to different floors?

Detailed Solution for Probability - MCQ 2 - Question 5

Total outcomes = 8*8*8*8
Favourable outcomes = 8*7*6*5 (first person having 8 choices, after that second person have 7 choices and so on)
So, probability = 105/256

Probability - MCQ 2 - Question 6

A speaks truth in 60% of the cases and B in 80% of the cases. In what  percentage of cases are they likely to contradict each other, narrating the same incident?

Detailed Solution for Probability - MCQ 2 - Question 6

Let  A = Event that A speaks the truth

and B= Event  that B speaks the truth. 

                

Then,  P ( A)  = 60/ 100 = ⅗ 

            P ( B)  = 80/ 100 =  ⅘ 

             _    

:-     P  ( A) =  ( 1- ⅗  )  = 2 / 5 

             _         

        P ( B )  = (1 - 4 /5 ) =  1 / 5

        P ( A and B  contradict each other) 

      = P [ ( A speaks truth and B tells a lie) or 

              ( A tells the lie and B speaks the truth) ]

                              _         _

       =  P [ ( A and B)  or (  A  and  B)]

                            _              _

         = P ( A and B)  +    P ( A  and B) 

                               _                _

         =  P (A) *  P ( B)  +     P ( A) *  P ( B) 

 

          =  (  3 / 5 * 1 / 5 ) +      ( 2 / 5 * 4 / 5 ) 

           =  3 / 25 + 8 / 25 

           =  11 / 25 

            = [ 11/ 25 * 100 ] % 

             

             =  44%

Probability - MCQ 2 - Question 7

A box contains 30 electric bulbs, out of which 8 are defective. Four bulbs are chosen at random from this box. Find the probability that at least one of them is defective?

Detailed Solution for Probability - MCQ 2 - Question 7

1 – 22c4/30c4 = 1 – 209/783 = 574/783

Probability - MCQ 2 - Question 8

Two person A and B appear in an interview. The probability of A’s selection is 1/5 and the probability of B’s selection is 2/7. What is the probability that only one of them is selected?

Detailed Solution for Probability - MCQ 2 - Question 8

A selects and B rejects + B selects and A rejects = (1/5)*(5/7) + (4/5)*(2/7) = 13/35

Probability - MCQ 2 - Question 9

A 4- digit number is formed by the digits 0, 1, 2, 5 and 8 without repetition. Find the probability that the number is divisible by 5.

Detailed Solution for Probability - MCQ 2 - Question 9

Probability - MCQ 2 - Question 10

A bag contains 6 red balls and 8 green balls. 2 balls are drawn at random one by one with replacement. Find the probability that both the balls are green

Detailed Solution for Probability - MCQ 2 - Question 10

(8c1)/(14c1) * (8c1)*(14c1) = 16/49

Probability - MCQ 2 - Question 11

A six-digit is to be formed from the given numbers 1, 2, 3, 4, 5 and 6. Find the probability that the number is divisible by 4.

Detailed Solution for Probability - MCQ 2 - Question 11

For a number to be divisible by 4, the last two digit should be divisible by 4.
So possible cases – 12, 16, 24, 32, 36, 52, 56, 64 (last two digits)
So favourable outcomes = 24 +24 +24 +24 + 24+ 24+24+24 = 192
So p = 192/720 = 4/15

Probability - MCQ 2 - Question 12

A bag contains 6 red balls and 7 white balls. Another bag contains 5 red balls and 3 white balls. One ball is selected from each. Find the probability that one ball is red and one is white?

Detailed Solution for Probability - MCQ 2 - Question 12

(6/13)*(3/8) + (7/13)*(5/8) = 53/104

Probability - MCQ 2 - Question 13

A lottery is organised by the college ABC through which they will provide scholarship of rupees one lakhs to only one student. There are 100 fourth year students, 150 third year students, 200 second year students and 250 first year students. What is the probability that a second year student is choosen.

Detailed Solution for Probability - MCQ 2 - Question 13

Second year students = 200
so, P = 200/700 = 2/7

Probability - MCQ 2 - Question 14

A card is drawn from a pack of 52 cards. The card is drawn at random; find the probability that it is neither club nor queen?

Detailed Solution for Probability - MCQ 2 - Question 14

1 – [13/52 + 4/52 – 1/52] = 9/13

Probability - MCQ 2 - Question 15

A box contains 50 balls, numbered from 1 to 50. If three balls are drawn at random with replacement. What is the probability that sum of the numbers are odd?

Detailed Solution for Probability - MCQ 2 - Question 15

There are 25 odd and 25 even numbers from 1 to 50.
Sum will be odd if = odd + odd + odd, odd + even + even, even + odd + even, even+ even + odd
P = (1/2)*(1/2)*(1/2) + (1/2)*(1/2)*(1/2) + (1/2)*(1/2)*(1/2) + (1/2)*(1/2)*(1/2)
=4/8 = ½

Probability - MCQ 2 - Question 16

From a pack of cards, if three cards are drawn at random one after the other with replacement, find the probability that one is ace, one is jack and one is queen?

Detailed Solution for Probability - MCQ 2 - Question 16

(4c1 + 4c1 + 4c1)/(52c3)

Probability - MCQ 2 - Question 17

A and B are two persons sitting in a circular arrangement with 8 other persons. Find the probability that both A and B sit together.

Detailed Solution for Probability - MCQ 2 - Question 17

Total outcomes = (10 -1)! = 9!
Favourable outcomes = (9 -1)!*2!
So p = 2/9

Probability - MCQ 2 - Question 18

Find the probability that in a random arrangement of the letter of words in the word ‘PROBABILITY’ the two I’s come together.

Detailed Solution for Probability - MCQ 2 - Question 18

Total outcomes = 11!/(2!*2!)
favourable outcomes = (10!*2!)/(2!*2!)
p = 2/11

Probability - MCQ 2 - Question 19

In a race of 12 cars, the probability that car A will win is 1/5 and of car B is 1/6 and that of car C is 1/3. Find the probability that only one of them won the race.

Detailed Solution for Probability - MCQ 2 - Question 19

1/5 + 1/6 + 1/3= 7/10 (all events are mutually exclusive)

Probability - MCQ 2 - Question 20

A bag contains 3 red balls and 8 blacks ball and another bag contains 5 red balls and 7 blacks balls, one ball is drawn at random from either of the bag, find the probability that the ball is red.

Detailed Solution for Probability - MCQ 2 - Question 20

Probability = probability of selecting the bag and probability of selecting red ball
(1/2)*(3/11) + (1/2)*(5/12) = 91/264

Information about Probability - MCQ 2 Page
In this test you can find the Exam questions for Probability - MCQ 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Probability - MCQ 2, EduRev gives you an ample number of Online tests for practice

Top Courses for Bank Exams

Download as PDF

Top Courses for Bank Exams