All Courses
Get the App Signup / Login
Sign in Open App
Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Gradient - Electrical Engineering (EE) MCQ

Test: Gradient - Electrical Engineering (EE) MCQ


Test Description

10 Questions MCQ Test - Test: Gradient

Test: Gradient for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Gradient questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Gradient MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Gradient below.
Solutions of Test: Gradient questions in English are available as part of our course for Electrical Engineering (EE) & Test: Gradient solutions in Hindi for Electrical Engineering (EE) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Gradient | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Gradient - Question 1
Save

Gradient of a function is a constant. State True/False.

Detailed Solution for Test: Gradient - Question 1

Answer: b
Explanation: Gradient of any scalar function may be defined as a vector. The vector’s magnitude and direction are those of the maximum space rate of change of φ.

Test: Gradient - Question 2
Save

The mathematical perception of the gradient is said to be

Detailed Solution for Test: Gradient - Question 2

Answer: c
Explanation: The gradient is the rate of change of space of flux in electromagnetics. This is analogous to the slope in mathematics.

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Gradient - Question 3
Save

Divergence of gradient of a vector function is equivalent to

Detailed Solution for Test: Gradient - Question 3

Answer: a
Explanation: Div (Grad V) = (Del)2V, which is the Laplacian operation. A function is said to be harmonic in nature, when its Laplacian tends to zero.

Test: Gradient - Question 4
Save

4. The gradient of xi + yj + zk is
Detailed Solution for Test: Gradient - Question 4

Answer: d
Explanation: Grad (xi + yj + zk) = 1 + 1 + 1 = 3. In other words, the gradient of any position vector is 3.

Test: Gradient - Question 5
Save

Find the gradient of t = x2y+ ez at the point p(1,5,-2)
Detailed Solution for Test: Gradient - Question 5

Answer: b
Explanation: Grad(t) = 2xy i + x2 j + ez k. On substituting p(1,5,-2), we get 10i + j + 0.135k

Test: Gradient - Question 6
Save

Curl of gradient of a vector is
Detailed Solution for Test: Gradient - Question 6

Explanation: Gradient of any function leads to a vector. Similarly curl of that vector gives another vector, which is always zero for all constants of the vector. A zero value in vector is always termed as null vector(not simply a zero).

Test: Gradient - Question 7
Save

Find the gradient of the function given by, x2 + y2 + z2 at (1,1,1)
Detailed Solution for Test: Gradient - Question 7

Answer: b
Explanation: Grad(x2+y2+z2) = 2xi + 2yj + 2zk. Put x=1, y=1, z=1, the gradient will be 2i + 2j + 2k.

Test: Gradient - Question 8
Save

The gradient can be replaced by which of the following?
Detailed Solution for Test: Gradient - Question 8

Answer: c
Explanation: Since gradient is the maximum space rate of change of flux, it can be replaced by differential equations.

Test: Gradient - Question 9
Save

When gradient of a function is zero, the function lies parallel to the x-axis. State True/False. 
Detailed Solution for Test: Gradient - Question 9

Answer: a
Explanation: Gradient of a function is zero implies slope is zero. When slope is zero, the function will be parallel to x-axis or y value is constant.

Test: Gradient - Question 10
Save

 Find the gradient of the function sin x + cos y.
Detailed Solution for Test: Gradient - Question 10

Grad (sin x + cos y) gives partial differentiation of sin x+ cos y with respect to x and partial differentiation of sin x + cos y with respect to y and similarly with respect to z. This gives cos x i – sin y j + 0 k = cos x i – sin y j.

Information about Test: Gradient Page
In this test you can find the Exam questions for Test: Gradient solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Gradient, EduRev gives you an ample number of Online tests for practice

Top Courses for Electrical Engineering (EE)

Download as PDF

Top Courses for Electrical Engineering (EE)

Important Questions for Gradient

Find all the important questions for Gradient at EduRev.Get fully prepared for Gradient with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the Gradient syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of Gradient resources.

Gradient MCQs with Answers

Prepare for the Gradient within the Electrical Engineering (EE) exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for Gradient

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace Gradient with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup