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JEE Exam  >  JEE Test  >   Main & Advanced Mock Test Series 2026  >  JEE Main Maths Mock Test- 9 - JEE MCQ

JEE Main & Advanced Maths Mock Test- 9 Free Online Test 2026


Full Mock Test & Solutions: JEE Main Maths Mock Test- 9 (25 Questions)

You can boost your JEE 2026 exam preparation with this JEE Main Maths Mock Test- 9 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of JEE 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 60 minutes
  • - Total Questions: 25
  • - Analysis: Detailed Solutions & Performance Insights
  • - Sections covered: SECTION I, SECTION II

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JEE Main Maths Mock Test- 9 - Question 1
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In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-

JEE Main Maths Mock Test- 9 - Question 2
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In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A) :A relation R on the set of complex number defined by Z1 RZ2 ⇔ Z1 − Z2 is real, is an equivalence relation.
Reason(R) :Reflexive and symmetric properties may not imply transitivity.

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JEE Main Maths Mock Test- 9 - Question 3
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The are (in square units) of the region bounded by x2 = 8 y , x = 4 and x-axis is

JEE Main Maths Mock Test- 9 - Question 4
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The limiting point of the system of co-axial circles x2+y2-6x-6y+4=0, x2+y2-2x-4y+3=0 is

JEE Main Maths Mock Test- 9 - Question 5
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[(1-i)/(1+i)] =

JEE Main Maths Mock Test- 9 - Question 6
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The number of tangents drawn from the point (-1,2) to x2+y2+2x-4y+4=0 is

Detailed Solution: Question 6

JEE Main Maths Mock Test- 9 - Question 7
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The conjugate of complex number [(2+5i)/(4-3i)] is

Detailed Solution: Question 7

Step 1: Multiply by the conjugate of the denominator

To simplify the complex number and find its conjugate, multiply both the numerator and denominator by the conjugate of the denominator, (4 + 3i):

(2 + 5i) / (4 - 3i) × (4 + 3i) / (4 + 3i)

Step 2: Simplify the denominator

The denominator becomes:

(4 - 3i)(4 + 3i) = 4² - (3i)² = 16 - (-9) = 16 + 9 = 25

Step 3: Simplify the numerator

Now, simplify the numerator:

(2 + 5i)(4 + 3i) = 2(4 + 3i) + 5i(4 + 3i) = 8 + 6i + 20i + 15i² Since i² = -1, we get: = 8 + 6i + 20i - 15 = -7 + 26i

Step 4: Combine the results

Now, the complex number is:

(-7 + 26i) / 25

Step 5: Conjugate of the complex number

The conjugate of a complex number a + bi is a - bi. Therefore, the conjugate of (-7 + 26i) / 25 is:

(-7 - 26i) / 25

Thus, the correct answer is:

b) (-7 - 26i) / 25.

JEE Main Maths Mock Test- 9 - Question 8
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The solution of differential equation

JEE Main Maths Mock Test- 9 - Question 9
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The maximum value of the function f(x)=[(x)/(4+x+x2)] at the interval [-1,1] will be

Detailed Solution: Question 9

JEE Main Maths Mock Test- 9 - Question 10
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sin⁻1 (cos(sin⁻1 x) + cos⁻1 (sin(cos⁻1 x) is equal to

JEE Main Maths Mock Test- 9 - Question 11
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In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A): y = sin (ax + b) is a general solution of y" + a^2y = 0 .
Reason(R) : y = sin (ax + b)  is a trigonometric function.

JEE Main Maths Mock Test- 9 - Question 12
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The inverse of the converse of a conditional statement is the _______________.

Detailed Solution: Question 12

The inverse will insert NOT into the statement.
The converse will switch the IF and THEN.
The contrapositive does both.
The contrapositive is the inverse of the converse of the conditional statement.

JEE Main Maths Mock Test- 9 - Question 13
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In the following question, a Statement of Assertion (A) is given followed by a corresponding Reason (R) just below it. Read the Statements carefully and mark the correct answer-
Assertion(A): The domain of the function
Reason (R): The domain of the function

JEE Main Maths Mock Test- 9 - Question 14
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If A is a square matrix such that A2 = I, then A⁻1 is equal to

JEE Main Maths Mock Test- 9 - Question 15
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The equation of the directrix to the parabola y2 − 2x − 6y − 5 = 0 is

JEE Main Maths Mock Test- 9 - Question 16
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Two finite sets have m and n elements, the total number of subsets of the first set is 56 more than the total number of subsets of the second. The value of m and n are respectively

Detailed Solution: Question 16

Let A denote the first set and B denote the second set
We have, n(A) = 2m and n(B) = 2n
As per the question, we have
n(A) = 56 + n(B)
⇒ n(A) - n(B) = 56
⇒ 2m - 2n = 56
⇒ 2n (2m - n - 1)
⇒ 2n (2m - n - 1) = 8 x 7
⇒ 2n = 8 = 23 or (2m - n - 1) = 7
⇒ n = 3 or 2m - n = 8 = 23 = 26 - 3
⇒ n = 3 or m - n = 3
⇒ n = 3 or m = 6
Hence, the required values of m and n are 6 and 3 respectively

JEE Main Maths Mock Test- 9 - Question 17
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A die is thrown 100 times. If getting an odd number is considered a success, the variance of the number of successes is

JEE Main Maths Mock Test- 9 - Question 18
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If in a moderately asymmetrical distribution mode and mean of the data are 6λ and 9λ respectively, then median is

JEE Main Maths Mock Test- 9 - Question 19
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The sides of a parallelogram are lx + ny + n = 0, lx + my + n' = 0, mx + ly + n = 0, mx + ly + n' = 0, the angle between its diagonals is

JEE Main Maths Mock Test- 9 - Question 20
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Equation of normal to the curve y = x(2 - x) at the point (2, 0) is

*Answer can only contain numeric values
JEE Main Maths Mock Test- 9 - Question 21
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Let f : (–3, 3) → R be a differentiable function with f(0) = – 2 and f'(0) = – 1 and g(x) = (f(3f(x) + 6))3 then g'(0) is equal to.


*Answer can only contain numeric values
JEE Main Maths Mock Test- 9 - Question 22
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At present a firm is manufacturing 2000 items. It is estimated that the rate of change of production P w.r.t. additional number of workers x is given by dP/dx = 100 - 12√x. If the firm employs 25 more workers, then the new level of production of items is:


*Answer can only contain numeric values
JEE Main Maths Mock Test- 9 - Question 23
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It is given that events A and B of an experiment are such that P(A / B) = 1 / 4 and P (B / A) = 1/12 and chance of occurence of an event "only A" is 1/12  (where P(x) denote the probability of occurence of event 'x'). Value of 22P(B) equals


Detailed Solution: Question 23

*Answer can only contain numeric values
JEE Main Maths Mock Test- 9 - Question 24
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If the function ƒ(x) = 2 + x2 – e–x and g(x) = ƒ–1(x), then the value of  equals 


Detailed Solution: Question 24

g(ƒ(x)) = x ⇒ g'(ƒ(x)). ƒ'(x) = 1
ƒ(x) = 1 ⇒ x = 0
g'(1). ƒ'(0) = 1
ƒ'(x) = 2x + e–x
ƒ'(0) = 1
g'(1) = 1

*Answer can only contain numeric values
JEE Main Maths Mock Test- 9 - Question 25
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Detailed Solution: Question 25

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About this JEE Mock Test

This mock test contains 25 questions designed to replicate the pattern, difficulty level and time pressure of the actual JEE exam. It is part of JEE Main & Advanced Mock Test Series 2026 on EduRev, covering all the topics that are being asked as per the current JEE syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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If you found this JEE Main Maths Mock Test- 9 helpful, you can further enhance your JEE preparation with complete mock tests, previous year questions & practice tests available in JEE Main & Advanced Mock Test Series 2026 course on EduRev. The course offers:
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