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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Lossy & Lossless Dielectrics - Electrical Engineering (EE) MCQ

Test: Lossy & Lossless Dielectrics - Electrical Engineering (EE) MCQ


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12 Questions MCQ Test - Test: Lossy & Lossless Dielectrics

Test: Lossy & Lossless Dielectrics for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Lossy & Lossless Dielectrics questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Lossy & Lossless Dielectrics MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Lossy & Lossless Dielectrics below.
Solutions of Test: Lossy & Lossless Dielectrics questions in English are available as part of our course for Electrical Engineering (EE) & Test: Lossy & Lossless Dielectrics solutions in Hindi for Electrical Engineering (EE) course. Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free. Attempt Test: Lossy & Lossless Dielectrics | 12 questions in 10 minutes | Mock test for Electrical Engineering (EE) preparation | Free important questions MCQ to study for Electrical Engineering (EE) Exam | Download free PDF with solutions
Test: Lossy & Lossless Dielectrics - Question 1
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For a dielectric, the condition to be satisfied is

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 1

Answer: b
Explanation: In a dielectric, the conductivity will be very less. Thus the loss tangent will be less than unity. This implies σ/ωε < 1 is true.

Test: Lossy & Lossless Dielectrics - Question 2
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For a perfect dielectric, which parameter will be zero?

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 2

Answer: a
Explanation: The conductivity will be minimum for a dielectric. For a perfect dielectric, the conductivity will be zero.

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Test: Lossy & Lossless Dielectrics - Question 3
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Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×108 m/s(in 10-8 order)

Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 3

Answer: c
Explanation: The phase constant is given by β = ω√(με), where ω is the frequency in rad/s and 1/√(με) is the velocity of wave. On substituting √(με) = 3×108 and ω = 12, we get β = 12/(3×108) = 4 x 10-8m/s.

Test: Lossy & Lossless Dielectrics - Question 4
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Calculate the velocity of a wave with frequency 2 x109 rad/s and phase constant of 4 x 108units.
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 4

Answer: b
Explanation: The velocity of a wave is the ratio of the frequency to the phase constant. Thus V = ω/β. On substituting the given values, we get V = 2 x109/ 4 x 108 = 5 units.

Test: Lossy & Lossless Dielectrics - Question 5
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Which of the following is the correct relation between wavelength and the phase constant of a wave?
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 5

Answer: a
Explanation: The phase constant is the ratio of 2π to the wavelength λ. Thus β = 2π/λ is the correct relation

Test: Lossy & Lossless Dielectrics - Question 6
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In lossy dielectric, the phase difference between the electric field E and the magnetic field H is
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 6

Answer: d
Explanation: In a lossy dielectric, the E and H component will be in phase. This implies that the phase difference between E and H will be 0.

Test: Lossy & Lossless Dielectrics - Question 7
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The intrinsic impedance is the ratio of square root of
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 7

Answer: b
Explanation: The intrinsic impedance is the impedance of a particular material. It is the ratio of square root of the permeability to permittivity. For air, the intrinsic impedance is 377 ohm or 120π.

Test: Lossy & Lossless Dielectrics - Question 8
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Calculate the skin depth of a material with attenuation constant of 2 units.
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 8

Answer: c
Explanation: The skin depth of a material is the reciprocal of the attenuation constant. Thus δ = 1/α. On substituting for α = 2, we get δ = ½ = 0.5 units.

Test: Lossy & Lossless Dielectrics - Question 9
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Calculate the phase constant of a wave with skin depth of 2.5 units.
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 9

Answer: d
Explanation: The skin depth is the reciprocal of the phase constant and the attenuation constant too. Thus δ = 1/β. On substituting for δ = 2.5, we get β = 1/δ = 1/2.5 = 2/5 units.

Test: Lossy & Lossless Dielectrics - Question 10
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An example for lossless propagation is
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 10

Answer: d
Explanation: There are many techniques employed to achieve zero attenuation or maximum propagation. But it is not achievable practically. Thus lossless propagation is not possible practically

Test: Lossy & Lossless Dielectrics - Question 11
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Skin depth phenomenon is found in which materials?
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 11

Answer: c
Explanation: Skin depth is found in pure conductors. It the property of the conductor to allow a small amount of electromagnetic energy into its skin, but not completely. This is the reason why EM waves cannot travel inside a good conductor.

Test: Lossy & Lossless Dielectrics - Question 12
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An example for lossless propagation is
Detailed Solution for Test: Lossy & Lossless Dielectrics - Question 12

There are many techniques employed to achieve zero attenuation or maximum propagation. But it is not achievable practically. Thus lossless propagation is not possible practically.

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