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SRMJEEE Maths Mock Test - 2 - JEE MCQ


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30 Questions MCQ Test - SRMJEEE Maths Mock Test - 2

SRMJEEE Maths Mock Test - 2 for JEE 2024 is part of JEE preparation. The SRMJEEE Maths Mock Test - 2 questions and answers have been prepared according to the JEE exam syllabus.The SRMJEEE Maths Mock Test - 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SRMJEEE Maths Mock Test - 2 below.
Solutions of SRMJEEE Maths Mock Test - 2 questions in English are available as part of our course for JEE & SRMJEEE Maths Mock Test - 2 solutions in Hindi for JEE course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt SRMJEEE Maths Mock Test - 2 | 35 questions in 50 minutes | Mock test for JEE preparation | Free important questions MCQ to study for JEE Exam | Download free PDF with solutions
SRMJEEE Maths Mock Test - 2 - Question 1
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Every continuous function is

SRMJEEE Maths Mock Test - 2 - Question 2
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Area bounded by the curve xy2 = a2 (a - x) and y-axis is

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SRMJEEE Maths Mock Test - 2 - Question 3
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Let f(x) = [cos x + sin x], 0 < x < 2π where [x] denotes the greatest integer less than or equal to x. The number of points of discontinuity of f(x) is

Detailed Solution for SRMJEEE Maths Mock Test - 2 - Question 3

We know that [x] is discontinuous at integral values of x.

SRMJEEE Maths Mock Test - 2 - Question 4
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The term independent of x in the expansion of ((2x) - (3/x))6 is
SRMJEEE Maths Mock Test - 2 - Question 5
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The lines 2x - 3y = 5 and 3x - 4y = 7 are the diameters of a circle of area 154 square units. The equation of the circle is
Detailed Solution for SRMJEEE Maths Mock Test - 2 - Question 5

The correct option is B  x2+y2−2x+2y=47
Centre of circle = Point of intersection of diameters = (1, ­–1)

Now area = 154 ⇒ πr2=154 ⇒ r=7

Hence the equation of required circle is(x−1)2+(y+1)2 = 72 ⇒ x2+y2−2x+2y = 47.

SRMJEEE Maths Mock Test - 2 - Question 6
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Coordinates of two points are A(1,0) and B(-1,0) and Q is a point which satisfies AQ-BQ = + 1. The locus of the point Q is
Detailed Solution for SRMJEEE Maths Mock Test - 2 - Question 6
Option B is correct.
SRMJEEE Maths Mock Test - 2 - Question 7
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The equation of tangent at point (1,2) to the parabola y2=4x is
SRMJEEE Maths Mock Test - 2 - Question 8
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The number of solutions of the equation

SRMJEEE Maths Mock Test - 2 - Question 9
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The area bounded by the curve y=sinx, y=0, x=0 and x=(π/2) is
SRMJEEE Maths Mock Test - 2 - Question 10
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The family of curves, in which the subtangent at any point to any curve is double the abscissa, is given by
SRMJEEE Maths Mock Test - 2 - Question 11
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If the matrix is singular one, then λ is
SRMJEEE Maths Mock Test - 2 - Question 12
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SRMJEEE Maths Mock Test - 2 - Question 13
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∫x sec2x dx=
SRMJEEE Maths Mock Test - 2 - Question 14
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SRMJEEE Maths Mock Test - 2 - Question 15
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SRMJEEE Maths Mock Test - 2 - Question 16
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If A and B are 2 x 2 matrices then (A+B)2=
SRMJEEE Maths Mock Test - 2 - Question 17
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The ratio of the altitude of the cone of greatest volume which can be inscribed in a given sphere to the diameter of the sphere is
SRMJEEE Maths Mock Test - 2 - Question 18
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The mean of 3, y, 4, x, 10, is 5, then y =
SRMJEEE Maths Mock Test - 2 - Question 19
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The inverse of matrix

SRMJEEE Maths Mock Test - 2 - Question 20
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In a certain distribution, the following results were obtained  , Median = 48, Coefficient of skewness = -0.3.

What is the value of standard deviation?
SRMJEEE Maths Mock Test - 2 - Question 21
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The angle between lines y2sin2θ-xysin2θ+x2(cos2θ-1) = 1 is
SRMJEEE Maths Mock Test - 2 - Question 22
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Three identical dice are rolled. The probability that the same number will appear on each of them is
SRMJEEE Maths Mock Test - 2 - Question 23
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If the sides of a triangle are proportional to the cosines of the opposite angles then the triangle is
SRMJEEE Maths Mock Test - 2 - Question 24
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If the difference between the corresponding roots of x2 + ax + b = 0 and x2 + bx + a = 0 is same and a ≠ b, then
SRMJEEE Maths Mock Test - 2 - Question 25
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If A.M. between two numbers is 5 and their G.M. is 4, then their H.M. is
Detailed Solution for SRMJEEE Maths Mock Test - 2 - Question 25

If x, y and z respectively represent AM, GM and HM between two numbers a and b, then
y2 = xz
Here x = 5, y = 4
then 16 = 5 x z
z = 16/5

SRMJEEE Maths Mock Test - 2 - Question 26
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A condition for a function y = f (x) to have an inverse is that it should be
SRMJEEE Maths Mock Test - 2 - Question 27
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The number of 4-digit even numbers that can be formed using 0, 1, 2, 3, 4, 5, 6 without repetition is
Detailed Solution for SRMJEEE Maths Mock Test - 2 - Question 27

Each even number must have 0, 2, 4 or 6 in is units place
Here total number of digits = 7

When 0 occurs at units place there is no restriction on other places and when 2 or 4 occurs at units place there is restriction on thousands' place as 0 can not be put at thousands' place
Case I When 0 occurs at units place:

∴ The number of numbers formed in this case

Case II. When 0 does not occur at units place:

The units' place can be filled up by any one of the three digits 2, 4 and 6 in 3 ways
∴ The number of numbers formed in this case

∴ The required number = 120 + 300 = 420

SRMJEEE Maths Mock Test - 2 - Question 28
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The derivative of is given by
SRMJEEE Maths Mock Test - 2 - Question 29
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A line passing through point A(-5,-4) meet other three lines x + 3y + 2 = 0, 2x + y + 4 = 0 and x - y - 5 = 0 at B, C and D respectively. If (15/AB )2 + (10/AC)2 = (6/AD)2, then the equation of line is
Detailed Solution for SRMJEEE Maths Mock Test - 2 - Question 29

Equation of any line through A(-5, -4) is

then the coordinates of any point on this line at a distance r from A are
(r cosθ - 5, r sinθ - 4)
If AB = r1, AC = r2, AD = r3
then (r1 cosθ - 5, r1 sinθ - 4) lies on x + 3y + 2 = 0
⇒ r1 cosθ - 5 + 3 (r1 sinθ - 4) + 2 = 0
⇒ r1 (cosθ + 3 sinθ) = 15

Therefore according to the given condition

Hence the required equation of the line is

SRMJEEE Maths Mock Test - 2 - Question 30
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X follows a binomial distribution with parameters n = 6 and p. If 4 P (X = 4) = P (X = 2), then p =
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