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Adiabatic & Reradiating Surfaces - Free MCQ Practice Test with solutions,


MCQ Practice Test & Solutions: Test: Adiabatic & Reradiating Surfaces (10 Questions)

You can prepare effectively for Mechanical Engineering Heat Transfer with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Adiabatic & Reradiating Surfaces". These 10 questions have been designed by the experts with the latest curriculum of Mechanical Engineering 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Adiabatic & Reradiating Surfaces - Question 1

Two black discs each of diameter 50 cm are placed parallel to each other concentrically at a distance of one meter. The discs are maintained at 1000 K and 500 K. Calculate the heat flow between the discs when no other surface is present

Detailed Solution: Question 1

Q = F 12 A σ (T – T 4).

Test: Adiabatic & Reradiating Surfaces - Question 2

Two black discs each of diameter 50 cm are placed parallel to each other concentrically at a distance of one meter. The discs are maintained at 1000 K and 500 K. Calculate the heat flow between the discs when the disks are connected by a cylindrical black no-flux surface

Detailed Solution: Question 2

Q = F 12 A σ (T – T 4).

Test: Adiabatic & Reradiating Surfaces - Question 3

Heat exchange between two black surfaces enclosed by an insulated surface is given by

Detailed Solution: Question 3

This is the net heat exchange between two black surfaces enclosed by an insulated surface.

Test: Adiabatic & Reradiating Surfaces - Question 4

Heat exchange between two gray surfaces enclosed by an adiabatic surface is given by

Detailed Solution: Question 4

This is the net heat exchange between two gray surfaces enclosed by an adiabatic surface.

Test: Adiabatic & Reradiating Surfaces - Question 5

A blind cylindrical hole of 2 cm diameter and 3 cm length is drilled into a metal slab having emissivity 0.7. If the metal slab is maintained at 650 K, make calculations for the radiation heat escape from the hole

Detailed Solution: Question 5

Q = E 1 A 1 σ b T 14 [1 – F 11/1 – (1 – E 1) F 11].

Test: Adiabatic & Reradiating Surfaces - Question 6

A cavity in the shape of a frustum of a cone has diameter 30 cm and 60 cm and the height is 80 cm. If the cavity is maintained at temperature of 800 K, determine the heat loss from the cavity when the smaller diameter is at the bottom

Detailed Solution: Question 6

Q = E 1 A 1 σ b T 14 [1 – F 11/1 – (1 – E 1) F 11].

Test: Adiabatic & Reradiating Surfaces - Question 7

Consider the above problem, find how this heat loss would be affected if the cavity is positioned with bigger diameter at the base

Detailed Solution: Question 7

Percentage change in heat flow = 6577 – 1640/6577 = 0.7506.

Test: Adiabatic & Reradiating Surfaces - Question 8

A conical cavity of base diameter 15 cm and height 20 cm has inside surface temperature 650 K. If emissivity of each surface is 0.85, determine the net radiative heat transfer from the cavity

Detailed Solution: Question 8

Q = E 1 A 1 σ b T 14 [1 – F 11/1 – (1 – E 1) F 11]. Here, F 11 = 0.649 and A 1 = 0.0503 m2.

Test: Adiabatic & Reradiating Surfaces - Question 9

A cylindrical cavity of base diameter 15 cm and height 20 cm has inside surface temperature 650 K. If emissivity of each surface is 0.85, determine the net radiative heat transfer from the cavity

Detailed Solution: Question 9

Q = E 1 A 1 σ b T 14 [1 – F 11/1 – (1 – E 1) F 11]. Here, F 11 = 0.842 and A 1 = 0.11186 m2.

Test: Adiabatic & Reradiating Surfaces - Question 10

What is the unit of coefficient of radiant heat transfer?

Detailed Solution: Question 10

Its value can be calculated from the heat flux equation for any configuration.

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