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Alligation & Mixture Video Lecture | Quantitative Aptitude (Quant) - CAT

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00:00 Introduction
04:10 Question-1
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FAQs on Alligation & Mixture Video Lecture - Quantitative Aptitude (Quant) - CAT

1. What is alligation and mixture?
Ans. Alligation and mixture is a mathematical concept used to solve problems related to the mixing of two or more components with different concentrations or quantities to get a desired concentration or quantity of the resulting mixture.
2. How is alligation and mixture used in real-life scenarios?
Ans. Alligation and mixture is used in various real-life scenarios such as calculating the ratio of ingredients in recipes, determining the concentration of chemicals in solutions, finding the average of grades in a class, or calculating the ratio of different grades of coffee beans in a blend.
3. Can you explain the process of solving an alligation and mixture problem?
Ans. To solve an alligation and mixture problem, follow these steps: 1. Set up a table with the components and their concentrations or quantities. 2. Calculate the weighted average of the components based on their concentrations or quantities. 3. Use the weighted average to find the ratio or concentration of the resulting mixture. 4. Use the ratio or concentration to determine the quantity of the resulting mixture if needed.
4. Are there any shortcuts or formulas for solving alligation and mixture problems?
Ans. Yes, there are formulas that can be used to solve alligation and mixture problems. One such formula is the rule of alligation, which states that the ratio of quantities or concentrations of the components is equal to the ratio of their distances from the mean or average. This formula can simplify the calculation process and save time.
5. Can you provide an example of an alligation and mixture problem and its solution?
Ans. Sure, here's an example: Problem: A chemist has 10 liters of a solution with 20% concentration of acid. How many liters of a 50% acid solution should be added to obtain a solution with a 30% concentration of acid? Solution: Let x be the number of liters of the 50% acid solution to be added. Using the alligation formula, we set up the following table: 20% 30% 50% |-----|-----| 10-x x 10 The ratio of the quantities is 20:30:50 = 2:3:5. Therefore, we can write the equation: (10-x)/x = 3/5. Solving for x, we get x = 25/3 liters. So, 25/3 liters of the 50% acid solution should be added to obtain a solution with a 30% concentration of acid.
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00:00 Introduction
04:10 Question-1
08:45 Question-2
13:53 Question-3
19:42 Question-4
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