Anodising - Metal & Non Metals, Chemistry CBSE Class 10 Video Lecture

hello friends this video on metal and
nonmetal part 6 is got you by exam
Viacom no more fear from exam before
watching this video please make sure
that you have watched part 1 to part 5
as this let's study the term analyzing
first what is an amazing as I told that
is the process of forming a thick layer
of oxides for aluminium it's not to only
volume here for any metal you can use
this process but generally square
aluminum and with this is Al 2 O 3 layer
is created and this is resistant to
Carson right so signalization to
corrosion it is desired that before I
when selling this aluminum utensils we
create this al2o3 layer that means that
we are making the aluminum utensils more
resistant to Colton so how do we do this
how do we improve the resistance by
making a thick layer of oxide so the
question is how do we make a thick layer
of oxide right to do this we use this in
electrolysis process so here what we do
is this is a clean aluminum that is a
anode the false tip and today is mega
any Kathryn doesn't matter and we put
some acid in this and this diluted acid
may be Sen against in dilute HCl so what
happens is since it is dilute I see
little of water in this so what will
happen is this guy will give a positive
this guy will give me negative light mmm
so this electrons will come from here
right electrons will come from here
electrons will be somewhere here because
a negative thing so the level of
electrons here correct that's how it is
now this water will break into hydrogen
plus so hydrogen plus one and oxygen
minus 2 then we do ads in plus one for
every oxy
it will break like this what will break
like this right iced water will break
into this hydrogen hydrogen ions and
oxygen eyes so now this guy
since it is positive oxygen will flow
this side and hydrogen will flow this
side correctly I am Telling this is
because it is negative my ox hydrogen
since it is a positive charge it will
flow towards my negative thing right
that is my cathode oxygen will go
towards us a node and hydrogen will go
towards this cathode so what happens is
near the anode we have huge
concentration of oxygen so we have more
oxygens if you see we have more oxygens
correct so if you see we have more and
more oxygens here correct since we have
more and more oxygens here this guy
oxygen will react with the algorithm to
give no.3 correct and since the oxygen
concentration is more it gives a thicker
protective layer sometimes we have what
we do in this hydrochloric acid we put
some color so we put some dye now check
that what happens is the layer that is
formed this layer it gets a color also
because the oxygen molecules which is
even in the reaction happens I mean it
moves it moves with a color also right
so that time this illiberal it's a color
also thin color so it looks good so this
is also used sometimes because even you
on don't know make it look like green
finger blue we can put the current die
we die in the SCL soulish in the dilute
HCl solution and that color also becomes
part of this mean because a layer of
al2o3 is created so at that time in the
al2o3 3 hit it it is in this color
alright because as part of the acid so
hope you understand this process in this
I know do you have cathode so in this is
positive so hydrogen and water breaks
into hydrogen and oxygen ions is
positive the oxygen ion is attracted
toward this hydrogen ions accredit
toward this sphere and bhagavad cathode
we are by only about anode so in the
animal diffusion of oxygen ions there
that means oxidation can happen and this
a two or three is created so let's do
recap on what I've learned till now we
have learned that sodium is a most
reactive metal on the reaction of Magnus
is less vigorous than sodium right but
there's not as reactive as sodium and
but the burning of oxygen didn't help us
to decide the reactivity of zinc iron
copper or lead right but till no me no
sodium is a motion actor magnesium is
less in the middle and then we have
these a bunch of elements make this
actually so to put we can say that we
have this sodium - M is the first then
you have manganese and all in the second
and then you have Jane iron copper let
in third and then you have gold silver
right so well we have this the activity
is known but we do further find out the
reactive between these in these so the
oxygen didn't help us thank you
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