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Test: Finite Automata With Epsilon Transition - Computer Science Engineering (CSE) MCQ


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10 Questions MCQ Test - Test: Finite Automata With Epsilon Transition

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Test: Finite Automata With Epsilon Transition - Question 1

 According to the given transitions, which among the following are the epsilon closures of q1 for the given NFA?
Δ (q1, ε) = {q2, q3, q4}
Δ (q4, 1) =q1
Δ (q1, ε) =q1

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 1

The set of states which can be reached from q using ε-transitions, is called the ε-closure over state q.

Test: Finite Automata With Epsilon Transition - Question 2

State true or false?Statement: An NFA can be modified to allow transition without input alphabets, along with one or more transitions on input symbols.

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 2

It is possible to construct an NFA with ε-transitions, presence of no input symbols, and that is called NFA with ε-moves.

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Test: Finite Automata With Epsilon Transition - Question 3

State true or false?Statement: ε (Input) does not appears on Input tape.

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 3

ε does not appears on Input tape, ε transition means a transition without scanning a symbol i.e. without moving the read head.

Test: Finite Automata With Epsilon Transition - Question 4

Statement 1: ε- transition can be called as hidden non-determinism.
Statement 2: δ (q, ε) = p means from q it can jump to p with a shift in read head.
Which among the following options is correct?

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 4

 The transition with ε leads to a jump but without any shift in read head. Further, the method can be called one to introduce hidden non-determinism.

Test: Finite Automata With Epsilon Transition - Question 5

According to the given transitions, which among the following are the epsilon closures of q1 for the given NFA?
Δ (q1, ε) = {q2, q3, q4}
Δ (q4, 1) =q1
Δ (q1, ε) =q1

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 5

The set of states which can be reached from q using ε-transitions, is called the ε-closure over state q.

Test: Finite Automata With Epsilon Transition - Question 6

Predict the total number of final states after removing the ε-moves from the given NFA?

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 6

The NFA which would result after eliminating ε-moves can be shown diagramatically.

Test: Finite Automata With Epsilon Transition - Question 7

 For NFA with ε-moves, which among the following is correct?

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 7

Due to the presence of ε symbol, or rather an epsilon-move, the input alphabets unites with it to form a set including ε.

Test: Finite Automata With Epsilon Transition - Question 8

Which among the following is false?
ε-closure of a subset S of Q is:

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 8

All the mentioned are the closure properties of ε and encircles all the elements if it satisfies the following options:
a) Every element of S ϵ Q
b) For any q ϵ ε(S), every element of δ (q, ε) is in ε(S)
c) No other element is in ε(S)

Test: Finite Automata With Epsilon Transition - Question 9

 The automaton which allows transformation to a new state without consuming any input symbols:

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 9

 NFA-l or e-NFA is an extension of Non deterministic Finite Automata which are usually called NFA with epsilon moves or lambda transitions.

Test: Finite Automata With Epsilon Transition - Question 10

 e-transitions are

Detailed Solution for Test: Finite Automata With Epsilon Transition - Question 10

An epsilon move is a transition from one state to another that doesnt require any specific condition.

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