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BITSAT Maths Test - 5 - JEE MCQ


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30 Questions MCQ Test - BITSAT Maths Test - 5

BITSAT Maths Test - 5 for JEE 2024 is part of JEE preparation. The BITSAT Maths Test - 5 questions and answers have been prepared according to the JEE exam syllabus.The BITSAT Maths Test - 5 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for BITSAT Maths Test - 5 below.
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BITSAT Maths Test - 5 - Question 1

The area bounded by the curve y = x3, the x-axis and the ordiantes at x = -2 and x = 1 is

BITSAT Maths Test - 5 - Question 2

If the sum of the coefficients in the expansion of (α2x2 - 2αx + 1)51 vanishes, then α is equal to

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BITSAT Maths Test - 5 - Question 3

The angle between the tangents from the origin to the circle (x-7)2 + (y+1)2 = 25 is

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BITSAT Maths Test - 5 - Question 4

The limiting point of the system of co-axial circles x2+y2-6x-6y+4=0, x2+y2-2x-4y+3=0 is

BITSAT Maths Test - 5 - Question 5

The differential equation for the family of curves x2 + y2 - 2ay = 0, where a is an arbitrary constant is

BITSAT Maths Test - 5 - Question 6

If [(1 + i√3)/(1 + i√3)]n is an integer ,then n is equal to

Detailed Solution for BITSAT Maths Test - 5 - Question 6

Presuming the question actually means

[ ( 1 + √3i ) / ( 1 - √3i ) ]ⁿ

i.e. the whole thing raised to the power of n, not just the denominator.

Let w = ( 1 + √3i ) / ( 1 - √3i )

Multiplying numerator and denominator by ( 1 + √3i ) gives

w = ( 1 + √3i )² / [ ( 1 - √3i ) ( 1 + √3i ) ]

  = ( 1 - 3 + 2√3i ) / ( 1 + 3 )

  = ( -2 + 2√3i ) / 4

  = ( -1 + √3i) / 2.

So w is a primitive cubed root of unity.     (*) ... see note below

So wⁿ is an integer

<=> wⁿ = 1

<=> n is a multiple of 3.

BITSAT Maths Test - 5 - Question 7

The general solution of the equation x2(dy/dx)=2 is

BITSAT Maths Test - 5 - Question 8

The solution of y'- y = 1, y(0) = 1 is given by y (x)

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BITSAT Maths Test - 5 - Question 9

The number of points at which the function f(x)=|x-0.5|+|x-1|+tanx is not differentiable in (0,2) is

BITSAT Maths Test - 5 - Question 10

Sum of the infinite series 1 + 3/2! + 6/3! + 10/4! + ...... is

BITSAT Maths Test - 5 - Question 11

If y = sec tan⁻1 x, then (dy/dx) =

Detailed Solution for BITSAT Maths Test - 5 - Question 11

Solution:

- Given: y = sec(tan⁻1 x)
- Let's first simplify sec(tan⁻1 x):
- tan(tan⁻1 x) = x
- Let θ = tan⁻1 x, then tanθ = x
- secθ = 1/cosθ
- We know that cosθ = 1/√(1 + tan²θ)
- Substituting the value of tanθ = x, we get cosθ = 1/√(1 + x²)
- Therefore, sec(tan⁻1 x) = 1/(1/√(1 + x²)) = √(1 + x²)
- So, y = √(1 + x²)

- Now, let's find dy/dx using the chain rule:
- y = √(1 + x²)
- dy/dx = d/dx(√(1 + x²))
- dy/dx = (1/2)(1 + x²)^(-1/2) * 2x
- dy/dx = x/(1 + x²)^(3/2)

Therefore, the correct answer is A: x/(1 + x²).

BITSAT Maths Test - 5 - Question 12

If a flag staff of 6 mt high placed on the top of a tower throws a shadow of 2 √3 mt along the ground then the angle that the sun makes with the ground is

BITSAT Maths Test - 5 - Question 13

A variable straight line of slope 4 intersects the hyperbola xy = 1 at two points. The locus of the point which divides the line segment between these two points in the ratio 1:2 is

BITSAT Maths Test - 5 - Question 14

The general solution of the differential equation (dy/dx) = (x2/y2) is

BITSAT Maths Test - 5 - Question 15

The area bounded by the curve y2 = 9x and the lines x = 1, x = 4 and y = 0 in the first quadrant is

BITSAT Maths Test - 5 - Question 16

BITSAT Maths Test - 5 - Question 17

BITSAT Maths Test - 5 - Question 18

Let f(x + y) = f(x)f(y) for all x and y. Suppose that f(3) = 3 and f′(0) = 11 then f′(3) is given by

BITSAT Maths Test - 5 - Question 19

A square matrix can always be expressed as a

BITSAT Maths Test - 5 - Question 20

If A and B are square matrices and A⁻1 and B⁻1 of same order exists, then (AB)⁻1 is equal to

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BITSAT Maths Test - 5 - Question 21

The curved surface of the cone inscribed in a given sphere is maximum if h=

BITSAT Maths Test - 5 - Question 22

If z is a complex number, then | 3z − 1 | = 3 | z − 2 | represents

BITSAT Maths Test - 5 - Question 23

The angle between lines given by x2+4y2-7xy=0 is

BITSAT Maths Test - 5 - Question 24

If x+y+1=0 tocuhes the parabola y2=λx,then λ is equal to

BITSAT Maths Test - 5 - Question 25

The line y=mx+c touches the parabola x2=4ay if

BITSAT Maths Test - 5 - Question 26

How many words are formed from the letters of the word EAMCET so that two vowels are never together?

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BITSAT Maths Test - 5 - Question 27

Number of triangles formed by joining 12 points, no three of which are in the same straight line except 7 of them which are in a straight line, is

BITSAT Maths Test - 5 - Question 28

The mean and variance of a Binomial distribution are 6 and 4. The parameter n is

BITSAT Maths Test - 5 - Question 29

Five horses are in a race. Mr. A selects two of the horses at random and bets on them. The probability that Mr. A selected the winning horse is

Detailed Solution for BITSAT Maths Test - 5 - Question 29

Out of 5 horses only 1 is the winning horse
The probability that Mr A selected the losing horse = 4/5 x 3/4
∴ The probability that Mr A selected the winning horse = 1 - 4/5 x 3/4 = 2/5

BITSAT Maths Test - 5 - Question 30

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