Collision in 2 dimensions - Work, Energy & Power Video Lecture - Class 11

please make sure that you have watched
all the videos from bat 1 to power 22
before going ahead with part 23 now let
us study coalition in two dimension to
dimension means after collision the two
objects can move in not only in a
straight line but in a plane they can
move along x axis or y axis let us
suppose these are the balls Boyle vine
moves collides with the second ball and
then they both disperse in different
direction that means initially the aim
along x axis then they dispersed in this
way one Bend along this direction and
the other went along this direction so
here now in this case the collision is
taking place in two dimension because x
axis as well as y axis comes into play
so in this case let us suppose this is
my x axis and this is y axis fine now
let us suppose the two objects initial
and final again here also we will do the
same thing before and after collision
before collision m1 was moving with
velocity U 1 and M 2 was moving with
zero velocity because m2 was at rest
after collision m1 is moving with
velocity v1 m2 is moving with some
velocity say V 2 now let us say that m1
is moving making some angle theta1 with
the x axis similarly M 2 is moving
making some angle theta2 with the x axis
in this case since x axis and y axis
came into picture what we will do when
we write equation for momentum
conservation we have to write two
equation for two different axis first we
write the momentum conservation along x
axis so along x axis what would be the
total initial momentum this must be m1
v1 total linear momentum after collision
this will be for first object M
and v1 cos theta1 because it is moving
along this axis this is the direction of
v1
so along x axis it would be v1 cos theta
1 so it will be m1 v1 cos theta1 plus m2
v2 cos theta2
so this will be the first equation along
x axis similarly we will write the
momentum conservation along y axis so
along y axis what would be the initial
momentum initial momentum would be 0
because initially the object is moving
only along the x axis so initial
momentum along y axis would be 0 final
momentum along y axis would be m1 v1
sine theta 1 because this is v1 cos
theta 1 so this would be v1 sine theta 1
right similarly for this one for this V
2 this would be v2 cos theta 2 and this
would be v2 sine theta 2 but this are in
opposite direction therefore this would
be minus m2 v2 sine theta 2 otherwise
everything else will remain the same
whenever we talk of collision the most
important thing is to write the
equations for momentum conservation and
energy conservation so in case of 2
dimension it is just that we will have
two two equations one along x-axis one
along by askes now so the app these are
the two equations which are very general
equations I wrote considering that the
equation that the collision which is
taking places in elastic because
momentum conservation will be there even
for elastic as well as inelastic
formation now let us suppose that if the
equal is the forgive the collision which
is taking place is elastic in that case
we will also have that the initial
kinetic energy will be equal to the
final kinetic energy so we will take
into consideration that fact as well
fine so basically what I try to show in
two-dimension words in case you get a
problem in two-dimension you need to
consider conserving Roma momentum along
the axis along x axis and then along y
axis otherwise everything else will
remain the same the concept will still
remain the same now that we have studied
collision be studied waters collision
what are the types of collision elastic
collision inelastic collision we also
start studied momentum and energy
conservation in case of collision now
that we got the basic idea of collision
we will try to solve few problems on
collision thank you
visit exam viacom to watch free
educational videos try free online tests
get the best quality study materials
study from the best tutors and mentors
and much more thanks once again