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Electronics and Communication Engineering (ECE) Exam  >  Electronics and Communication Engineering (ECE) Tests  >  Test: S & P Polarised Waves - Electronics and Communication Engineering (ECE) MCQ

Test: S & P Polarised Waves - Electronics and Communication Engineering (ECE) MCQ


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10 Questions MCQ Test - Test: S & P Polarised Waves

Test: S & P Polarised Waves for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Test: S & P Polarised Waves questions and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus.The Test: S & P Polarised Waves MCQs are made for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: S & P Polarised Waves below.
Solutions of Test: S & P Polarised Waves questions in English are available as part of our course for Electronics and Communication Engineering (ECE) & Test: S & P Polarised Waves solutions in Hindi for Electronics and Communication Engineering (ECE) course. Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free. Attempt Test: S & P Polarised Waves | 10 questions in 10 minutes | Mock test for Electronics and Communication Engineering (ECE) preparation | Free important questions MCQ to study for Electronics and Communication Engineering (ECE) Exam | Download free PDF with solutions
Test: S & P Polarised Waves - Question 1
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The resultant electric field of a wave with Ex = 3 and Ey = 4 will be

Detailed Solution for Test: S & P Polarised Waves - Question 1

Answer: d
Explanation: The resultant electric field of two electric components Ex and Ey is E = √(Ex2 + Ey2). On substituting for Ex = 3 and Ey = 4, we get E = 5 units.

Test: S & P Polarised Waves - Question 2
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In S polarisation, the electric field lies in the plane perpendicular to that of the interface. State True/False

Detailed Solution for Test: S & P Polarised Waves - Question 2

Answer: a
Explanation: In the EM wave propagation, the electric and magnetic fields are perpendicular to each other. The S polarised wave is similar to the transverse magnetic (TM) wave, the electric field lies in the plane perpendicular to that of the interface.

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Test: S & P Polarised Waves - Question 3
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In P polarisation, the electric field lies in the same plane as the interface. State True/False.

Detailed Solution for Test: S & P Polarised Waves - Question 3

Answer: a
Explanation: In the EM wave propagation, the electric and magnetic fields are perpendicular to each other. The P polarised wave is similar to the transverse electric (TE) wave, the magnetic field lies in the plane perpendicular to that of the interface or the electric field lies in the same plane as the interface.

Test: S & P Polarised Waves - Question 4
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The group delay of a wave with phase constant 2.5 units and frequency of 1.2 radian/sec is
Detailed Solution for Test: S & P Polarised Waves - Question 4

Answer: d
Explanation: The group delay is given by td = β/ω. On substituting for β = 2.5 and ω = 1.2, we get the group delay as td = 2.5/1.2 = 2.08 units.

Test: S & P Polarised Waves - Question 5
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The Brewster angle is valid for which type of polarisation?
Detailed Solution for Test: S & P Polarised Waves - Question 5

Answer: b
Explanation: The Brewster angle is valid for perpendicular polarisation. The P polarised wave is also a type of perpendicular polarisation. In P polarisation, the electric field lies in the plane of the interface.

Test: S & P Polarised Waves - Question 6
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Find the reflection coefficient of a wave with an incident electric field of 5 units and reflected electric field of 2 units.
Detailed Solution for Test: S & P Polarised Waves - Question 6

Answer: b
Explanation: The reflection coefficient is the ratio of the reflected electric field to the incident electric field. Thus τ = Er/Ei. On substituting for Ei = 5 and Er = 2, we get τ = 2/5 = 0.4(no unit).

Test: S & P Polarised Waves - Question 7
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The transmission coefficient of a wave with incident and transmitted electric field of 5 and 5 respectively is
Detailed Solution for Test: S & P Polarised Waves - Question 7

Answer: b
Explanation: The transmission coefficient is the ratio of the transmitted electric field to the incident electric field. Thus T = Et/Ei. On substituting for Et = 5 and Ei = 5, we get T = 5/5 = 1(no unit). Simply, when the incident and transmitted field are same, no reflection occurs and the transmission is unity.

Test: S & P Polarised Waves - Question 8
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Find the relative permittivity of the medium having a refractive index of 1.6
Detailed Solution for Test: S & P Polarised Waves - Question 8

Answer: b
Explanation: The refractive index is the square root of the relative permittivity. It is given by n = √εr. To get εr, put n = 1.6. We get εr = n2 = 1.62 = 2.56(no unit).

Test: S & P Polarised Waves - Question 9
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Calculate the transmission coefficient of a wave with a reflection coefficient of 0.6
Detailed Solution for Test: S & P Polarised Waves - Question 9

Answer: d
Explanation: The transmission coefficient is the reverse of the reflection coefficient. Thus T + τ = 1. On substituting for τ = 0.6, we get T = 0.4. It has no unit.

Test: S & P Polarised Waves - Question 10
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The phase constant of a wave propagation with frequency of 35 radian/sec and time delay of 7.5 sec is
Detailed Solution for Test: S & P Polarised Waves - Question 10

Answer: b
Explanation: The group delay expression is td = β/ω. To get β, put ω = 35 and td = 7.5. Thus we get β = td x ω = 7.5 x 35 = 262.5 units.

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