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Test: Types of Fluids - Mechanical Engineering MCQ


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15 Questions MCQ Test - Test: Types of Fluids

Test: Types of Fluids for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Types of Fluids questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Types of Fluids MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Types of Fluids below.
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Test: Types of Fluids - Question 1

The relation between shear stress Z and velocity gradient   of a fluid is given by ​ where A and n are constants. If n = 1, what type of fluid will it be?

Detailed Solution for Test: Types of Fluids - Question 1

Explanation: When n = 1, the relation reduces to Newton’s law of viscosity: z = A * , where A will represent the viscosity of the fluid. The fluid following this relation will be a Newtonian fluid as it is a linear relation. The equation given is of a straight line.

Test: Types of Fluids - Question 2

The relation between shear stress Z and velocity gradient   of a fluid is given by ​  where A and n are constants. What type of fluid will it be if n < 1 and n > 1 respectively?

Detailed Solution for Test: Types of Fluids - Question 2

Explanation: When n ≠ 1, the relation will be treated as Power law for Non-Newtonian fluids:
.
For n < 1, the rate of change of the shear stress decreases with the increase in the value of velocity gradient. Such fluids are called Pseudoplastics.

For n > 1, the rate of change of the shear stress increases with the increase in the value of velocity gradient. Such fluids are called Dilatants.

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Test: Types of Fluids - Question 3

For what value of flow behaviour index, does the consistency index has a dimension independent of time?

Detailed Solution for Test: Types of Fluids - Question 3

The relation between shear stress Z and velocity gradient The relation between shear stress Z & velocity gradient in figure of a fluid is given by The relation reduces to Newton’s law of viscosity where A represents viscosity of fluid
where A is the flow consistency index and n is the flow behaviour index.
The relation between shear stress Z & velocity gradient if A is flow consistency index
Thus [A] will be independent of time when n = 2.

Test: Types of Fluids - Question 4

The relation between shear stress Z and velocity gradient   of a fluid is given by ​  + B where A, n and B are constants.
Which of the following conditions will hold for a Bingham plastic?

Detailed Solution for Test: Types of Fluids - Question 4

Explanation: For Bingham Plastics, shear stress will not remain constant after an yield value of stress. Thus, A ≠ 0;B ≠ 0. After the yield value, the relation between the shear stress and velocity gradient will become linear. Thus, n = 1.

Test: Types of Fluids - Question 5

The relation between shear stress Z and velocity gradient   of a fluid is given by ​  + B where A, n and B are constants. Which of the following conditions will hold for a Rheopectic?

Detailed Solution for Test: Types of Fluids - Question 5

Explanation: For Rheopectics, shear stress will not remain constant after an yield value of stress. Thus, A ≠ 0; B ≠ 0. After the yield value, the rate of change of the shear stress increases with the increase in the value of velocity gradient. Thus, n > 1.

Test: Types of Fluids - Question 6

The above graph of viscosity vs time depicts which of the following fluids?

(Hint : This fluid is present in inks and paints)

Detailed Solution for Test: Types of Fluids - Question 6

Explanation: For Thixotropics,their viscosity is time dependent and decreases as time goes on.

Test: Types of Fluids - Question 7

The relation between shear stress Z and velocity gradient   of a fluid is given by ​ where A and n are constants. The graphs are drawn for three values of n. Which one will be the correct relationship between n1, n2 and n3?

Detailed Solution for Test: Types of Fluids - Question 7

Explanation:

  • The graph corresponding to n = n1 represents Pseudoplastics, for which the rate of change of the shear stress decreases with the increase in the value of velocity gradient.
  • The graph corresponding to n = n2 represents Newtonian fluids, for which shear stress changes linearly with the change in velocity gradient.
  • The graph corresponding to n = n3 represents Dilatents, for which the rate of change of the shear stress increases with the increase in the value of velocity gradient.
Test: Types of Fluids - Question 8

Which of the following is a shear-thinnning fluid?

Detailed Solution for Test: Types of Fluids - Question 8

Explanation: Shear-thinning fluids are those which gets strained easily at high values of shear stresses. The relation between shear stress Z and velocity gradient   of a shear-thinning fluid is given by , where A and n are constants and n < 1. This relation is followed by Pseudoplastics.

Test: Types of Fluids - Question 9

Which of the following is a shear-thickening fluid?

Detailed Solution for Test: Types of Fluids - Question 9

Explanation: Shear-thickening fluids are those for which it gets harger to strain it at high values of shear stresses. The relation between shear stress Z and velocity gradient  of a shear-thickening fluid is given by   where A and n are constants and n > 1. This relation is followed by Dilatants.

Test: Types of Fluids - Question 10

What will be the dimension of the flow consistency index for a fluid with a flow behaviour index of -1? 

Detailed Solution for Test: Types of Fluids - Question 10

Explanation: The relation between shear stress Z and velocity gradient  of a fluid is given by   where A is the flow consistency index and n is the flow behaviour index. If n = -1, A = Z * Unit of Z is N/m2 and  is s-1. Thus, the unit of A will be N/m2 s.

*Answer can only contain numeric values
Test: Types of Fluids - Question 11

An inverted U-tube manometer is used to measure the pressure difference between two pipes A and B, as shown in the figure. Pipe A is carrying oil (specific gravity = 0.8) and pipe B is carrying water. The densities of air and water are 1.16 kg/m3, respectively. The pressure difference between pipes A and B is kPa.

Acceleration due to gravity g = 10 m/s2.


Detailed Solution for Test: Types of Fluids - Question 11

Density of oil ρoil = 800 kg/m3
Density of water ρwater = 1000 kg/m3
Density of air ρair = 1.16 kg/m3
Acceleration due to gravity g = 10 m/s2

PA – ρoil g (0.2) – ρair g (0.08) + ρwater
g (0.38) = PB
∴ PB – PA = 2.199 kPa

Hence, the correct answer is –2.2 kPa.

*Answer can only contain numeric values
Test: Types of Fluids - Question 12

A spherical balloon with a diameter of 10 m, shown in the figure below is used for advertisements. The balloon is filled with helium (RHe = 2.08 kJ/kg⋅K) at ambient conditions of 15°C and 100 kPa. Assuming no disturbances due to wind, the maximum allowable weight (in Newton) of balloon material and rope required to avoid the fall of the balloon (Rair = 0.289 kJ/kg ⋅K) is _____


Detailed Solution for Test: Types of Fluids - Question 12

Density of helium

Under the equilibrium condition,
Buoyant force
= Weight of balloon + Weight of Helium
ρair  × (Volume of balloon) g
= Wballoon + ρHelium × (Vol. of balloon) g

Weight of balloon
= (ρair – ρHelium) × Vballoon × g

Test: Types of Fluids - Question 13

Refer to figure, the absolute pressure of gas A in the bulb is

Detailed Solution for Test: Types of Fluids - Question 13

Density of Hg = = ρ × Hg 13 6 10 kg/m 3 3 .
Density of water = = ρH20
1000 kg/m3

Pressure above the section (1)–(1) should be same

Hence, the correct option is (a).

Test: Types of Fluids - Question 14

If ‘P’ is the gauge pressure within a spherical droplet, then gauge pressure within a bubble of the same fluid and of same size will be

Detailed Solution for Test: Types of Fluids - Question 14

Gauge pressure inside the spherical droplet

Gauge pressure inside the bubble

where ‘d’ is the diameter of bubble and droplet
Pbubble = 2Pdroplet
Hence, the correct option is (d).

*Answer can only contain numeric values
Test: Types of Fluids - Question 15

A cube of side 100 mm is placed at the bottom of an empty container on one of its faces. The density of the material of the cube is 800 kg/m3. Liquid of density 1000 kg/m3 is now poured into the container. The minimum height to which the liquid needs to be poured into the container for the cube to just lift up is _____ mm.


Detailed Solution for Test: Types of Fluids - Question 15

Given that density of cube material δcube = 800 kg/m3

δwater = 1000 kg/m3

weight of cube = δcube × volume of cube × g

= 800 × 0.1 × 0.1 × 0.1 × g

= 0.8 gN

To just lift the cube weight of cube = bouyamey force = weight of liquid displaced

= liquid × volume of liquid × g

= 1000 × 0.1 × 0.1 × h × g

= 10 hg where h = height of water pound

By equating weight of cube = bouyamey force

0.8g = 10 hg

h = 0.8/10 = 0.08m  = 80mm

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