Types of Molecular orbital - Chemical Bonding Video Lecture - Inorganic

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bonding part will nine is brought to you
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before watching the video please make
sure that you have watched part 1 to
part weary 8 so the molecule orbital as
I told of a diet atomic Monica diatomic
molecule we will be studying not can we
have Sigma Pi and Delta etcetera but
we'll be focusing only on Sigma and PI
molecule already Sigma as I told the
names I guess is symmetrical is
cylindrical II symmetrical around the
axis where the PI molecular orbitals are
not symmetrical correct this example so
this is my two atoms atom a1 and a2
in this case the Sigma is possible for
this as I told this is my s is my S
orbital there is a possible of
possibility of getting s molecular
orbital from this coming
esque atomic orbital so this is my Sigma
this is my Sigma 1 s this Sigma 1 s star
because antibonding
so if you see from p also i can either
toward right can have this Sigma because
this big P and P are head-on and they
have the same molecular axis right so we
can have a sigma here Sigma 2 P and
Sigma 2 P star here Modelling and D
morning
similarly as I told the other 2p this
one and this one these two P they'll
have a PI bonding PI molecular orbital
so if you see this 2p they combine to
form pi bonding molecular orbital and pi
antibonding model already correct so
let's see the energy level diagram for
various molecular orbital so the
exception here for oxygen neon and
chlorine the energy diagram is this and
for other molecules the energy eigen is
this if we compare this since for mine
if you see the differences till from
Sigma is Sigma star and Sigma us Sigma
star to s is all same but the only
difference is this in case of oxygen
neon and fluorine my sigma 2pz is lower
than pipe you can say that Sigma 2p is
lower than PI 2p if you see here also my
first Sigma 2 becomes and then PI Q
becomes but in case of other my pipe to
become first and then Sigma to become
rest other things are all same if you
notice the difference from here to here
1s is all same the only differences in
case of oxygen neon and chlorine my
Sigma 2p comes first and then PI 2
becomes right in other case my pipe
would become first and then symbol let's
draw the electronic condition for 4 on
so now if you see in this borough on we
have boron molecule would have 10
electrons 8 5 into 10 liquids
correct so this theory says that
molecular orbital Theory you consider as
a molecule orbital and let's try to fill
the electrons here so 10 my 1s so if you
write the electronic invasion of boron
it is 1s2 2s2 and then 2 P 1 right this
is the electronic condition of boron
atom or molecule so one has to let me
put two electrons here and then two ends
to let me put this on here and 2p one is
labelled okay see this is the order we
had for boron we have Sigma I think we
have Sigma 1 X Sigma 1 star and then we
have seen my 2 s 2 s are like that
similarly here also will have this boron
- so this guy also will have seen
balance correct because this V 2 bar on
the side or on this side so four
electrons will have to fill here again
four electrons will have to fill here
like this now we have two electrons
right so you go first here and then
first here obviously the same principle
first one electrons are filled and then
only second electrons will be filled
correct so the electronic configuration
for this will be what so it will be if
you see it will be Sigma 1 s 2 then we
have Sigma star 1s - this guy they will
have Sigma 2 s 2 this guy then we will
have Sigma star us - let me laughs PI to
be
you can say that 2 P 2 against M PI 2 P
right 1 inch or if you say that PI 2 px
1 then you can say PI 2 P Y both are
same actually doesn't matter all right
now if you see this has to be paramagnet
okay we'll discuss later this is my
network evaluation let's take an example
carbon so carbon is a c2 his CT molecule
is 2 carbon atom 1 carbon atom is I told
number 6 1s2 2s2 2p2 so let's put here 1
s 2 ways to and to Peter similarly here
also 1 s 2 2 s 2 and 2 P let's fill it
down here for electrons here so they
fill the for electrons for a trans here
would spin the kool-aid transfer for
later on zealous spirit 1 2 3 and all
right let's foil fill the lowest energy
in this case so what would be the
electronic ammunition 1 s 2 Sigma 1 s 2
Sigma star Wollaston Sigma 2 s 2 Sigma
star to estimate then we have pi 2py to
then pi to be xed ok that will make
electronic configuration be disabled the
only thing is you should know it's order
you should know the diagram of this and
then this is pretty simple you have 1 as
the yeah antibonding one is Sigma 2 s NT
morning Sigma 2 s PI 2 P Sigma 2 P and
so on let's write the electronic
completion of my person
molecules mitral more example but two
nitrogen atom and electronic
complication of Martin and nitrogen is
1s2 2s2 2p3 correct so let's draw this
will have one s two electrons here - s -
well it was here to be three million
transfer slowly heroes will fill the
same way to s 2 + 2 T 3 all right now
let's collect boy electrons fill this up
again for electrons
who is Sigma 2 s star W has 6 electrons
first we'll go here second before here
third will go where holes will go here
fifth will go here and six then go ahead
correct
mommy get right the electronic image
please
so this is Sigma 1s Sigma star 1s - done
swimmer us 2 Sigma 2 s 2 then Phi P Y
you buy to be X 2 then we have Sigma to
be Z DZ let's write the electronic
efficient oxygen so the oxygen we know
the rule is different so here my Sigma
to become first and then PI 2 P you see
Sigma comes from Cordoba so we'll draw
we will take this structure so oxygen is
more like this is a liquid to oxygen
atom and oxygen electronic indigenous is
1s2 2s2 2p4 so let's put electrons here
1s you have to put two electrons 2 s
electron and 2p for electron one two
three so we're only here also let's put
that one s 2 electron 2 s electron and
to be for electron 1 2 3 & 4
let's find this for electron let's play
this one two three four
you are these two atomic orbital to
frame molecular orbital with four
electron hole film four electrons now
you are eight electrons right from P so
let's fill eight one two three four five
six seven and correct so the electronic
contribution will be Sigma 1 s to Sigma
star 1s 2 then Sigma 2 s 2 Sigma star 2
s 2 then we have Sigma P Z 2 then we
have pi 2py
2 by 2 px 2 and then you have
anti-bonding right pi star 2py one and
then pi star 2px this is the electronic
configuration and this doing more
example so that you can come you get
comfort in the electronic configuration
once we know how to write electronic
conduction will tell you how to find the
different properties of molecule using
the electronic configuration let us take
the fluorine example fluorine also
similar to oxygen here my EP Y comes
before Sigma 2 people right so fluorine
also is atomism we got two fluorine
molecules so one foreign molecule and
the mechanician be 1s2 2s2 2p5 so let us
do that
1s2 2s2 2p5 one there also 1s2 2s2 2p5
let's filler four electrons that is
simple 4 electrons done now we have five
plus eight electrons let's fill it 1 2 3
4 5 6
eight-nine really electronic computation
of correct you want again right oh
that's okay minister right let's take
the example of nyan nyan also has the
same as oxygen to be comes before this
one Pi Sigma to be come before PI 2 P so
jnana is nothing but 2 neon molecule
tuning on atom for neon the electronic
conviction is 1s2 2s2 2p6 so let's fill
this 1s2 2s2 basis
1 2 3 4 5 6 it also 1s2 2s2 2p6 1 2 3 4
5 6
margit for electrons when 4 electrons
and 10 electrons 5 plus 5
sorry 12 6 plus 6 2 electrons 1 2 3 4 5
6 7 8 9 10 11
J so all our friends we can just write
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