Electronics and Communication Engineering (ECE) Exam > Electronics and Communication Engineering (ECE) Videos > MIPS Assembly Programming Simplified > MIPS Tutorial 38 - 2D Array Implementation
MIPS Tutorial 38 - 2D Array Implementation Video Lecture | MIPS Assembly Programming Simplified - Electronics and Communication Engineering (ECE)
FAQs on MIPS Tutorial 38 - 2D Array Implementation Video Lecture - MIPS Assembly Programming Simplified - Electronics and Communication Engineering (ECE)
| 1. How do I declare a 2D array in MIPS? |  |
Ans. To declare a 2D array in MIPS, you need to first reserve space for the array using the `.data` section and then initialize the array elements using the `.word` directive. Here's an example:
```
.data
array: .word 1, 2, 3, 4
.word 5, 6, 7, 8
.text
main:
# Accessing array elements
la $t0, array
lw $t1, 0($t0) # Accessing element at row 0, column 0
lw $t2, 4($t0) # Accessing element at row 0, column 1
lw $t3, 8($t0) # Accessing element at row 1, column 0
lw $t4, 12($t0) # Accessing element at row 1, column 1
```
In this example, the 2D array "array" has two rows and four columns.
| 2. How do I access a specific element in a 2D array in MIPS? | |
Ans. To access a specific element in a 2D array in MIPS, you need to calculate the offset of the element based on its row and column indexes, and then load the value from the memory using the `lw` instruction. Here's an example:
```
.data
array: .word 1, 2, 3, 4
.word 5, 6, 7, 8
.text
main:
la $t0, array
li $t1, 0 # Row index
li $t2, 2 # Column index
# Calculating the offset
mul $t3, $t1, 4 # Multiply row index by 4 (4 bytes per element)
add $t3, $t3, $t2 # Add column index to the offset
add $t4, $t0, $t3 # Add offset to the base address
# Accessing the element at row 0, column 2
lw $t5, 0($t4)
```
In this example, the element at row 0, column 2 is accessed by calculating the offset as (row index * 4) + column index.
| 3. How do I initialize a 2D array in MIPS? | |
Ans. To initialize a 2D array in MIPS, you can use the `.word` directive to assign values to the array elements in the `.data` section. Here's an example:
```
.data
array: .word 1, 2, 3, 4
.word 5, 6, 7, 8
.text
main:
la $t0, array
li $t1, 0 # Row index
li $t2, 2 # Column index
# Calculating the offset
mul $t3, $t1, 4 # Multiply row index by 4 (4 bytes per element)
add $t3, $t3, $t2 # Add column index to the offset
add $t4, $t0, $t3 # Add offset to the base address
# Accessing and printing the element at row 0, column 2
lw $t5, 0($t4)
li $v0, 1
move $a0, $t5
syscall
```
In this example, the 2D array "array" is already initialized with values 1, 2, 3, 4 in the first row and 5, 6, 7, 8 in the second row.
| 4. Can I have different data types in a 2D array in MIPS? | |
Ans. No, in MIPS, a 2D array can only have a single data type. MIPS is a low-level assembly language and does not provide built-in support for data structures with different types. If you need to store different data types in a 2D structure, you can either use separate 2D arrays for each data type or use a struct to represent each element in the array.
| 5. How do I iterate over a 2D array in MIPS? | |
Ans. To iterate over a 2D array in MIPS, you can use nested loops to traverse each row and column of the array. Here's an example:
```
.data
array: .word 1, 2, 3, 4
.word 5, 6, 7, 8
.text
main:
la $t0, array
li $t1, 0 # Row index
li $t2, 0 # Column index
outer_loop:
# Inner loop for columns
move $t2, $zero # Reset column index
inner_loop:
# Calculating the offset
mul $t3, $t1, 4 # Multiply row index by 4 (4 bytes per element)
add $t3, $t3, $t2 # Add column index to the offset
add $t4, $t0, $t3 # Add offset to the base address
# Accessing and printing the current element
lw $t5, 0($t4)
li $v0, 1
move $a0, $t5
syscall
addi $t2, $t2, 1 # Increment column index
blt $t2, 4, inner_loop # Check if column index is less than 4
addi $t1, $t1, 1 # Increment row index
blt $t1, 2, outer_loop # Check if row index is less than 2
```
In this example, the nested loops iterate over each row and column of the 2D array "array" and print the corresponding element.
Text Transcript from Video
hello guys this is a male Peralta and
I'm glad to be back
remember that last time I showed you the
theory about how to actually implement a
two-dimensional array but now it's time
to let two dimensional array because now
that you have the basic idea now we are
going we're going to apply that idea
we're going to write the two-dimensional
array so that you understand how it is
done so I'm going to open Mars and in
this program that I'm going to write
I'm gonna write an array actually makes
no ray and we're going to add all the
elements in the diagonal so it's going
to be a program that is going to allow
you to actually display the sum of all
the elements in the diagonal so first
I'm going to click on file then new I'm
going to save this to my desktop I'm
going to call this MD array for
multi-dimensional array so as usual I'm
going to start with the data section and
here I'm going to have my
multi-dimensional array I'm going to
call it MD array the type of elements is
going to be integer so I'm going to say
that word and it's going to have two
five in the first row that word three
seven on the second row so I'm going to
say that I have a multi-dimensional
array the name of the array is MD array
if the type is integer the first row is
2 5 the second row is 3 7 so this is a
square matrix and by square matrix I
mean that it has the same number of rows
and this is not the same number of
columns so it has two rows one and two
and it has two columns column 1 column 2
and then why am i doing it this way I'm
doing it this way because I want to
simplify my code that way it's going to
be easier for you to understand and once
you understand this way you can actually
change it to any way to a different way
you can actually have a rectangular
matrix if you don't want to have a
square matrix so now I'm going to have
another variable in random access memory
and this is going to be the size so
sighs it's gonna be an integer so
because I have two columns and two rows
the size is going to be two and this is
one simplification because the number of
columns and the number of rows is the
same I only need to have one variable
for the size it's a two by two matrix
and now I'm going to have defining a
constant before I never showed you how
to define a constant so this is the way
we do it we say dot e QV that's for
constant so it's a substitute second
operand for first the first operand
symbol second operand is expression it's
like pounding fine if you know c c or
c++ so that eqv the name of my constant
is going to be data size so because I'm
dealing with integers this the data size
is four if I was dealing with doubles
the data size would be eight but in this
case is 4 this way my program is going
to be easier to maintain because if I
need to change the program from integer
to double I only have to change this if
I want to do it later I don't have to go
I don't have to go through my code and
change it and change all the instances I
only have to change this value here okay
so this is all the data that I need now
I'm going to go to the text section
and this is for the code so now I'm
going to have my main function in my
main function I'm going to have the
first thing I'm going to do is that I
want to have the base address of my
multi-dimensional array so I'm going to
say load address dollar a 0 comma MD
array so now register a 0 has the base
address of my multi-dimensional array
but I also want to have this size which
is 2 in a register so I'm going to say
load word dollar a 1 coma
sighs so now a 0 has the base address
and a 1 has the size so I'm going to
call a function I have a ring this
function yet but I will write it later
so the function is called some diagonal
because this function is going to sum
it's going to add up all the elements in
the diagonal in this case I have 2 and 7
this is the diagonal so 2 plus 7 is 9 so
when I say jump and Link some diagonal
and the argument notice that these are
the arguments it takes two arguments
this function it takes the base address
of the multi-dimensional array and this
is in a 0 and the size which is in a 1
remember that the 8 registers are used
for 4 parameters for arguments and once
I call the function the function is
going to return the sum of the diagonal
elements in register v-0 so I'm going to
move to register a 0 the value in
register v-0 so this song is going to be
stored in v-0 when every time from this
function this is going to have 2 plus 7
which is 9 this is going to have 9
and I want to put it in a zero so now a
zero has nine but why am I putting that
in a zero well because I want to display
the value to the screen so now I can say
load immediate dollar sign V 0 comma 1
and this is to display an integer to the
screen what integer I want to display
the integer in a zero because this by
convention we pass the the argument to a
zero and then I have to say Cisco and we
done the system is going to display the
integer in a zero in the argument is
zero to the screen which is going to be
the sum 2 plus 7 is 9
ok and then I'm going to end the program
in Maine so let say loading media does
enter 0 comma 10 Cisco okay so this is
the main procedure this is my data and
now I have to implement the most
important part of this tutorial which is
the function some diagonal remember that
some diagonal takes these two parameters
a 0 the base address and a 1 the size so
for this tutorial we're going to use the
row major representation this is the row
major representation and remember in the
last tutorial I said that row major is
the following we go row by row and we
other rows in contiguous memory so Row 1
first then Row 2 and then Row 3 so we
have to use this formula so we're going
to implement this formula to get all the
elements in the diagonal so I'm going to
say some diagonal
that's the name of the function so first
I'm going to say load immediate dollar
sign this zero comma zero because I'm
going to use v-0 to return the sum
remember that this zero has the son v-0
has the sum
okay and I'm going to say load immediate
the low sign T 0 comma 0 because I'm
going to use T 0 at the index
ok so now I'm going to say some loop
this label it's going to allow me to
have a loop it's going to add all the
elements in the diagonal so first of all
I'm going to say multiply double time T
one dollar sign T zero dollar sign a one
so what I'm doing here is the following
I'm multiplying T 0 by a 1 and the value
is going to be stored in T 1 so I'm
saying T 1 gets the value of Rho index
times the number of columns so notice
that I'm applying the formula from here
from Romain to representation so row
index times the number of columns so T 0
is the index initially 0 the first
iteration is going to be 0 that means
then it's going to be 1 so row index
which is p 0 multiplied by the number of
columns what is the number of columns
well it's right here remember that the
number of columns is the size which is 2
we have 2 columns now we need to
continue implementing this formula so
now that I have row index times column
size I need to add the column index so
I'm going to say add dollar T $1 T $1 T
0
so what I'm doing is that to all this
I'm adding the column index and realize
that the row index is the same as the
column index why because I'm working
only with the diagonal so if I go back
here I show you this we're going to be
adding the diagonal elements so the row
index is zero the column index is zero
the row index is 1 the column index is 1
and so on so it's a simplification
because we're only working with the
diagonal the row index is going to be
the same as the column index or it's
going to be the same as the size in my
program here so now I have that t1 is
equal to the row index times the number
of columns plus the column index so I
have done this part of the formula so
now I have to multiply all these by the
data size so I'm going to say multiply
store the value T $1 t1 I'm going to use
my constant which is the data size so
now t1 has the value row index times
column size plus column index and all
that multiplied by the data size
because the data size is 4 because I'm
working with integers here so I have all
these already these formula all the way
to here now I need to add the base
address so I'm going to say add dollar T
$1 T 1 dollar a 0 so what I'm doing here
is I'm adding the base address so
remember that in the data section I mean
we have the base address is MD array so
in Maine we are putting the base address
in register a 0 so load address a 0
comma MD array so we are adding the base
address and so T 1 has the address now
after all this calculation has been done
now T 1 has the location in random
access memory for the element that I'm
looking for so the first iteration T 0
is 0 so the first iteration after all
this calculation has been done T 1 has
the address of the first element which
in this case is going to be this element
0 0 so all these the location is here so
now I can get that value I'm going to
say load word in register dollar T 2
parenthesis dollar T 1 so
I am getting the element in the first
position and I'm putting that element in
register t2 so this element I'm getting
the element from random access memory
and I'm putting that element in register
t2 and now I want to add it to register
to the sum so a dollar v-0 $2 be zero
comma dollar t2 so this is equivalent to
saying that sum is a value of sum plus
MD array so I so I because the the row
index is the same as the column index so
each iteration I'm going to perform this
calculation to get the corresponding
element in the badge agonal then I'm
going to get the element from random
access memory and then I'm gonna I'm
gonna this element from random access
memory I'm going to add to the sum and
I'm going to do that every iteration in
the loop so now I need to increment the
loop counter or the loop index so when I
say our immediate dollar t0 dollar T 0
comma 1 and this is equivalent to saying
I the value of I plus 1 because remember
that t0 is the index so I'm incrementing
the index every iteration and then I'm
going to write my loop condition I'm
going to say branch is less than dollar
t0 dollar a1 some look
so if I'm saying that if I is less than
the size loop again so it's going to if
the index is less than the size is going
to go back to the loop
so let me write a comment here to make
it clearer so if I is less than the size
then loop again and this loop right here
is going to go through the array through
the multi-dimensional array and it's
going to add it's going to add up all
the elements in the diagonal so in this
case it's going to start with ku and
then it's going to go to seven and it's
going to say 2 plus 7 is 9 and then
knowing it's going to be stored in v-0
so we just need to return from the
function so we say jump register double
sign RA and that's it now I'm going to
test it I'm going to say I'm going to
symbol so I have a little air oh let me
see what the error is
okay right here line 25 so multiply
dollar T $1 to $0 a 1 let me fix it up a
little bit
save
so t1 t 0 a 1
let me try this let me check mu L oh
yeah actually I made a I made a mistake
here I'm using mu P mu L all right save
clear wrong assemble and as you can see
9 9 is the result 2 plus 7 is 9 and it's
right here but now what if I want to
make this a 3 by 3 array well it's
pretty easy I'm going to add more
elements I'm gonna say 7 now I'm going
to say 8 1 say 10 one more row I'm going
to add 1 of 4 and I'm gonna say armed 11
and now this is no longer a 2 by 2
multi-dimensional array this is a 3 by 3
multi-dimensional array and the size is
peeled for because we're working with
integers but now if we execute this
program it's going to go through the
diagonal so let's say 2 plus 7 is 9 and
9 plus 11 is 20 so we should see 20 so
save wrong a symbol and execute voila 20
right there so as you can see this is
working perfectly we have a
multi-dimensional array and we have a
constant for the size of the element and
this function is going to add up all the
all the elements in the diagonal and
notice that we only need one loop
because we are only going through the
diagonal elements so thank you for
watching please like this video please
subscribe to
channel and I hope to see you soon see
you next time
I'm glad to be back
remember that last time I showed you the
theory about how to actually implement a
two-dimensional array but now it's time
to let two dimensional array because now
that you have the basic idea now we are
going we're going to apply that idea
we're going to write the two-dimensional
array so that you understand how it is
done so I'm going to open Mars and in
this program that I'm going to write
I'm gonna write an array actually makes
no ray and we're going to add all the
elements in the diagonal so it's going
to be a program that is going to allow
you to actually display the sum of all
the elements in the diagonal so first
I'm going to click on file then new I'm
going to save this to my desktop I'm
going to call this MD array for
multi-dimensional array so as usual I'm
going to start with the data section and
here I'm going to have my
multi-dimensional array I'm going to
call it MD array the type of elements is
going to be integer so I'm going to say
that word and it's going to have two
five in the first row that word three
seven on the second row so I'm going to
say that I have a multi-dimensional
array the name of the array is MD array
if the type is integer the first row is
2 5 the second row is 3 7 so this is a
square matrix and by square matrix I
mean that it has the same number of rows
and this is not the same number of
columns so it has two rows one and two
and it has two columns column 1 column 2
and then why am i doing it this way I'm
doing it this way because I want to
simplify my code that way it's going to
be easier for you to understand and once
you understand this way you can actually
change it to any way to a different way
you can actually have a rectangular
matrix if you don't want to have a
square matrix so now I'm going to have
another variable in random access memory
and this is going to be the size so
sighs it's gonna be an integer so
because I have two columns and two rows
the size is going to be two and this is
one simplification because the number of
columns and the number of rows is the
same I only need to have one variable
for the size it's a two by two matrix
and now I'm going to have defining a
constant before I never showed you how
to define a constant so this is the way
we do it we say dot e QV that's for
constant so it's a substitute second
operand for first the first operand
symbol second operand is expression it's
like pounding fine if you know c c or
c++ so that eqv the name of my constant
is going to be data size so because I'm
dealing with integers this the data size
is four if I was dealing with doubles
the data size would be eight but in this
case is 4 this way my program is going
to be easier to maintain because if I
need to change the program from integer
to double I only have to change this if
I want to do it later I don't have to go
I don't have to go through my code and
change it and change all the instances I
only have to change this value here okay
so this is all the data that I need now
I'm going to go to the text section
and this is for the code so now I'm
going to have my main function in my
main function I'm going to have the
first thing I'm going to do is that I
want to have the base address of my
multi-dimensional array so I'm going to
say load address dollar a 0 comma MD
array so now register a 0 has the base
address of my multi-dimensional array
but I also want to have this size which
is 2 in a register so I'm going to say
load word dollar a 1 coma
sighs so now a 0 has the base address
and a 1 has the size so I'm going to
call a function I have a ring this
function yet but I will write it later
so the function is called some diagonal
because this function is going to sum
it's going to add up all the elements in
the diagonal in this case I have 2 and 7
this is the diagonal so 2 plus 7 is 9 so
when I say jump and Link some diagonal
and the argument notice that these are
the arguments it takes two arguments
this function it takes the base address
of the multi-dimensional array and this
is in a 0 and the size which is in a 1
remember that the 8 registers are used
for 4 parameters for arguments and once
I call the function the function is
going to return the sum of the diagonal
elements in register v-0 so I'm going to
move to register a 0 the value in
register v-0 so this song is going to be
stored in v-0 when every time from this
function this is going to have 2 plus 7
which is 9 this is going to have 9
and I want to put it in a zero so now a
zero has nine but why am I putting that
in a zero well because I want to display
the value to the screen so now I can say
load immediate dollar sign V 0 comma 1
and this is to display an integer to the
screen what integer I want to display
the integer in a zero because this by
convention we pass the the argument to a
zero and then I have to say Cisco and we
done the system is going to display the
integer in a zero in the argument is
zero to the screen which is going to be
the sum 2 plus 7 is 9
ok and then I'm going to end the program
in Maine so let say loading media does
enter 0 comma 10 Cisco okay so this is
the main procedure this is my data and
now I have to implement the most
important part of this tutorial which is
the function some diagonal remember that
some diagonal takes these two parameters
a 0 the base address and a 1 the size so
for this tutorial we're going to use the
row major representation this is the row
major representation and remember in the
last tutorial I said that row major is
the following we go row by row and we
other rows in contiguous memory so Row 1
first then Row 2 and then Row 3 so we
have to use this formula so we're going
to implement this formula to get all the
elements in the diagonal so I'm going to
say some diagonal
that's the name of the function so first
I'm going to say load immediate dollar
sign this zero comma zero because I'm
going to use v-0 to return the sum
remember that this zero has the son v-0
has the sum
okay and I'm going to say load immediate
the low sign T 0 comma 0 because I'm
going to use T 0 at the index
ok so now I'm going to say some loop
this label it's going to allow me to
have a loop it's going to add all the
elements in the diagonal so first of all
I'm going to say multiply double time T
one dollar sign T zero dollar sign a one
so what I'm doing here is the following
I'm multiplying T 0 by a 1 and the value
is going to be stored in T 1 so I'm
saying T 1 gets the value of Rho index
times the number of columns so notice
that I'm applying the formula from here
from Romain to representation so row
index times the number of columns so T 0
is the index initially 0 the first
iteration is going to be 0 that means
then it's going to be 1 so row index
which is p 0 multiplied by the number of
columns what is the number of columns
well it's right here remember that the
number of columns is the size which is 2
we have 2 columns now we need to
continue implementing this formula so
now that I have row index times column
size I need to add the column index so
I'm going to say add dollar T $1 T $1 T
0
so what I'm doing is that to all this
I'm adding the column index and realize
that the row index is the same as the
column index why because I'm working
only with the diagonal so if I go back
here I show you this we're going to be
adding the diagonal elements so the row
index is zero the column index is zero
the row index is 1 the column index is 1
and so on so it's a simplification
because we're only working with the
diagonal the row index is going to be
the same as the column index or it's
going to be the same as the size in my
program here so now I have that t1 is
equal to the row index times the number
of columns plus the column index so I
have done this part of the formula so
now I have to multiply all these by the
data size so I'm going to say multiply
store the value T $1 t1 I'm going to use
my constant which is the data size so
now t1 has the value row index times
column size plus column index and all
that multiplied by the data size
because the data size is 4 because I'm
working with integers here so I have all
these already these formula all the way
to here now I need to add the base
address so I'm going to say add dollar T
$1 T 1 dollar a 0 so what I'm doing here
is I'm adding the base address so
remember that in the data section I mean
we have the base address is MD array so
in Maine we are putting the base address
in register a 0 so load address a 0
comma MD array so we are adding the base
address and so T 1 has the address now
after all this calculation has been done
now T 1 has the location in random
access memory for the element that I'm
looking for so the first iteration T 0
is 0 so the first iteration after all
this calculation has been done T 1 has
the address of the first element which
in this case is going to be this element
0 0 so all these the location is here so
now I can get that value I'm going to
say load word in register dollar T 2
parenthesis dollar T 1 so
I am getting the element in the first
position and I'm putting that element in
register t2 so this element I'm getting
the element from random access memory
and I'm putting that element in register
t2 and now I want to add it to register
to the sum so a dollar v-0 $2 be zero
comma dollar t2 so this is equivalent to
saying that sum is a value of sum plus
MD array so I so I because the the row
index is the same as the column index so
each iteration I'm going to perform this
calculation to get the corresponding
element in the badge agonal then I'm
going to get the element from random
access memory and then I'm gonna I'm
gonna this element from random access
memory I'm going to add to the sum and
I'm going to do that every iteration in
the loop so now I need to increment the
loop counter or the loop index so when I
say our immediate dollar t0 dollar T 0
comma 1 and this is equivalent to saying
I the value of I plus 1 because remember
that t0 is the index so I'm incrementing
the index every iteration and then I'm
going to write my loop condition I'm
going to say branch is less than dollar
t0 dollar a1 some look
so if I'm saying that if I is less than
the size loop again so it's going to if
the index is less than the size is going
to go back to the loop
so let me write a comment here to make
it clearer so if I is less than the size
then loop again and this loop right here
is going to go through the array through
the multi-dimensional array and it's
going to add it's going to add up all
the elements in the diagonal so in this
case it's going to start with ku and
then it's going to go to seven and it's
going to say 2 plus 7 is 9 and then
knowing it's going to be stored in v-0
so we just need to return from the
function so we say jump register double
sign RA and that's it now I'm going to
test it I'm going to say I'm going to
symbol so I have a little air oh let me
see what the error is
okay right here line 25 so multiply
dollar T $1 to $0 a 1 let me fix it up a
little bit
save
so t1 t 0 a 1
let me try this let me check mu L oh
yeah actually I made a I made a mistake
here I'm using mu P mu L all right save
clear wrong assemble and as you can see
9 9 is the result 2 plus 7 is 9 and it's
right here but now what if I want to
make this a 3 by 3 array well it's
pretty easy I'm going to add more
elements I'm gonna say 7 now I'm going
to say 8 1 say 10 one more row I'm going
to add 1 of 4 and I'm gonna say armed 11
and now this is no longer a 2 by 2
multi-dimensional array this is a 3 by 3
multi-dimensional array and the size is
peeled for because we're working with
integers but now if we execute this
program it's going to go through the
diagonal so let's say 2 plus 7 is 9 and
9 plus 11 is 20 so we should see 20 so
save wrong a symbol and execute voila 20
right there so as you can see this is
working perfectly we have a
multi-dimensional array and we have a
constant for the size of the element and
this function is going to add up all the
all the elements in the diagonal and
notice that we only need one loop
because we are only going through the
diagonal elements so thank you for
watching please like this video please
subscribe to
channel and I hope to see you soon see
you next time
About this Video
Feb 19, 2025
Last updated
Video Description: MIPS Tutorial 38 - 2D Array Implementation for Electronics and Communication Engineering (ECE) 2025 is part of MIPS Assembly Programming Simplified preparation.
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