Amazon Aptitude Paper 1 - Quant MCQ

Do not confuse it with Tuesday.the correct answer is Monday

Assume there are x participants in the race. In a round race, number of participants in front of a person wil be x-1 and that behind him wil be x-1. i.e, 1/3(x-1) + 3/4(x-1) = x solving x = 13

Required number = (L.C.M. of 12,16, 18, 21, 28) + 7 = 1008 + 7 = 1015

Given:

• The ratio of two numbers is 3:4
• The H.C.F. (Highest Common Factor) of the two numbers is 4.

Let's denote the two numbers as 3x and 4x, where x is a common multiplier.

Since the H.C.F. of the two numbers is given as 4, x must be 4 (because H.C.F. is the highest common factor, and 4 is the common factor here).

So, the two numbers are:

• First number = 3×4=12
• Second number = 4×4=16

Now, let's calculate the L.C.M. (Least Common Multiple) of 12 and 16.

Method:

The L.C.M. of two numbers can be calculated using the formula:

LCM×HCF=Product of the numbers

So,

Clearly, 252 = 2 x 2 x 3 x 3 x 7.

In this alternating repetition series, the random number 21 is interpolated every other number into an otherwise simple addition series that increases by 2, beginning with the number 9.

Given data:

Train from Howrah to Patna reaches its destination after they meet in 9 hours.

Train from Patna to Howrah reaches its destination after they meet in 16 hours.

Solution:

Let the speed of the train from Howrah to Patna be S1 and the one from Patna to Howrah be S2.

We know that the speeds are in the ratio of the square roots of the times taken to reach their destinations after they meet.

⇒ S1/S2 = √time taken by Train 2 / √time taken by Train 1

⇒ S1/S2 = √16 / √9

⇒ S1/S2 = 4 / 3

Therefore: The ratio of their speeds is 4 : 3.

Thus, option (2) is the correct answer.

To solve this problem, we can use the concept of work done, which is calculated using the formula:

Work = Number of Men X Number of Hours per Day X Number of Days

• 9 men working 6 hours a day can complete the work in 88 days.

So, the total amount of work is:

Total Work = 9 x 6 x 88 = 4752 man-hours

Now, let's calculate the number of days (D) it will take for 6 men working 8 hours a day to complete the same amount of work.

Total Work = 6 x 8 x D

Set this equal to the total work we calculated:

6 x 8 x D = 4752

Solve for D:

48D = 4752

Weight increased per person is 1 kg. Total increase in weight = 25 kgs Weight of new man is 70 kgs, (Which means his weight is 25 kgs heavier) The weight of the old man was 70 - 25 = 45 kgs

Speed of boat in still water (b) = 4.5 km/hr. Speed of boat with stream (Down Stream), D = b + u Speed of boat against stream (Up stream), U = b – u It is given upstream time is twice to that of down stream. ⇒ Downstream speed is twice   to that of upstream. So b + u = 2(b – u) ⇒ u =b/3 = 1.5 km/hr.

SI for 3 years = 12005 - 9800 = Rs. 2205

⇒ SI for 1 years = 2205/3 = Rs. 735

SI for 5 years = 5 × 735 = Rs. 3675

⇒ Principal = 9800 - 3675 = Rs. 6125

As we know,

SI = Prt/100

⇒ 3675 = (6125 × r × 5)/100

⇒ r = (3675 × 100) / (5 × 6125)

∴ r = 12%

lets us consider t1 = time taken on level road. t2 = uphill. t3 = down hill; the distance traveled uphill and down hill same so t2*3 = 6*t3; => t2 = 2t3;---> (1) total time = 2*t1 + t2 + t3 = 6 hours ---> (2) 2t1+3t3 = 6 -->(3) total distance   = 2*(4t1) + 3*t2+ 6*t3 ---> (4) substitute (1) in (4) 8t1 + 12t3 => 4(2t1+3t3) then from (3) the total distance will become 4*6= 24 => one way distance = 12km

Let the number of cows be x and the number of hens be y. Then, 4x + 2y = 2 (x + y) + 14 4x + 2y = 2x + 2y + 14 2x = 14 x = 7.

Clearly, the required number would be such that it leaves a remainder of 1 when divided by 2, 3 or 4 and no remainder when divided by 5.

In same time ,they cover 110 km & 90 km respectively so ratio of their speed =110:90 = 11:9

Consider 9x - 3y = 12.........divide both sides by 3: 3x - y = 4............now multiply both sides by 2: 6x - 2y = 8 So, it`s (d)

Required sum = (80 - 3 x 3) years = (80 - 9) years = 71 years.

Principal = Rs. (100 x 5400)/(12*3) = Rs. 15000.

Let the ages of A, B, and C be represented by A, B, and C respectively.

From the given information:

1. The total age of A and B is 12 years more than the total age of B and C.

This can be written as an equation: A+B=(B+C)+12

Simplifying: A+B=B+C+12 Canceling out B from both sides: A=C+12

Thus, C is 12 years younger than A.

So, the correct answer is:

Option 1: C is 12 years younger than A.

Speed in still water A = ½ ( 11+5) km/hr A= 8 kmph

Let the age of three persons be x, 3x and 5x => 9x/3 = 27 = > x = 9

Greatest number of 4-digits is 9999. L.C.M. of 15, 25, 40 and 75 is 600. On dividing 9999 by 600, the remainder is 399. Required number (9999 - 399) = 9600.