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JEE Main Chemistry Mock Test- 2 - JEE MCQ


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25 Questions MCQ Test - JEE Main Chemistry Mock Test- 2

JEE Main Chemistry Mock Test- 2 for JEE 2024 is part of JEE preparation. The JEE Main Chemistry Mock Test- 2 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Chemistry Mock Test- 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Chemistry Mock Test- 2 below.
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JEE Main Chemistry Mock Test- 2 - Question 1

The compound 'A' when treated with methyl alcohol and few drops of H₂SO₄ give wintergreen smell. The compound 'A' is

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 1

Salicylic acid gives wintergreen smell with methyl alcohol and H2SOto form Methyl salicylate.

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JEE Main Chemistry Mock Test- 2 - Question 2

Which of the following will not give iodoform test?

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 2

Benzyl alcohol does not have the CH3CO- group or CH3CH2Oso it will not give the positive iodoform test.

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JEE Main Chemistry Mock Test- 2 - Question 3

Phospholipids are esters of glycerol with

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 3

Phospholipids are esters of glycerol with two carboxylic acid residue and one phosphate group. Hence, phospholipids may be regarded as derivative of glycerol in which two hydroxyl group are esterified with a fatty acid, while third is esterified with phosphoric acid.Phospholipids are formed by the esterification of.

JEE Main Chemistry Mock Test- 2 - Question 4

Splitting of spectral lines under the influence of magnetic field is called

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 4
  • Splitting of spectral lines under the influence of magnetic field is called Zeeman effect.
  • In stark effect spectral lines split due to electricity.
  • In photoelectric effect the splitting of spectral line takes place as the light falls on the metal.
JEE Main Chemistry Mock Test- 2 - Question 5

The maximum number of unpaired d-electrons are in

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 5

Fe+3 has 5 unpaired electrons, more than other ones.

JEE Main Chemistry Mock Test- 2 - Question 6

Alkyl groups are o- and p-directing because of

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 6

Hyperconjugation effect in Alkyl group:

JEE Main Chemistry Mock Test- 2 - Question 7

In graphite, the electrons are

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 7

In graphite, each carbon atom uses only 3 of its 4 outer energy level electron in covalently bonding to there other carbon atoms in a place. In graphite, electrons are spread out between the structure.

JEE Main Chemistry Mock Test- 2 - Question 8

In which of the following molecule, all the atoms lie in one plane?

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 8

It has got sp2 hybridization, giving it a planar structure.Further backbonding from flouine makes the B-F bonds stronger than normal single bonds.

JEE Main Chemistry Mock Test- 2 - Question 9

Pairs of species having identical shapes for molecules is

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 9
  • XeF2 contains sp3d hybridized Xe atom with three lone pairs of electrons.
  • Fluorine atoms occupy axial positions while three lone pairs of electrons occupy equatorial positions in trigonal bipyramid.
  • Since the lone pair of electrons does not consider for the shape of the molecule, thus, the shape of XeF2 comes out to be linear.
  • While C -atom of CO2 is sp hybridised and thus, possesses a linear shape.

JEE Main Chemistry Mock Test- 2 - Question 10

Which one of the following is expected to exhibit optical isomerism

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 10

Optical isomers of cis-[Co(en)₂Cl₂] :
Why does dichloridobisethylenediaminecobalt(III) have only three optical  isomers? - Chemistry Stack Exchange

JEE Main Chemistry Mock Test- 2 - Question 11

The oxidation state of Cr in [Cr(NH₃)₄Cl₂]⁺ is

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 11

Applying sum of individual charge = charge on molecule
x+(0)×4 + (-1)×2 = +1
x=3

JEE Main Chemistry Mock Test- 2 - Question 12

Nickel is purified by

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 12

The Mond process, sometimes known as the carbonyl process, is a technique created by Ludwig Mond in 1890, to extract and purify nickel. The process was used commercially before the end of the 19th century. This process converts nickel oxides into pure nickel.

JEE Main Chemistry Mock Test- 2 - Question 13

Which of the following noble gas is least polarisable?

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 13

Helium is the least polarizable noble gas due to presence of weakest Van der Waal's forces.

JEE Main Chemistry Mock Test- 2 - Question 14

The IUPAC name of

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 14

The longest chain has 7 carbons, making it a hept- root.

The chain contains a double bond (ene) and a triple bond (yne).

Number the chain to give the double and triple bonds the lowest possible locants. In this case, numbering from the left gives the double bond at carbon 5 and the triple bond at carbon 1.

So, we have a hept-5-en-1-yne backbone.

Chloro group at carbon 6.

Ethyl group at carbon 4.

Methyl group at carbon 5.

Assemble the name with the substituents in alphabetical order, followed by the main chain name

6-Chloro-4-ethyl-5-methyl hept-1-yn-5-ene

JEE Main Chemistry Mock Test- 2 - Question 15

When HCl gas is passed through a saturated solution of common salt, pure NaCl is precipitated because

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 15

When hydrogen chloride gas (HCl) is circulated through the saturated solution.
HCl and NaCl dissociate into their respective ions as:

NaCl → Na+ Cl-

HCl → H+ + Cl-

The concentration of Cl− ions increases considerably in solution due to ionization HCl. 

Hence, the ionic product [Na+][Cl−] exceeds the solubility product of sodium chloride and, therefore, pure sodium chloride precipitates out from the solution.

JEE Main Chemistry Mock Test- 2 - Question 16

Which of the following pair represents stereoisomerism?

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 16
  • Optical isomerism (such as enantiomers and diastereoisomers) and geometric isomerism (cis trans isomerism) represents stereoisomerism.
  • Stereoisomers have the same molecular formula and same connectivity of atoms, but differ in the orientations of atoms.
  • Chain isomerism, position isomerism and functional group isomerism represents structural isomerism. 
JEE Main Chemistry Mock Test- 2 - Question 17

Which of the following pair of elements belongs to same period of the periodic table?

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 17

Calcium and zinc both belong to the same period, i.e Period 4

JEE Main Chemistry Mock Test- 2 - Question 18

Natural rubber is a polymer of

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 18

Natural rubber is from the monomer cis-isoprene (2-methyl-1,3-butadiene).
It is an addition polymer that is obtained as a milky white fluid known as latex from a tropical rubber tree. 

JEE Main Chemistry Mock Test- 2 - Question 19

In view of their low ionization energies, the alkali metals are

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 19

Alkali metals can readily lose their lone electron to form +1 oxidation state and can easily ionize this electron and this ns1 configuration results in alkali metals to have large ionic and atomic radii and they have high second ionization energy. This ionization energy decreases down the group and act as strong reducing agent.

JEE Main Chemistry Mock Test- 2 - Question 20

100 ml of a liquid A was mixed with 25 ml of a liquid B to give B to give a non-ideal solution of A-B mixture. The volume of this mixture would be

Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 20

For non-ideal solution, ΔVmix ​< 0.

Final volume decreases due to negative deviation from original volume 125 ml.
Hence, total volume will be little less than (100 + 25 = 125 mL).

*Answer can only contain numeric values
JEE Main Chemistry Mock Test- 2 - Question 21

Total number of species in which atleast one atom have same hybridization as in central atom of azide ion.
N2O, C2H2, CO2, C3O2, BeF2, NO2, PF3


Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 21

N2O, C2H2, CO2, C3O2, BeF2

*Answer can only contain numeric values
JEE Main Chemistry Mock Test- 2 - Question 22

How many chiral centers are in the following compound?


Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 22

*Answer can only contain numeric values
JEE Main Chemistry Mock Test- 2 - Question 23

An ideal solution was found to have a vapour pressure of 80 torr when the mole fraction of a non-volatile solute was 0.2. What would be the vapour pressure of the pure solvent at the same temperature?


Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 23

*Answer can only contain numeric values
JEE Main Chemistry Mock Test- 2 - Question 24

What is the final temperature (in kelvin) of 0.10 mole monoatomic ideal gas that performs 75 cal of work adiabatically if the initial temperature is 227°C ? (use R = 2 cal/K-mol)


Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 24

*Answer can only contain numeric values
JEE Main Chemistry Mock Test- 2 - Question 25

log p v/s log RT curve plotted for 1 mole ideal gas. Calculate molar volume occupied by gas? (in liter)


Detailed Solution for JEE Main Chemistry Mock Test- 2 - Question 25

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