Practice Mock Test for SNAP - 14 - CAT MCQ

If there are no conditions, then the total number of possibilities is 3 × 3 × 2 = 18. As per the given conditions, she will not carry the white purse with her black dress. She can combine the two pairs of shoes with the white purse and the black dress. These two possibilities are ruled out. Thus the total number of possibilities is 18 – 2 = 16.

Since the number is divisible by 9, the sum of its digits must be a multiple of 9.

Since, 45 + A + B is a multiple of 9, A + B = 9.........(i)

Now, as the number is divisible by 11, using divisibility test for 11 yields (22 + B) – (23 + A) is 0 or a multiple of 11.

This simplifies to (B – A – 1) is 0 or a multiple of 11.

The only possible value is 0.

So, (B – A) = 1................(ii)

Solving these equations (i) and (ii),we get A = 4 and B = 5.

From the information, it can be concluded that the values over the years form an AP with common difference 200. The no of terms is 10 and their sum id 10500.Therefore, we get

Solve this equation to get a = 150.

So the value of the certificates purchased in the 7^th year is 150 + (6 × 200) = Rs. 1350.

Statement I alone is not sufficient to answer the question since it does not provide any information about adults. Statement II gives the ratio of the number of adults to the number of children needed. Since the total number of actors is known, statement II alone is sufficient to answer the question.

This question is best solved by working backwards. In the 4^th temple, 60 flowers are offered and then there are no flowers left. This means that the person had 60 flowers, which were obtained by making the initial number 5-fold. Since 60 = 12 × 5, the person had 12 flowers when he was entering the 4^th temple. So, the person must have 12 flowers with him after offering 60 flowers in the 3^rdtemple. This means that he had 60 + 12 = 72 flowers in the 3^rd temple. Working with the same logic as before, 72 = 18 × 4 implies that he had 18 flowers left after the 2^nd temple, or, 60 + 18 = 78 flowers in the 2^nd temple. Now, 78 = 26 × 3 implies that he had 26 + 60 = 86 flowers in the 1^st temple. Since 86 = 43 × 2, he had 43 flowers in the beginning.

The total number of small cubes is 6 × 7 × 13 = 546. The number of cubes with no face painted is 4 × 5 × 11 = 220. Therefore the number of cubes with at least one face painted is 546 – 220 = 326.

The given information states that Vrinda prefers Sheldon to Wallace. So, she would read Sheldon before Wallace. So, whatever be the order that she reads books, she cannot read Wallace first.

Suppose the number is x. then, (8 + x) / (21 + x) = (13 + x) / (31 + x). Solving this equation yields x = 5.

The difference between the divisors and corresponding remainders is always 15. So the required number of tiles is

LCM(24, 36, 42) – 15 = 504 – 15 = 489.

Simple interest will always be less than compound interest. In compound interest, as the number of calculations per year increases, the interest also increases. Therefore, Sunil will pay the second highest interest.

Suppose B can complete 4 units of work in 4 days. Then, A can complete 2 units in 3 days, i.e., 4 units in 6 days.

In other words, A and B can complete 2/3 units and 1 unit of work each day respectively.

Since they work together, they can complete 2/3 + 1 = 5/3 units of work each day.

Working together, they can complete the job in 18 days. So the total work is (5/3) x 18 = 30 units.

B completes 1 unit per day, thus he can complete the job in 30 days.

We shall solve this question by options. Substitute x = 5000 in option 3,we get y = 26000. Again put x = 7000 in option 3, we get y = 34000. Hence option 3 is the answer.

Suppose the volume of the tank is 120 litres. In 1 hour, P, Q and R can fill 30, 15 and 10 litres respectively while S can empty 12 litres. From this, the effective per hour rates(putting the values in option),

for eg in option pipe

Q = 15,

P and S = 30 - 12 = 18.

P, R, S = 30 + 10 - 12 = 28.

Q, R, S = 15 + 10 - 12 = 13.

Thus for answer choices a to d, the rates are are 15, 18, 28 and 13 litres per hour respectively.Thus if the combination from the option are used to find the time i.e 120/rate, the times taken will be 8, 6.66, 4.28 and 9.23 hours respectively. Hence option C.

The installments will form a GP with common ratio 2. The sum of this GP is 32760

= a(2¹² – 1) / (2 – 1).

Solving this equation yields a = 8.

Thus the 2^nd installment is 8 x 2 = 16 and the last installment is 8 x 2¹¹ = 16384.

Suppose the first term is a and the common difference is d. Then the 7^th term and the 10^th term are (a + 6d) and (a + 9d) respectively.

So, (a + 6d) / (a + 9d) = -1.

Simplifying this ratio gives 2a + 15d = 0.

The 16^th term is a + 15d = -15.

Solving these as simultaneous equations yields

a = 15 and d = -2.

The 3^rd term is a + 2d = 15 – 4 = 11.

We are interested in the case where one of them gets a seat and the other doesn’t.

The probability of A not getting seat is =1-1/3 = 2/3

The probability of B not getting seat is =1-1/5 = 4/5

The required probability is (1/3 × 4/5) + (2/3 × 1/5) = 2/5.

The diameter of the circle becomes the diagonal of the first square. So the side of the first square is R(2)^1/2. This side becomes the diameter of the second circle as well as the diagonal of the second square. So the side of the second square will be R.

The number of ways in which the horses can graze is ⁷P₃ = 210.

In state A, 12% of 30 lakhs, i.e., 3.6 lakh are literate and women among them are 2/5^th of 3.6 lakh, that happens to be

72000×2 = 144000.

40% of literate people in state A are women. Referring to the previous solution, the number of literate women is 144000. So the company needs to print 144000 brochures of types A, B and C in the ratio 3 : 6 : 1. Thus the company must print (1/10) x 144000 = 14400 brochures of type C.

25% of the people in state C are literate. So, (3/4) x 30 lakh = 22.5 lakh people in state C are illiterate. 40% of these, i.e., 9 lakh are men.

10% of the people in state E are literate. So, (9/10) x 60 lakh = 54 lakh people in state E are illiterate. 60% of these, i.e., 32.4 lakh are men.

Since the ratio of teachers to population is always 1 : 100, the ratio of the number of teachers required in state C to that required in state E = 9 / 32.4.

1500 of the 2500 vehicles on Wednesday were cars. This is 60%

The total money collected from the 1000 trucks and 2000 cars on Friday was

(1000 × 1) + (2000 × 0.5) = Rs. 2000.

From the diagram it is clear that Tuesday has the maximum number of trucks. Hence option B is the answer.

The least number of trucks cross the bridge on Saturday and Sunday. Therefore these days should be selected for the weekly offs. Hence option C is the answer

Now , we know the Pythagorean Triplet (8,15, 17). Thus, if 5x = 15 = ⇒ x = 3 then it also satisfies 3x - 1 = 8 when we put x = 3

Thus, length of hypotenuse is 17cm.

L - B = 23 & 2(L + B) = 206 or L + B = 103. Now, solving we get L = 63 and B = 40. So, area = (L × B) = 63 ×  40 = 2520.

Area of quadrilateral = Ar(ΔABC +ΔACD).

Ar (ΔACD) = √3/4(20)² = 173.

Ar (ΔABC) = 96.