Test: Force on a Current Carrying Conductor - Electrical Engineering (EE) MCQ

The force in a current carrying conductor is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them. Hence F=Kq1q2/r², where K is the constant of proportionality.

The force in a current carrying conductor is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

The force in a current carrying conductor is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

From the expression:
F=Kq1q2/r², the value of K being 9*10⁹, we get F=13.5kN.

Force is a cross product. A cross product involves the sine of the angle between them. If two quantities are parallel to each other, the angle between them is zero. Sin(0) is zero, hence force is zero.

When a charged particle is undeflected in a field, the magnitude of the magnetic force and electric force acting on the particle is the same, hence the ratio is 1.

Gravitational force is the weakest force in nature as it does not bind anything strongly with its help.

According to Flemming’s left hand rule, the index finger denotes the direction of magnetic field, the thumb denoted the direction of force and the middle finger denoted the direction of current.

When a conductor carries a certain value of current, the force developed in the conductor, the current in the conductor and the magnetic field in the conductor are mutually perpendicular to each other.

When a conductor carries a certain value of current, the force developed in the conductor, the current in the conductor and the magnetic field in the conductor are mutually perpendicular to each other.