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Test: Fractionation Column Ponchon & Savarit Method - Chemical Engineering MCQ


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10 Questions MCQ Test - Test: Fractionation Column Ponchon & Savarit Method

Test: Fractionation Column Ponchon & Savarit Method for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Test: Fractionation Column Ponchon & Savarit Method questions and answers have been prepared according to the Chemical Engineering exam syllabus.The Test: Fractionation Column Ponchon & Savarit Method MCQs are made for Chemical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Fractionation Column Ponchon & Savarit Method below.
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Test: Fractionation Column Ponchon & Savarit Method - Question 1

 The Ponchon Savorit method is applicable for determining negligible heat loss.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 1

Explanation: As this method includes enthalpy concentration data it helps to determine the negligible heat loss.

Test: Fractionation Column Ponchon & Savarit Method - Question 2

 External reflux ratio is used for Ponchon Savorit method.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 2

Explanation: Here the reflux ratio is based on the flow rates of the final plates of the enriching section or stripping section; so internal reflux ratio comes to the part.

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Test: Fractionation Column Ponchon & Savarit Method - Question 3

Find the heat removed by the condenser if the net heat out of the condenser is 25000 J and the total moles are 25.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 3

Explanation: Heat removed by the condenser = net heat out/ net moles out
= 25000 J/ 25
= 1000.

Test: Fractionation Column Ponchon & Savarit Method - Question 4

From the enthalpy-concentration diagram find the location of heat removed by the condenser.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 4

Explanation: X is the heat removed by the condenser where the net heat removed by the net moles out can be determined.

Test: Fractionation Column Ponchon & Savarit Method - Question 5

Find the internal reflux ratio by analysing the below fractionator.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 5

Explanation: Internal reflux ratio = 50/40 = 1.25.

Test: Fractionation Column Ponchon & Savarit Method - Question 6

Estimate the heat removed by the condenser.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 6

Explanation: Heat removed by the condenser = Qc/D + Hd = 50/25 + 20 = 20 KJ/Kg.

Test: Fractionation Column Ponchon & Savarit Method - Question 7

 Find the distillate rate by analysing the fractionator given below.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 7

Explanation: We have to calculate from n th tray
L*HL + G* Hg = DQ
Q=(50*20 + 40*10)/20 = 30 KJ.

Test: Fractionation Column Ponchon & Savarit Method - Question 8

The fictitious stream is the difference in the flow rates of the nth tray.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 8

Explanation: Fictitious stream = Gn+1 – Ln (Represented by delta).

Test: Fractionation Column Ponchon & Savarit Method - Question 9

Ponchon Savorit method do not include enthalpy concentration diagram.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 9

Explanation: The heat losses or heat used by the condenser or reboiler determined only by enthalpy concentration data.

Test: Fractionation Column Ponchon & Savarit Method - Question 10

Find the flow rate of liquid entering into the enriching section if the internal reflux ratio is 1.5 times min. Given minimum reflux ratio is 0.95 and the gas flow rate is 35 mol/hr.

Detailed Solution for Test: Fractionation Column Ponchon & Savarit Method - Question 10

Explanation: Internal reflux ratio = Liquid flow rate/ gas flow rate ( in n th plate of section)
1.5 *0.95 = L/35
L= 49.87 mol/hr.

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