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RRB Group D / RPF Constable Exam  >  RRB Group D / RPF Constable Tests  >  OneTime: RRB Group D Practice Test - 2 - RRB Group D / RPF Constable MCQ

OneTime: RRB Group D Practice Test - 2 - RRB Group D / RPF Constable MCQ


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30 Questions MCQ Test - OneTime: RRB Group D Practice Test - 2

OneTime: RRB Group D Practice Test - 2 for RRB Group D / RPF Constable 2025 is part of RRB Group D / RPF Constable preparation. The OneTime: RRB Group D Practice Test - 2 questions and answers have been prepared according to the RRB Group D / RPF Constable exam syllabus.The OneTime: RRB Group D Practice Test - 2 MCQs are made for RRB Group D / RPF Constable 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for OneTime: RRB Group D Practice Test - 2 below.
Solutions of OneTime: RRB Group D Practice Test - 2 questions in English are available as part of our course for RRB Group D / RPF Constable & OneTime: RRB Group D Practice Test - 2 solutions in Hindi for RRB Group D / RPF Constable course. Download more important topics, notes, lectures and mock test series for RRB Group D / RPF Constable Exam by signing up for free. Attempt OneTime: RRB Group D Practice Test - 2 | 100 questions in 90 minutes | Mock test for RRB Group D / RPF Constable preparation | Free important questions MCQ to study for RRB Group D / RPF Constable Exam | Download free PDF with solutions
OneTime: RRB Group D Practice Test - 2 - Question 1
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Bhim can complete a work in 15 days and Amar can do the same work in 18 days. Bhim worked for 10 days and left the job. In how many days, Amar alone can finish the remaining work?

Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 1

Explanation in English :

Bhim’s 1 day work = 1/15

∴ Bhim’s 10 day work = 10 * 1/15 = 2/3

Remaining work = (1 – 2/3) = 1/3

Now, 1/18 work is done by Amar in 1 day.

∴ 1/3 work is done by Amar in (18 * 1/3) = 6 days.

OneTime: RRB Group D Practice Test - 2 - Question 2
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The present ages of Muni and Pani are in the ratio 15 : 8. After 8 years, their ages will be in the ratio 17 : 10. The present age of Muni is

Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 2

Explanation in English :

Let present ages of Muni and Pani be 15x and 8x.

According to given statement

(15x + 8)/(8x + 8) = 17/10

150x + 80 = 136x + 136

14x = 56

x = 4

Hence, present age of Muni = 15x

= 15 X 4 = 60 years.

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OneTime: RRB Group D Practice Test - 2 - Question 3
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In a rectangle, the length is thrice its breadth. If the area of the rectangle is 6075 cm2, the length will be

Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 3

Let the breadth of rectangle be ‘b’ cm

∴ length will be = ‘3b’ cm

=> b * 3b = 6075

=> b2 = 6075/3 = 2025

=> b = 45 cm

Length of the rectangle = 3 * 45 = 135 cm.

OneTime: RRB Group D Practice Test - 2 - Question 4
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The profit earned after selling a box for Rs. 1516 is the same as loss incurred after selling it for Rs. 1112. What is the cost price of the box?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 4

According to the given statement

1516 – x = x – 1112, where x is the CP

2x = 2628

x = CP = Rs. 1314

OneTime: RRB Group D Practice Test - 2 - Question 5
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The average age of 80 kids in a class is 15. The average age of a group of 15 kids in the class is 16 and the average age of another 25 kids in the class is 14. What is the average age of the remaining kids in the class?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 5

Let S80 be the sum of the ages of kids

S15 be the sum of the ages of a group of 15 kids

S25 be the sum of the ages of another 25 kids

As per problem,

S80 = 15 X 80 = 1200

S15 = 16 X 15 = 240

S25 = 14 X 25 = 350

Sum of the ages of remaining kids = 1200 – (S15 + S25)

= 1200 – (240 + 350)

= 1200 – 590

= 610

∴ Average = 610/40 = 15.25

OneTime: RRB Group D Practice Test - 2 - Question 6
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Ramya purchased an item of Rs. 460 and sold it at loss of 12 percent. With that amount, she purchased another item and sold it at a gain of 12 percent. What was her overall gain/loss?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 6

Explanation in English :

Loss of 12% = (88/100) X 460

= Rs. 404.8

On this amount, profit of 12% = (112/100) X 404.8

= 453.376

In overall transaction, since CP is greater than SP, it’s loss

Loss = 460 – 453.376

= Rs. 6.624

OneTime: RRB Group D Practice Test - 2 - Question 7
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16 fitters and 12 welders together can complete a work in 8 days. 20 fitters can complete the same work in 16 days. How many days will 16 welders take to complete the same work?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 7

F = Fitter; W = Welder

(16F + 12W) X 8 = 20F X 16

128F + 96W = 320F

96W = 192F

W = 2F

∴ 20 fitters will correspond to 10 welders

10 welders can complete the work in 16 days

∴ 16 welders can complete the work in (16 X 10)/16

= 10 days

OneTime: RRB Group D Practice Test - 2 - Question 8
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The average height of 34 students of a school is 150 cm. If the height of the teacher is included, the average rises by 1 cm. Find the height of the teacher.
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 8

et S34 be the sum of the heights of students

S35 be the sum of the heights of students + teacher

As per problem,

S34 = 150 X 34 = 5100

S35 = 151 X 35 = 5285

Height of the teacher = 5285 – 5100

= 185 cm

OneTime: RRB Group D Practice Test - 2 - Question 9
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A sum of money becomes 3 times in 5 years under simple interest. In how many years it will become 5 times at the same rate of simple interest?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 9

As per given statement,

(P X 5 X R)/100 = 2P

R = 40%

In second case,

(P X T X 40)/100 = 4P

=> T = 10 years

OneTime: RRB Group D Practice Test - 2 - Question 10
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Which is the least number to be subtracted from 3198 to make it a perfect square?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 10

The perfect squares, between which 3198 lies, are

3136 and 3249

3136 < 3198 < 3249

∴ 3198 – 3136 = 62 is the number which has to subtracted from 3198 to make it a perfect square.

OneTime: RRB Group D Practice Test - 2 - Question 11
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What will come in the place of question mark?

326, 982, 353, 1009, 380, ?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 11

Explanation in English :

 

326(+27=) 353(+27=)380

982(+27=) 1009(+27=) 1036

Explanation in Hindi :

 

326(+27=) 353(+27=)380

982(+27=) 1009(+27=) 1036

OneTime: RRB Group D Practice Test - 2 - Question 12
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What will come in the place of question mark?

63, 54, 45, 36, ?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 12

63(-9=) 54(-9=) 45(-9=) 36(-9=) 27

Explanation in Hindi :

 

63(-9=) 54(-9=) 45(-9=) 36(-9=) 27

OneTime: RRB Group D Practice Test - 2 - Question 13
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What will come in the place of question mark?

147, 130, 113, 96, ?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 13

 

147(-17=) 130(-17=) 113(-17=) 96(-17=) 79

Explanation in Hindi :

 

147(-17=) 130(-17=) 113(-17=) 96(-17=) 79

OneTime: RRB Group D Practice Test - 2 - Question 14
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As per following data, solve the questions

Find the  total number of girls across all three classes.
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 14

First, compute the actual numbers in each class:

  • Class 5: ratio 2 : 3, total 60 → one part = 60/5 = 12
    • Boys = 2×12 = 24
    • Girls = 3×12 = 36

  • Class 6: ratio 3 : 2, total 40 → one part = 40/5 = 8
    • Boys = 3×8 = 24
    • Girls = 2×8 = 16

  • Class 7: ratio 2 : 1, total 30 → one part = 30/3 = 10
    • Boys = 2×10 = 20
    • Girls = 1×10 = 10

Then the total number of girls across all three classes is
36 + 16 + 10 = 62.

 

OneTime: RRB Group D Practice Test - 2 - Question 15
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Total number of boys from Class 5, 6 and 7 is
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 15

[(2/5) X 60] + [(3/5) X 40] + [(2/3) X 30]

= 24 + 24 + 20

= 68

OneTime: RRB Group D Practice Test - 2 - Question 16
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Difference between 5th class girls and 7th class boys is
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 16

[(2/3) X 30] ~ [(3/5) X 60] = 20 ~ 36

= 16

OneTime: RRB Group D Practice Test - 2 - Question 17
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The sum of a number and its four-fifth is 27. What is the number?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 17

If x is the required number,

Then according to the problem statement

x + (4/5)x = 27

5x + 4x = 135

9x = 135

x = 15

OneTime: RRB Group D Practice Test - 2 - Question 18
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If + means *, - means ÷, * means -, ÷ means +, then solve the following
25 + 6 – 2 * 1 = ?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 18

25 + 6 – 2 * 1 = ?

25 x 6 ÷ 2 – 1 = ?

25 x 3 – 1 = ?

75 – 1 = ?

∴ ? = 74

OneTime: RRB Group D Practice Test - 2 - Question 19
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A person is standing at a distance from a flag post and the height of the flag post is 20 m. Angle of elevation from his toe is 45o. How far is he standing from the flag post?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 19


 

tan 450 = 20/x, where x = distance of the person from the flag post

1 = 20 / x

∴ x = 20 m

OneTime: RRB Group D Practice Test - 2 - Question 20
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In a regular pentagon, the exterior angle will be ______
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 20

OneTime: RRB Group D Practice Test - 2 - Question 21
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The average speed of a bus is 4/5th the average speed of a bike. The bike covers 520 km in 8 h. How much distance (in km) will the bus cover in 9 h?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 21

Average speed of bike = 520/8 = 65 km/h

Average speed of bus = 4/5 * 65 = 52 km/h

Distance covered by bus = 52 * 9 = 468 km.

OneTime: RRB Group D Practice Test - 2 - Question 22
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A train crosses a platform in 60 sec and a man standing on the platform in 20 sec. What is the length of the platform? (Consider length of train to be 280m)
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 22

Let the length of platform be x m.

Speed of train = (x + 280)/60 = 280/20

=> (x + 280)/60 = 14

=> x + 280 = 840

=> x = 560 m.

OneTime: RRB Group D Practice Test - 2 - Question 23
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Angle in the semi-circle will be
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 23

OneTime: RRB Group D Practice Test - 2 - Question 24
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The factors of x2 + 16x + 48 are
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 24

x2 + 12x + 4x + 48

= x(x + 12) + 4(x + 12)

= (x + 12) (x + 4)

OneTime: RRB Group D Practice Test - 2 - Question 25
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Which of the following has the longest wavelength?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 25

Red light has longest wavelength = 620-740 nm

OneTime: RRB Group D Practice Test - 2 - Question 26
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Optical fiber works on the principle of
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 26

An optical fiber is a cylindrical dielectric waveguide, that transmits light along its axis, by the process of total internal reflection.

OneTime: RRB Group D Practice Test - 2 - Question 27
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SONAR is based on the principle of
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 27

Sonar uses the echo principle by sending out sound waves underwater or through the human body to locate objects.

OneTime: RRB Group D Practice Test - 2 - Question 28
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1 amu is equal to –
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 28

1 a.m.u. = 1.6726219 × 10−24 g

1 a.m.u. = 1.6726219 × 10−27 kg

OneTime: RRB Group D Practice Test - 2 - Question 29
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Bar is unit of –
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 29

No explanation provided

OneTime: RRB Group D Practice Test - 2 - Question 30
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Which of the following is a base soluble in water?
Detailed Solution for OneTime: RRB Group D Practice Test - 2 - Question 30

KOH; alkali is a base which are soluble in water.

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