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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Magnetic Force & Lorentz Force - Electrical Engineering (EE) MCQ

Test: Magnetic Force & Lorentz Force - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Magnetic Force & Lorentz Force

Test: Magnetic Force & Lorentz Force for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Magnetic Force & Lorentz Force questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Magnetic Force & Lorentz Force MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Magnetic Force & Lorentz Force below.
Solutions of Test: Magnetic Force & Lorentz Force questions in English are available as part of our course for Electrical Engineering (EE) & Test: Magnetic Force & Lorentz Force solutions in Hindi for Electrical Engineering (EE) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Magnetic Force & Lorentz Force | 10 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Magnetic Force & Lorentz Force - Question 1
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Find the electric force when the charge of 2C is subjected to an electric field of 6 units.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 1

Answer: c
Explanation: The electric force is given by F = qE, where q = 2C and E = 6 units. Thus we get F = 2 x 6 = 12 units.

Test: Magnetic Force & Lorentz Force - Question 2
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Find the magnetic force when a charge 3.5C with flux density of 4 units is having a velocity of 2m/s.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 2

Answer: b
Explanation: The magnetic force is given by F = q(v x B), where q = 3.5C, v = 2m/s and B = 4 units. Thus we get F = 3.5(2 x 4) = 28 units.

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Test: Magnetic Force & Lorentz Force - Question 3
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Find the electric field when the velocity of the field is 12m/s and the flux density is 8.75 units.

Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 3

Answer: b
Explanation: The electric field intensity is the product of the velocity and the magnetic flux density ie, E = v x B = 12 x 8.75 = 105 units.

Test: Magnetic Force & Lorentz Force - Question 4
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Find the Lorentz force of a charge 2.5C having an electric field of 5 units and magnetic field of 7.25 units with a velocity 1.5m/s.
Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 4

Answer: a
Explanation: The Lorentz force is given by F = qE + q(v x B), it is the sum of electric and magnetic force. On substituting q = 2.5, E = 5, v = 1.5 and B = 7.25, F = 2.5(5) + 2.5(1.5 x 7.25) = 39.68 units.

Test: Magnetic Force & Lorentz Force - Question 5
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The force on a conductor of length 12cm having current 8A and flux density 3.75 units at an angle of 300 is
Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 5

Answer: d
Explanation: The force on a conductor is given by F = BIL sin θ, where B = 3.75, I = 8, L = 0.12 and θ = 300. We get F = 3.75 x 8 x 0.12 sin 30 = 1.8 units.

Test: Magnetic Force & Lorentz Force - Question 6
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The force per unit length of two conductors carrying equal currents of 5A separated by a distance of 20cm in air(in 10-6 order) 
Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 6

Answer: a
Explanation: The force per unit length of two conductors is given by
F = μ I1xI2/2πD, where I1 = I2 = 5 and D = 0.2. Thus F = 4π x 10-7 x 52/ 2π x 0.2 = 25 x 10-6 units.

Test: Magnetic Force & Lorentz Force - Question 7
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When currents are moving in the same direction in two conductors, then the force will be
Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 7

Answer: a
Explanation: When two conductors are having currents moving in the same direction then the forces of the two conductors will be moving towards each other or attractive.

Test: Magnetic Force & Lorentz Force - Question 8
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Find the flux density due to a conductor of length 6m and carrying a current of 3A(in 10-7order) 
Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 8

Answer: a
Explanation: The flux density is B = μH, where H = I/2πR. Put I = 3 and R = 6, we get B = 4π x 10-7 x 3/2π x 6 = 1 x 10-7 units.

Test: Magnetic Force & Lorentz Force - Question 9
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Find the maximum force of the conductor having length 60cm, current 2.75A and flux density of 9 units.
Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 9

Answer: a
Explanation: The force on a conductor is given by F = BIL sin θ, where B = 3.75, I = 8, L = 0.12 and θ = 90 for maximum force. We get F
= BIL= 9 x 2.75 x 0.6 sin 90 = 14.85 units.

Test: Magnetic Force & Lorentz Force - Question 10
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The magnetic force impacts the energy of the field. State True/false. 
Detailed Solution for Test: Magnetic Force & Lorentz Force - Question 10

Answer: a
Explanation: The magnetic force depends on the flux density of a material and the flux density is in turn dependent on the energy of the material. It can be shown that F = q(v x B) and E = 0.5 x B2/μ. It is clear that B and F are related.

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