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SSC CPO Mock Test (Paper 1) - 6 - SSC MCQ


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30 Questions MCQ Test - SSC CPO Mock Test (Paper 1) - 6

SSC CPO Mock Test (Paper 1) - 6 for SSC 2024 is part of SSC preparation. The SSC CPO Mock Test (Paper 1) - 6 questions and answers have been prepared according to the SSC exam syllabus.The SSC CPO Mock Test (Paper 1) - 6 MCQs are made for SSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for SSC CPO Mock Test (Paper 1) - 6 below.
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SSC CPO Mock Test (Paper 1) - 6 - Question 1
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Complete the analogous pair.
CDBE : EFDG :: NOMP : ?

Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 1

Given Pair:

CDBE : EFDG

Analyzing the Pattern:

  • C → E (Move 2 letters forward in the alphabet)
  • D → F (Move 2 letters forward in the alphabet)
  • B → D (Move 2 letters forward in the alphabet)
  • E → G (Move 2 letters forward in the alphabet)

Applying the Same Pattern to NOMP:

  • N → P (Move 2 letters forward in the alphabet)
  • O → Q (Move 2 letters forward in the alphabet)
  • M → O (Move 2 letters forward in the alphabet)
  • P → R (Move 2 letters forward in the alphabet)

The correct sequence is PQOR.

Correct Answer:

A: PQOR

SSC CPO Mock Test (Paper 1) - 6 - Question 2
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If the letters in each of the following five words are first rearranged in the alphabetical order and then the groups of letters so formed are rearranged as in a dictionary, which word would have its group of letters in the MIDDLE among the five?

Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 2
When the letters in each of the words are arranged in alphabetical order it becomes as follows:
cdeo, ackl, eemt, and ador.
Now when the words are rearranged as in a dictionary then their respective position becomes as follows : ackl, ador, cdeo and eemt.
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SSC CPO Mock Test (Paper 1) - 6 - Question 3
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Re-arrange the given words in alphabetical order and tick the one that comes in the middle.

SSC CPO Mock Test (Paper 1) - 6 - Question 4
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Choose the numeral pair which is different from others .
SSC CPO Mock Test (Paper 1) - 6 - Question 5
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Complete the analogous pair.
Shoes : Leather : : Brick :?
SSC CPO Mock Test (Paper 1) - 6 - Question 6
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Choose the word which is least like the other words in the group .
SSC CPO Mock Test (Paper 1) - 6 - Question 7
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Choose the number which is different from others.
SSC CPO Mock Test (Paper 1) - 6 - Question 8
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Complete the analogous pair.
Skirmish : War : : Disease : ?
SSC CPO Mock Test (Paper 1) - 6 - Question 9
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Complete the analogous pair.
Push : Pull : : Throw : ?
SSC CPO Mock Test (Paper 1) - 6 - Question 10
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Count the number of triangles in the figure given below
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 10

After labelling the figure in the question, it looks like as under:

There are sixteen triangles in this figure namely:
AMN, AMB, ABN, ACD, ACO, AOD, OSR, OSE, OER, OFG, OFH, OHG, PMC, NQD, COS and ODR

SSC CPO Mock Test (Paper 1) - 6 - Question 11
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Complete the analogous pair.
Bizarre : Unusual :: Whimsical : ?
SSC CPO Mock Test (Paper 1) - 6 - Question 12
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Ravi walks 100 m from his house towards North. From there he goes 100 m towards West. Here is the house of Sunder. From there they both goes to the market which is in the South-West direction from Sunder's house. If the market is in the West of Ravi's house, then how far is the market from Ravi's house?
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 12

  1. Ravi's Movement:

    • Ravi walks 100 m North from his house.
    • Then, he walks 100 m West, reaching Sunder's house.

  2. Market's Location:

    • The market is located in the South-West direction from Sunder's house.
    • It is also mentioned that the market is directly West of Ravi's house.

Analyzing the Situation:

  • Ravi's initial position is his house. He moves 100 m North and then 100 m West to reach Sunder's house.
  • From Sunder's house, moving in the South-West direction and ending up directly West of Ravi's house means the market is located somewhere along the West line from Ravi's house.

Distance Calculation:

  • From Sunder's house (which is 100 m North and 100 m West of Ravi's house), moving South-West (which forms a 45-degree angle) would imply that the market lies directly West of Ravi's house, maintaining the same vertical distance from the original North-South line.

Using the Pythagorean theorem to find the direct distance between Ravi's house and the market:

  • The North and South directions cancel out as the market is directly West.
  • The direct distance traveled diagonally from Sunder's house to the market is 100 m (since it's 100 m North and 100 m West).

Thus, the total horizontal distance from Ravi's house to the market is:

  • 100 m (West from Ravi's house to Sunder's house)
  • 100 m (diagonal from Sunder's house to the market, projected onto the West line)

Total distance: 100+100=200 m.

Conclusion:

The correct distance from Ravi's house to the market is:

C: 200 m.

SSC CPO Mock Test (Paper 1) - 6 - Question 13
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Study the following and answer the question based on it.
1. A,B,C,D,E,F and G are sitting on a wall and they all facing to north.
2. C is at the right of D.
3. B is at the end and E is his neighbour.
4. G is sitting between E and F.
5. D is third from southen end.
Which of the conditions is not necessary to find the position of A?
SSC CPO Mock Test (Paper 1) - 6 - Question 14
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If the following series is written in the reverse order and the alternate letter are deleted from it then which letter will divide the new series in two equal parts?
ABCDEFGHIJKLMNOPQRSTUVWXYZ.
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 14
SSC CPO Mock Test (Paper 1) - 6 - Question 15
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Group the following figures into three classes on the basis of identical properties.
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 15
3,6,9 are geometrical figures containing line segments (the number of these line segments is half the number of sides in the figure) parallel to the sides of the figure.
1,5,8 consist of a circle and a triangle intersecting it. The triangle is also divided into two equal parts by a straight line.
2,4,7 are all funnel shaped figures.
SSC CPO Mock Test (Paper 1) - 6 - Question 16
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Find the missing character.
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 16
The lower number is obtained by adding the squares of the upper two numbers. Thus,
In fig. (A), 22+42=20.
In fig. (B), 32+92=90.
∴ In fig. (C), missing number = 12+52=26.
SSC CPO Mock Test (Paper 1) - 6 - Question 17
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Find the missing character.
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 17
Clearly, (1st cell of 1st column)2+(2nd cell of 1st column)2+(3rd cell of 1st column)2=4th cell of 1st column.
Thus, in the first column, 4 2 + 2 2 + 1 2 = 21.
In the second column, 5 2 + 3 2 + 8 2 = 98.
∴ In the third column, missing number = 6 2 + 7 2 + 3 2 = 36 + 49 + 9 = 94.
SSC CPO Mock Test (Paper 1) - 6 - Question 18
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Choose the odd one out.
SSC CPO Mock Test (Paper 1) - 6 - Question 19
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Find the missing character.
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 19
Suppose X denotes the numbers in the first row and Y denotes the numbers in the second row.
Then, the pattern is X2 - X = Y.
32 - 3 = 9 - 3 = 6; 82 - 8 = 64 - 8 = 56; 102 - 10 = 100 - 10 = 90;
22 - 2 = 4 - 2 = 2; 12 - 1 = 1 - 1 = 0.
Similarly, 52 - 5 = 20.
So, the missing number is 5.
SSC CPO Mock Test (Paper 1) - 6 - Question 20
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Choose the odd one out.
SSC CPO Mock Test (Paper 1) - 6 - Question 21
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If the first and second letters of the 'UNPRECEDENTED' are interchanged with the last and second last letters and similarly the third and the fourth letters are interchanged with the third and the fourth letters from the last respectively and so on, then what will be the 7th letter to the right of the 3rd letter from the left?
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 21
U N P R E C E D E N T E D is represented as:

Third letter from left is T and 7th letter to the right of T is R
SSC CPO Mock Test (Paper 1) - 6 - Question 22
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If 'DO' is written as 'FQ' and 'IN' is written as 'KP', then how would 'AT' be written?
SSC CPO Mock Test (Paper 1) - 6 - Question 23
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In a certain code language 'how old are you' is written as '9734' and 'he is old' is written as '2 75'. How is 'he' written in that code language?
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 23
9734 → how old are you
275 → he is old
he → 2 or 5
SSC CPO Mock Test (Paper 1) - 6 - Question 24
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Which of the following combination of circles best represents Athlets, Sprinters and Marathon runners?
SSC CPO Mock Test (Paper 1) - 6 - Question 25
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The given diagram shows the number of students who failed in an examination comprising papers in English, Hindi and Mathematics. The total number of students who took the test is 500. What is the percentage of students who failed in atleast two subject ?
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 25

Number of students who failed at least two subjects
= 10 + 5 + 12 + 12 = 39
Hence, required percentage = 39 500 X 100 = 7.8

SSC CPO Mock Test (Paper 1) - 6 - Question 26
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If 'x' means '+', '+' means '÷', '÷' means '-' and '-' means 'X', what will be the value of the following expression?
5 - 7 x 9 + 3 x 2
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 26

5 - 7 x 9 + 3 x 2
⇒ 5 x 7 + 9 x 3 - 2 = 35 + 3 - 2
⇒ 38 - 2 = 36

SSC CPO Mock Test (Paper 1) - 6 - Question 27
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If Δ denotes =, + denotes > , - denotes >, □ denotes ≠, x denotes > and x denotes < then a + b -c denotes :-
SSC CPO Mock Test (Paper 1) - 6 - Question 28
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If + means -, - means x, x means ÷ and ÷ means +, then 15 x 3 x 10 + 5 - 3 = ?
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 28

15 x 3 + 10 - 5 x 3
= 5 + 10 - 15 = 0 (Use BODMAS Rule)

SSC CPO Mock Test (Paper 1) - 6 - Question 29
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Complete the analogous pair.
11529 : 72135 :: 152943 : ?
SSC CPO Mock Test (Paper 1) - 6 - Question 30
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Choose the odd one out.
Detailed Solution for SSC CPO Mock Test (Paper 1) - 6 - Question 30
  1. 385: Sum of digits = 3 + 8 + 5 = 16
  2. 582: Sum of digits = 5 + 8 + 2 = 15
  3. 671: Sum of digits = 6 + 7 + 1 = 14
  4. 264: Sum of digits = 2 + 6 + 4 = 12

Observations:

  • The sum of the digits for 385 is 16.
  • The sum of the digits for 582 is 15.
  • The sum of the digits for 671 is 14.
  • The sum of the digits for 264 is 12.

Conclusion:

so the odd number is 582 

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