All Courses
Get the App Signup / Login
Sign in Open App
JEE Exam  >  JEE Tests  >  JEE Main Chemistry Test- 1 - JEE MCQ

JEE Main Chemistry Test- 1 - JEE MCQ


Test Description

25 Questions MCQ Test - JEE Main Chemistry Test- 1

JEE Main Chemistry Test- 1 for JEE 2024 is part of JEE preparation. The JEE Main Chemistry Test- 1 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Chemistry Test- 1 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Chemistry Test- 1 below.
Solutions of JEE Main Chemistry Test- 1 questions in English are available as part of our course for JEE & JEE Main Chemistry Test- 1 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main Chemistry Test- 1 | 25 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
JEE Main Chemistry Test- 1 - Question 1
Save

 20 g of an ideal gas contains only atoms of S and O occupies 5.6 L at NPT. What is the mol. wt. of gas ?

Detailed Solution for JEE Main Chemistry Test- 1 - Question 1

Given,
Mass of gas = 20 g
Pressure of gas = 1 atm
Volume of gas = 5.6 L
Temperature of gas = 273 K
Using ideal gas law,

where,
P = pressure of the gas
V = volume of the gas
T = temperature of the gas
n = number of moles of the gas
R = gas constant = 0.0821
Latm/moleK
M = molar mass of gas
w = mass of gas
Now put all the given values in the formula, we get
Therefore, the molar mass of the gas is, 80.0475 g/mole

JEE Main Chemistry Test- 1 - Question 2
Save

5.6 litres of a gas at N.T.P. are found to have a mass of 11 g. The molecular mass of the gas is

Detailed Solution for JEE Main Chemistry Test- 1 - Question 2
1 mole or molecular mass of the gas has volume 22.4 L
Given that:
11g of gas has volume 5.6 L

So molecular mass = (11/5.6)×22.4 = 44 u
1 Crore+ students have signed up on EduRev. Have you? Download the App
JEE Main Chemistry Test- 1 - Question 3
Save

A crystalline salt Na2SO4.xH2O on heating losses 55.9 per cent of its mass. The formula of crystalline salt is---

Detailed Solution for JEE Main Chemistry Test- 1 - Question 3
Na2SO4.xH2O has weight =46+32+64+18x=142+18xg
on heating it will become anhydrous so, I.e. water will be evaporated.
55.9% of(142+18x)=18x=>79.378+10.062x=18x
=>7.938x=79.378=>x~10g
so Na2SO4.10H2O and this amount of water is called
water of crystallisation.
JEE Main Chemistry Test- 1 - Question 4
Save

Vapour density of a metal chloride is 66. Its oxide contains 53% metal. The atomic weight of the metal is
Detailed Solution for JEE Main Chemistry Test- 1 - Question 4
Equivalent of metal = Equivalent of chloride

53/n = 47/8 , E = 9.02 , Atomic mass of metal = n X 9.02

Molecular mass of chloride = 2 X 66 = n X 9.02 + n X 35.5

on solving n = 3

Atomic mass of metal = 9.02 X 3 = 27.06
JEE Main Chemistry Test- 1 - Question 5
Save

When two aqueous solutions react together to give off solid product, this reaction is known as
Detailed Solution for JEE Main Chemistry Test- 1 - Question 5
Chemical reactions:precipitation. The precipitate forms because the solid (AgCl) is insoluble in water. That is true for all precipitates - the solids are insoluble in aqueous solutions. Precipitation reaction occur all around us.
JEE Main Chemistry Test- 1 - Question 6
Save

At S.T.P. the density of CCl4 vapour in g/L will be nearest to
Detailed Solution for JEE Main Chemistry Test- 1 - Question 6
Stp of mole of a gas = 22.4L 1mole --> 154g of CCl4 density=mass/volume =154/22.4 = 6.875
JEE Main Chemistry Test- 1 - Question 7
Save

Which of the following transitions of electrons in the hydrogen, atom will emit maximum energy ?
Detailed Solution for JEE Main Chemistry Test- 1 - Question 7

JEE Main Chemistry Test- 1 - Question 8
Save

The uncertainty found from the uncertainty principle  (Δx.Δp = h/4 π) is
Detailed Solution for JEE Main Chemistry Test- 1 - Question 8
Heisenberg uncertainty principle states that exact momentum and exact position of matter wave can't be determined simultaneously.
∆P.∆X>equal to h/4π
JEE Main Chemistry Test- 1 - Question 9
Save

The number of atoms of hydrogen in 2 moles of NH3
Detailed Solution for JEE Main Chemistry Test- 1 - Question 9

Therefore 2 moles will have 1.204*1024 molecules of NH3.

There are 3 atoms in each molecule, so 2 moles will have 3*(1.204*1024) atoms

which is 3.61 * 1024 atoms.

JEE Main Chemistry Test- 1 - Question 10
Save

The spectrum of He is expected to be similar to that of
Detailed Solution for JEE Main Chemistry Test- 1 - Question 10

The spectrum of an atom depends on the number of electrons present in it. Here, helium has two electrons, so the spectrum of Li+ (Z = 3) is similar to that of helium because both He and Li+ have two electrons.

JEE Main Chemistry Test- 1 - Question 11
Save

The electrons present in K-shell of the atom will differ in
Detailed Solution for JEE Main Chemistry Test- 1 - Question 11
The electrons present in K-shell of the atom will differ in spin quantum number as the electrons will have opposite spins.
JEE Main Chemistry Test- 1 - Question 12
Save

Which of the following statements about quantum numbers is wrong?
Detailed Solution for JEE Main Chemistry Test- 1 - Question 12

If the value of l=0, then electron lies in s-subshell which has spherical shape. So electron distribution is spherical.

Shape of orbital is given by azimuthal quantum number as it describes the subshell.

Magnetic quantum number determines the shift of atomic orbital due to external magnetic field i.e., zeeman effect.

Spin quantum number describes the spin of electron in particular orbital. Orientations of electron cloud is specified of a magnetic quantum number.

So B option is incorrect.

JEE Main Chemistry Test- 1 - Question 13
Save

Out of the two compounds shown below, the vapour pressing of B at a particular temperature is expected to be
Detailed Solution for JEE Main Chemistry Test- 1 - Question 13

Because of intramolecular hydrogen bonding in (B), i.e., ortho nitrophenol, the vapour pressure of ortho nitrophenol is expected to be higher than paranitrophenol.

Therefore, the correct option is A.

JEE Main Chemistry Test- 1 - Question 14
Save

In which of the following molecules, the central atom does not use sP3-hybrid orbitals in its bonding ?
Detailed Solution for JEE Main Chemistry Test- 1 - Question 14

In the given options, BeF3−​, Be forms three sigma bonds with three flourines.

So, hybridisation of Be becomes sp2. 

Hence, the correct answer is option A.

JEE Main Chemistry Test- 1 - Question 15
Save

The correct increasing bond angle among ,  and 
Detailed Solution for JEE Main Chemistry Test- 1 - Question 15

BF3​is trigonal planar which makes the angle as 120 degree.PF3​ is trigonal bipyramidal making the angle slightly less than 109 degrees ClF3​ is T-shaped making the least angle.

JEE Main Chemistry Test- 1 - Question 16
Save
Calculated bond order in the superoxide () ion is 
Detailed Solution for JEE Main Chemistry Test- 1 - Question 16
O2^- (superoxide) = 13 valence e⁻. = σs(2 e⁻) σs*(2e⁻) σp(2e⁻) πp(4e⁻) πp*(3e⁻) σp*(0) . bond order = ½[ σs(2e⁻) σp(2e⁻) πp(4 e⁻) - σs*(2e⁻) πp*(3e⁻) ]. = ½[8-5] = 1.5
JEE Main Chemistry Test- 1 - Question 17
Save

The ionic species having largest size is
Detailed Solution for JEE Main Chemistry Test- 1 - Question 17


Li+ ion being smallest in size is heavily hydrated and thus Li+(aq) is largest in size.

JEE Main Chemistry Test- 1 - Question 18
Save

From which of the following species it is easiest to remove one electron ?
Detailed Solution for JEE Main Chemistry Test- 1 - Question 18

Energy is released when an electron is added to the atom. Hence 1st electron affinity (EA1​) is always taken as negative. The addition of second electron to the negativity charged ions is opposed by Coulombic repulsion, hence energy has to be supplied for the addition of second electron. Hence (EA2​) is taken as positive. 

 

Addition of an electron to F− and O− ions will involve repulsions, hence their (EA2​) will be positive.
Due to stable fully filled configuration of Na+ (1s2 2s2 2p6) it has lower value of electron affinity than O. Hence O has highest electron affinity.

JEE Main Chemistry Test- 1 - Question 19
Save
With respect to chlorine, hydrogen will be
Detailed Solution for JEE Main Chemistry Test- 1 - Question 19
With respect to Chlorine, hydrogen will be electropositive.

Reason:

Chlorine being a strong electronegative element tends to force hydrogen to lose electron and hydrogen acquire electropositive character so that chlorine can complete its octet. 

JEE Main Chemistry Test- 1 - Question 20
Save

Which element has the greatest tendency to lose electrons ?
Detailed Solution for JEE Main Chemistry Test- 1 - Question 20
Fe has high electronegativity. it is a metal and it has proper to lose electron
*Answer can only contain numeric values
JEE Main Chemistry Test- 1 - Question 21
Save

0.01 mole of iodoform (CHI3) reacts with Ag to produce a gas whose volume at NTP in ml is :-
2CHI3 + 6Ag —→ 6AgI(s) + C2H2(g)

Detailed Solution for JEE Main Chemistry Test- 1 - Question 21

mol of C2H2 = 1/2 × mol of CHI3
= 1/2 × 0.01 = 0.005
volume at N.T.P. = 0.005 × 22400 = 112 ml

*Answer can only contain numeric values
JEE Main Chemistry Test- 1 - Question 22
Save

Sum of σ and π bonds are present in CH3COOH?

Detailed Solution for JEE Main Chemistry Test- 1 - Question 22

Single bond is σ bond and double bond contains 1σ and 1 π bond. Therefore, it contains 7 σ and 1 π bond. Hence, total is 8

*Answer can only contain numeric values
JEE Main Chemistry Test- 1 - Question 23
Save

How many maximum electrons can be accomodate in 7th shell of element X?

Detailed Solution for JEE Main Chemistry Test- 1 - Question 23

Maximum number of electron in a shell
= 2n2
= 2(7)2
= 98

*Answer can only contain numeric values
JEE Main Chemistry Test- 1 - Question 24
Save

 

How many groups show – I effect?

Detailed Solution for JEE Main Chemistry Test- 1 - Question 24

*Answer can only contain numeric values
JEE Main Chemistry Test- 1 - Question 25
Save

Number of lone pair present in P4O6.

Detailed Solution for JEE Main Chemistry Test- 1 - Question 25

Information about JEE Main Chemistry Test- 1 Page
In this test you can find the Exam questions for JEE Main Chemistry Test- 1 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main Chemistry Test- 1, EduRev gives you an ample number of Online tests for practice

Top Courses for JEE

Download as PDF

Top Courses for JEE

Important Questions for JEE Main Chemistry Test- 1

Find all the important questions for JEE Main Chemistry Test- 1 at EduRev.Get fully prepared for JEE Main Chemistry Test- 1 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the JEE Main Chemistry Test- 1 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of JEE Main Chemistry Test- 1 resources.

JEE Main Chemistry Test- 1 MCQs with Answers

Prepare for the JEE Main Chemistry Test- 1 within the JEE exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for JEE Main Chemistry Test- 1

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace JEE Main Chemistry Test- 1 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup