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Test: Eccentrically Loaded Riveted Joints - Mechanical Engineering MCQ


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9 Questions MCQ Test - Test: Eccentrically Loaded Riveted Joints

Test: Eccentrically Loaded Riveted Joints for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Eccentrically Loaded Riveted Joints questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Eccentrically Loaded Riveted Joints MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Eccentrically Loaded Riveted Joints below.
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Test: Eccentrically Loaded Riveted Joints - Question 1

 

A bracket is attached to a vertical wall by means of four rivets. Find the rivet which is under maximum stress.

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 1

Explanation: Primary Shear act vertically upward on all the rivets. Secondary shear is proportional to the distance from CG. Hence rivets 1 and 4 are under maximum stress.

Test: Eccentrically Loaded Riveted Joints - Question 2

 

Calculate the primary shear stress on each rivet if P=30kN and diameter of rivets is 15mm.

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 2

Explanation: τ₁=P/4A or 7500/A.

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Test: Eccentrically Loaded Riveted Joints - Question 3

 If secondary shear stress acting on any bolts is given by Cxr₁ where r₁ is the distance of bolt from CG, then find the value of C. Bolts are equidistant with spacing of 100mm. Force P=30kN.

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 3

Explanation: C=Pe/[r₁²+r₂²+r₃²+r₄²].

Test: Eccentrically Loaded Riveted Joints - Question 4

 Calculate the effective force in vector form to which rivet 2 is subjected. Bolts are separated by 100mm and force P=30kN.

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 4

Explanation: Primary force=7500j, Sec Force=Cx50(-i) where C=7

Test: Eccentrically Loaded Riveted Joints - Question 5

Calculate the effective force in vector form to which rivet 4 is subjected. Bolts are separated by 100mm and force P=30kN.

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 5

Explanation: Primary force=7500j, Sec Force=Cx100 i where C=72.

Test: Eccentrically Loaded Riveted Joints - Question 6

Calculate the diameter of the rivets if permissible shear stress is 60N/mm². Bolts are separated by 100mm and force P=30kN.

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 6

Explanation: Magnitude of force acting on Bolt 4 or Bolt 1=√7500²+7200² or 10396.6=πd²τ/4.

Test: Eccentrically Loaded Riveted Joints - Question 7

 Are the bolts 2 and 3 under same force?

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 7

Explanation: Primary shear force is same but secondary shear forces direction are different in the two bolts.

Test: Eccentrically Loaded Riveted Joints - Question 8

Are the bolts 2 and 3 subjected to same magnitude of force?

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 8

Explanation: Although the vectors are different for the forces on two bolts but their magnitudes are same.

Test: Eccentrically Loaded Riveted Joints - Question 9

Can we use the rivets of diameter 18mm in the following case if P=30kN and bolts are separated by 100mm each. Maximum permissible shear stress is 60N/mm².

Detailed Solution for Test: Eccentrically Loaded Riveted Joints - Question 9

Explanation: The minimum diameter required for the rivets is obtained 15mm. Any rivet greater than this diameter is safe to use.

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