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Short Tricks: SHM Problems Video Lecture | Physics Class 11 - NEET
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FAQs on Short Tricks: SHM Problems Video Lecture - Physics Class 11 - NEET
| 1. What is SHM (Simple Harmonic Motion)? |  |
| 2. What are the key properties of an object undergoing SHM? | |
Ans. The key properties of an object undergoing Simple Harmonic Motion are amplitude, frequency, period, and phase. The amplitude is the maximum displacement of the object from its equilibrium position. Frequency represents the number of complete oscillations per unit time, while the period is the time taken to complete one full oscillation. Phase indicates the position of the object within its oscillatory cycle.
| 3. How can we determine the frequency of an object undergoing SHM? | |
Ans. The frequency of an object undergoing Simple Harmonic Motion can be determined by dividing the reciprocal of the period. Mathematically, frequency (f) is equal to 1 divided by the period (T). Therefore, f = 1/T.
| 4. What is the relationship between the mass and frequency in SHM? | |
Ans. In Simple Harmonic Motion, the frequency of oscillation is independent of the mass of the object. The mass only affects the amplitude of the oscillation, not the frequency. This means that two objects with different masses but the same restoring force will oscillate with the same frequency.
| 5. How can we calculate the displacement of an object at a given time during SHM? | |
Ans. The displacement of an object at a given time during Simple Harmonic Motion can be calculated using the equation: x = A * cos(ωt + φ), where x is the displacement, A is the amplitude, ω is the angular frequency (2πf), t is the time, and φ is the phase constant. By substituting the values of A, ω, t, and φ, the displacement can be determined.
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