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JEE Exam  >  JEE Test  >  SRME Subject Wise & Full Length Mock Tests 2026  >  SRMJEEE Maths Mock Test - 2 - JEE MCQ

SRMJEEE Subject Wise & Full Length Maths Mock Test - 2 Free Online Test


Full Mock Test & Solutions: SRMJEEE Maths Mock Test - 2 (40 Questions)

You can boost your JEE 2026 exam preparation with this SRMJEEE Maths Mock Test - 2 (available with detailed solutions).. This mock test has been designed with the analysis of important topics, recent trends of the exam, and previous year questions of the last 3-years. All the questions have been designed to mirror the official pattern of JEE 2026 exam, helping you build speed, accuracy as per the actual exam.

Mock Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 40 minutes
  • - Total Questions: 40
  • - Analysis: Detailed Solutions & Performance Insights

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SRMJEEE Maths Mock Test - 2 - Question 1
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If the area of a Δ A B C be λ then a2 sin 2B + b2 sin 2A is equal to

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SRMJEEE Maths Mock Test - 2 - Question 2
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The radius of the circle in which the sphere x2 + y2 + z2 + 2x - 2y - 4z - 19 = 0 is cut by the plane x + 2y + 2z + 7 = 0, is

Detailed Solution: Question 2

Radius of sphere is=5 then perpen dicular dice Frome plane=4 now radius of circle r,sqr=25_16=9so r=3

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SRMJEEE Maths Mock Test - 2 - Question 3
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The pole of the line lx+my+n=0 w.r.t. the parabloa y2 =4ax

Detailed Solution: Question 3

SRMJEEE Maths Mock Test - 2 - Question 4
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The difference of an integer and its cube is divisible by

Detailed Solution: Question 4

Solution:


  • Let the integer be x.

  • The difference of the integer and its cube is x - x^3.

  • For this difference to be divisible by a number, the number should divide the difference without leaving a remainder.

  • We need to find a number which divides x - x^3 without leaving a remainder.

  • Factoring out x from x - x^3 gives x(1 - x^2).

  • Further factoring 1 - x^2 gives (1 - x)(1 + x).

  • Therefore, the difference x - x^3 = x(1 - x)(1 + x).

  • The number that divides x - x^3 without leaving a remainder is the common factor of x, 1 - x, and 1 + x.

  • The common factor of x, 1 - x, and 1 + x is 1.

  • Therefore, the difference of an integer and its cube is divisible by 1, which means it is divisible by any integer including 4, 6, 10, and 9.

  • However, the smallest number among the given options that divides x - x^3 without leaving a remainder is 6.

  • Hence, the correct answer is B: 6.


    •  

SRMJEEE Maths Mock Test - 2 - Question 5
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If A+B+C=180o, then [(tanA+tanB+tanC)/(tanA tanB tanC)]=

Detailed Solution: Question 5

Given, A + B + C = 180
So, A + B = 180 - C
Taking tan on both sides we get,
⇒ tan(A+B) = tan(180-C)
⇒ 
⇒ tanA + tanB = -tanC(1 - tanA tanB)
⇒ tanA + tanB = - tanC + tanA tanB tanC
⇒ tanA + tanB + tanC = tanA tanB tanC

SRMJEEE Maths Mock Test - 2 - Question 6
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The area (in square units) of the region enclosed by the curves y = x2 and y = x3 is

Detailed Solution: Question 6

By solving equations 1and 2 we can get 0,1as values for x which can be the limits and by subtracting y=x^2 from x^3 and integrating the result within the limits 0 to 1 we can get area = 1\12

SRMJEEE Maths Mock Test - 2 - Question 7
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In a Δ A B C , a = 1 and the perimeter is six times the AM of the sines of the angles. The measure of ∠ A is

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SRMJEEE Maths Mock Test - 2 - Question 8
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if A is a 3 x 3 matrix and B is its adjoint matrix. If ∣B∣ = 64, then ∣A∣ =

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SRMJEEE Maths Mock Test - 2 - Question 9
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If and are two square matrices such that , then

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SRMJEEE Maths Mock Test - 2 - Question 10
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If f(x) = {2x - 3, x ≤ 2} then f(1) is equal to

Detailed Solution: Question 10

To find f(1) from the function f(x) = 2x - 3 when x ≤ 2, follow these steps:

  • Substitute x = 1 into the function: f(1) = 2(1) - 3.
  • Calculate the value: 2 - 3 = -1.

Now, calculate f(2):

  • Use the same function with x = 2: f(2) = 2(2) - 3.
  • Compute the result: 4 - 3 = 1.

We found f(1) = -1 and f(2) = 1.

Therefore, f(1) is equal to -f(2).

SRMJEEE Maths Mock Test - 2 - Question 11
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If x dy = y(dx + y dy), y > 0 and y (1) = 1, then y (-3) is equal to

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SRMJEEE Maths Mock Test - 2 - Question 12
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Equation 2x2+7xy+3y2+8x+14y+λ=0 represents a pair of straight lines, value of λ is

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SRMJEEE Maths Mock Test - 2 - Question 13
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In the expansion of (y1/6 - y-1/3)9 the term independent of y is :

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SRMJEEE Maths Mock Test - 2 - Question 14
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If then a and b are

SRMJEEE Maths Mock Test - 2 - Question 15
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The points with position vectors 10î + 3ĵ, 12î - 5ĵ and aî + 11ĵ are collinear if a =

Detailed Solution: Question 15

Given, A = (10i + 3j​)
B = (12i - 5j)​
C = (ai + 11j​)
AB = 2i - 8j​
AC = (a - 10)i + 8j​
AB and AC are collinear
⇒ 2/(a - 10) = -8/8
⇒ 2 = 10 - a
⇒ a = 8

SRMJEEE Maths Mock Test - 2 - Question 16
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Detailed Solution: Question 16

SRMJEEE Maths Mock Test - 2 - Question 17
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If  then the value of a + c is equal to

Detailed Solution: Question 17


Comparing the elements we get c + 1 = 0 ⇒ c = −1 and a−1=0⇒a=1

SRMJEEE Maths Mock Test - 2 - Question 18
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A committee consists of 9 experts from three institutions A, B and C, of which 2 are from A, 3 from B and 4 from C. If three experts resign, then the probability that they belong to different institutions is

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SRMJEEE Maths Mock Test - 2 - Question 19
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The number of vectors of unit length perpendicular to vectors and is

SRMJEEE Maths Mock Test - 2 - Question 20
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If then is

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Since for all i.
for all

SRMJEEE Maths Mock Test - 2 - Question 21
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The sum of an infinite G.P. is 3. The sum of the series formed by squaring its terms is also 3. The series is

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SRMJEEE Maths Mock Test - 2 - Question 22
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If the two circles 2x2 + 2y2 -3x + 6y + k = 0 and x2 + y2 - 4x + 10y + 16 = 0 cut orthogonally, then the value of k is

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SRMJEEE Maths Mock Test - 2 - Question 23
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The equation line passing through the point P(1,2) whose portion cut by axes is bisected at P, is

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SRMJEEE Maths Mock Test - 2 - Question 24
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The strength of a beam varies as the product of its breadth b and square of its depth d. A beam cut out of a circular log of radius r would be strong when

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SRMJEEE Maths Mock Test - 2 - Question 25
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The equation of the common tangent to the curves y2=8x and xy=-1 is :

Detailed Solution: Question 25

SRMJEEE Maths Mock Test - 2 - Question 26
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If a matrix is such that
Then what is equal to?

Detailed Solution: Question 26

Let A be a matrix such that
Post multiply by on both the sides, we get

SRMJEEE Maths Mock Test - 2 - Question 27
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If α, β are the roots of the equation x2- 2x + 2 = 0, then the value of α2 + β2 is

Detailed Solution: Question 27

α + β = 2
αβ = 2
(α + β)2 = 22
α2 + β2 +2αβ = 4
α2 + β2 +2(2) = 4
α2 + β2 + 4 = 4
α2 + β2 = 0

SRMJEEE Maths Mock Test - 2 - Question 28
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The order and degree of differential equation √(dy/dx) - 4 (dy/ dx) - 7x = 0 are

Detailed Solution: Question 28

√(dy/ dx)- 4 (dy/dx) -7x = 0
or √(dy/ dx) = 4 (dy/dx) + 7x
Squaring both side
dy/ dx = [4 (dy/dx ) + 7x]2
or dy dx = 16 ( dy/dx )2 + 49x2 + 56 dy/ dx x
∴ order = 1
degree = 2

SRMJEEE Maths Mock Test - 2 - Question 29
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How many total words can be formed from the letters of the word INSURANCE in which vowels are always together?

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SRMJEEE Maths Mock Test - 2 - Question 30
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The 5th term of a G.P. is 2, then the product of its first 9 term is

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About this JEE Mock Test

This mock test contains 40 questions designed to replicate the pattern, difficulty level and time pressure of the actual JEE exam. It is part of SRMJEEE Subject Wise & Full Length Mock Tests 2026 on EduRev, covering all the topics that are being asked as per the current JEE syllabus. Attempting this test under timed conditions will help you assess your exam readiness, identify subject-wise weak areas, and improve your speed and accuracy before the actual exam.

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