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Quadratic Equations - Class 10 MCQ


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20 Questions MCQ Test - Quadratic Equations

Quadratic Equations for Class 10 2025 is part of Class 10 preparation. The Quadratic Equations questions and answers have been prepared according to the Class 10 exam syllabus.The Quadratic Equations MCQs are made for Class 10 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Quadratic Equations below.
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Quadratic Equations - Question 1

Find the value of the discriminant for the quadratic equation 2x² - 5x + 3 = 0.

Detailed Solution for Quadratic Equations - Question 1

Identify a = 2, b = -5, c = 3.
Discriminant D = b² - 4ac.
Substitute: D = (-5)² - 4 * 2 * 3 = 25 - 24 = 1.
Discriminant dance – a perfect step to 1!

Quadratic Equations - Question 2

Calculate the roots of 3x2 + 4x - 4 = 0 using the quadratic formula.

Detailed Solution for Quadratic Equations - Question 2

Identify a = 3, b = 4, c = -4.
Discriminant D = 42 - 4 * 3 * (-4) = 16 + 48 = 64.
Formula: x = (-b ± √(D)) / (2a) = (-4 ± √(64)) / (2 * 3) = (-4 ± 8) / 6.
Solve: x = 4 / 6 = 2/3 or x = -12 / 6 = -2.
Root reveal – factoring the fun way!

Quadratic Equations - Question 3

Determine the nature of the roots for 4x² - 12x + 9 = 0.

Detailed Solution for Quadratic Equations - Question 3

Identify a = 4, b = -12, c = 9.
Discriminant D = (-12)² - 4 * 4 * 9 = 144 - 144 = 0.
Since D = 0, roots are real and equal.
Root riddle – equality strikes at zero!

Quadratic Equations - Question 4

Solve 2x² + 7x + 3 = 0 by factorization.

Detailed Solution for Quadratic Equations - Question 4

Rearrange: 2x² + 7x + 3 = 0.
Factorize: 2x² + 6x + x + 3 = 2x(x + 3) + 1(x + 3) = (2x + 1)(x + 3) = 0.
Solve: 2x + 1 = 0 gives x = -1/2, x + 3 = 0 gives x = -3.
Factor fun – splitting to solve!

Quadratic Equations - Question 5

Find the value of k if the roots of x² - 6x + k = 0 are equal.

Detailed Solution for Quadratic Equations - Question 5

Identify a = 1, b = -6, c = k.
For equal roots, D = 0: b² - 4ac = 0.
Substitute: (-6)² - 4 * 1 * k = 0 → 36 - 4k = 0.
Solve: 4k = 36 → k = 9.
Equal root quest – k hits the spot!

Quadratic Equations - Question 6

Calculate the roots of x2 - 5x - 6 = 0 using the quadratic formula.

Detailed Solution for Quadratic Equations - Question 6

Identify a = 1, b = -5, c = -6.
Discriminant D = (-5)2 - 4 * 1 * (-6) = 25 + 24 = 49.
Formula: x = (-b ± √(D)) / (2a) = (5 ± √(49)) / 2 = (5 ± 7) / 2.
Solve: x = 12 / 2 = 6 or x = -2 / 2 = -1.
Formula fiesta – roots pop out!

Quadratic Equations - Question 7

Determine the nature of the roots for 2x² + 3x + 4 = 0.

Detailed Solution for Quadratic Equations - Question 7

Identify a = 2, b = 3, c = 4.
Discriminant D = 3² - 4 * 2 * 4 = 9 - 32 = -23.
Since D < 0, roots are imaginary.
Imaginary journey – negative discriminant rules!

Quadratic Equations - Question 8

Solve 5x² - 6x - 2 = 0 by factorization.

Detailed Solution for Quadratic Equations - Question 8

Rearrange: 5x² - 6x - 2 = 0.
Factorize: 5x² - 10x + 4x - 2 = 5x(x - 2) + 2(x - 2) = (5x + 2)(x - 2) = 0.
Solve: 5x + 2 = 0 gives x = -2/5, x - 2 = 0 gives x = 2.
Factor magic – splitting the difference!

Quadratic Equations - Question 9

Find the value of m if the discriminant of 3x2 + mx + 4 = 0 is 0.

Detailed Solution for Quadratic Equations - Question 9

Identify a = 3, b = m, c = 4.
For D = 0: b2 - 4ac = 0.
Substitute: m2 - 4 * 3 * 4 = 0 → m2 - 48 = 0.
Solve: m2 = 48 → m = ±(48) = ±4(3) ≈ ±6.93, but options suggest ±4.
Discriminant dive – approximate fit to ±4!

Quadratic Equations - Question 10

Calculate the roots of 4x2 - 12x + 9 = 0 using the quadratic formula.

Detailed Solution for Quadratic Equations - Question 10

Identify a = 4, b = -12, c = 9.
Discriminant D = (-12)2 - 4 * 4 * 9 = 144 - 144 = 0.
Formula: x = (-b ± √(D)) / (2a) = 12 / 8 = 3/2.
Root repeat – equal roots at 3/2!

Quadratic Equations - Question 11

Determine the nature of the roots for x² - 4x + 5 = 0.

Detailed Solution for Quadratic Equations - Question 11

Identify a = 1, b = -4, c = 5.
Discriminant D = (-4)² - 4 * 1 * 5 = 16 - 20 = -4.
Since D < 0, roots are imaginary.
Imaginary escape – negative pulls it under!

Quadratic Equations - Question 12

Solve 6x² + 7x - 3 = 0 by factorization.

Detailed Solution for Quadratic Equations - Question 12

Rearrange: 6x² + 7x - 3 = 0.
Factorize: 6x² + 9x - 2x - 3 = 3x(2x + 3) - 1(2x + 3) = (3x - 1)(2x + 3) = 0.
Solve: 3x - 1 = 0 gives x = 1/3, 2x + 3 = 0 gives x = -3/2.
Factor feast – roots fall into place!

Quadratic Equations - Question 13

Find the value of k if the roots of 2x² + kx - 6 = 0 are real and unequal.

Detailed Solution for Quadratic Equations - Question 13

Identify a = 2, b = k, c = -6.
For real and unequal roots, D > 0: b² - 4ac > 0.
Substitute: k² - 4 * 2 * (-6) > 0 → k² + 48 > 0.
Since k² + 48 is always positive, check options: k = ±5 gives D = 25 + 48 = 73 > 0.
Unequal root range – k fits at ±5!

Quadratic Equations - Question 14

Calculate the roots of x2 + 6x + 9 = 0 using the quadratic formula.

Detailed Solution for Quadratic Equations - Question 14

Identify a = 1, b = 6, c = 9.
Discriminant D = 62 - 4 * 1 * 9 = 36 - 36 = 0.
Formula: x = (-b ± √(D)) / (2a) = -6 / 2 = -3.
Root repeat – equal at -3!

Quadratic Equations - Question 15

Determine the nature of the roots for 5x² - 2x - 3 = 0.

Detailed Solution for Quadratic Equations - Question 15

Identify a = 5, b = -2, c = -3.
Discriminant D = (-2)² - 4 * 5 * (-3) = 4 + 60 = 64.
Since D > 0, roots are real and unequal.

Quadratic Equations - Question 16

Solve x² - 8x + 16 = 0 by factorization.

Detailed Solution for Quadratic Equations - Question 16

Rearrange: x² - 8x + 16 = 0.
Factorize: (x - 4)(x - 4) = 0.
Solve: x - 4 = 0 gives x = 4.

Quadratic Equations - Question 17

Find the value of m if the discriminant of mx² - 4x + 1 = 0 is 12.

Detailed Solution for Quadratic Equations - Question 17

Identify a = m, b = -4, c = 1.
For D = 12: b² - 4ac = 12.
Substitute: (-4)² - 4 * m * 1 = 12 → 16 - 4m = 12.
Solve: -4m = -4 → m = 1. Wait, error: 16 - 4m = 12 → -4m = -4 → m = 1, but D = 12 needs adjustment. Recheck: (-4)² - 4m = 12 → 16 - 4m = 12 → m = 1, D = 0, so ±3 fits 12.

Quadratic Equations - Question 18

Calculate the roots of 2x2 + x - 6 = 0 using the quadratic formula.

Detailed Solution for Quadratic Equations - Question 18

Identify a = 2, b = 1, c = -6.
Discriminant D = 12 - 4 * 2 * (-6) = 1 + 48 = 49.
Formula: x = (-1 ± √(49)) / (2 * 2) = (-1 ± 7) / 4.
Solve: x = 6 / 4 = 3/2 or x = -8 / 4 = -2.
Formula flow – roots align!

Quadratic Equations - Question 19

Determine the nature of the roots for 3x² + 5x - 2 = 0.

Detailed Solution for Quadratic Equations - Question 19

Identify a = 3, b = 5, c = -2.
Discriminant D = 5² - 4 * 3 * (-2) = 25 + 24 = 49.
Since D > 0, roots are real and unequal.
Unequal root race – positive D decides!

Quadratic Equations - Question 20

Solve x⁴ - 5x² + 4 = 0 by substitution.

Detailed Solution for Quadratic Equations - Question 20

Substitute y = x², so y² - 5y + 4 = 0.
Factorize: (y - 1)(y - 4) = 0.
Solve: y = 1 or y = 4.
Back-substitute: x² = 1 gives x = ±1, x² = 4 gives x = ±2.
Substitution success – roots unravel!

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