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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Magnetic Vector Potential - Electrical Engineering (EE) MCQ

Test: Magnetic Vector Potential - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Magnetic Vector Potential

Test: Magnetic Vector Potential for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Magnetic Vector Potential questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Magnetic Vector Potential MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Magnetic Vector Potential below.
Solutions of Test: Magnetic Vector Potential questions in English are available as part of our course for Electrical Engineering (EE) & Test: Magnetic Vector Potential solutions in Hindi for Electrical Engineering (EE) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Magnetic Vector Potential | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Magnetic Vector Potential - Question 1
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The magnetic vector potential is a scalar quantity. 

Detailed Solution for Test: Magnetic Vector Potential - Question 1

Answer: b
Explanation: The magnetic vector potential could be learnt as a scalar. But it is actually a vector quantity, which means it has both magnitude and direction.

Test: Magnetic Vector Potential - Question 2
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Find the magnetic field intensity when the magnetic vector potential x i + 2y j + 3z k.

Detailed Solution for Test: Magnetic Vector Potential - Question 2

Answer: b
Explanation: The magnetic field intensity is given by H = -Grad(Vm). The gradient of Vm is 1 + 2 + 3 = 6. Thus H = -6 units.

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Test: Magnetic Vector Potential - Question 3
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The value of ∫ H.dL will be

Detailed Solution for Test: Magnetic Vector Potential - Question 3

Answer: b
Explanation: By Stoke’s theorem, ∫ H.dL = ∫ Curl(H).dS and from Ampere’s law, Curl(H) = J. Thus ∫ H.dL = ∫ J.dS which is nothing but current I.

Test: Magnetic Vector Potential - Question 4
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Given the vector potential is 16 – 12sin y j. Find the field intensity at the origin.
Detailed Solution for Test: Magnetic Vector Potential - Question 4

Answer: c
Explanation: The field intensity is given by H = – Grad(V). The gradient is given by 0 – 12cos y. At the origin, the gradient will be -12 cos 0 = -12. Thus the field intensity will be 12 units.

Test: Magnetic Vector Potential - Question 5
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Find the vector potential when the field intensity 60x2 varies from (0,0,0) to (1,0,0).
Detailed Solution for Test: Magnetic Vector Potential - Question 5

Answer: b
Explanation: The field intensity H = -Grad(V). To get V, integrate H with respect to the variable. Thus V = -∫H.dl = -∫60x2 dx = -20x3 as x = 0->1 to get -20.

Test: Magnetic Vector Potential - Question 6
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Find the flux density B when the potential is given by x i + y j + z k in air. 
Detailed Solution for Test: Magnetic Vector Potential - Question 6

Answer: b
Explanation: The field intensity H = -Grad(V). Since the given potential is a position vector, the gradient will be 3 and H = -3. Thus the flux density B = μH = 4π x 10-7 x (-3) = -12π x 10-7 units.

Test: Magnetic Vector Potential - Question 7
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The Laplacian of the magnetic vector potential will be
Detailed Solution for Test: Magnetic Vector Potential - Question 7

Answer: a
Explanation: The Laplacian of the magnetic vector potential is given by Del2(A) = -μ J, where μ is the permeability and J is the current density.

Test: Magnetic Vector Potential - Question 8
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The magnetic vector potential for a line current will be inversely proportional to
Detailed Solution for Test: Magnetic Vector Potential - Question 8

Answer: d
Explanation: The magnetic vector potential for the line integral will be A = ∫ μIdL/4πR. It is clear that the potential is inversely proportional to the distance or radius R.

Test: Magnetic Vector Potential - Question 9
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The current element of the magnetic vector potential for a surface current will be
Detailed Solution for Test: Magnetic Vector Potential - Question 9

Answer: c
Explanation: The magnetic vector potential for the surface integral is given by A = ∫ μKdS/4πR. It is clear that the current element is K dS.

Test: Magnetic Vector Potential - Question 10
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The relation between flux density and vector potential is 
Detailed Solution for Test: Magnetic Vector Potential - Question 10

Answer: a
Explanation: The magnetic flux density B can be expressed as the space derivative of the magnetic vector potential A. Thus B = Curl(A).

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