To determine the equivalent resistance of two resistors when connected in parallel - Lab Exp. Video Lecture - Class 10

to determine the equivalent resistance
of two resistors when connected in
parallel
a pirate is required dry cell with
terminals g6 Eveready cell ten pieces of
insulated thick copper wire with Barons
single key or one-way key ammeter
voltmeter rheostat 10 ohm
two known resistors a and B of
resistance 1 ohm and 2 ohm respectively
sandpaper
procedure rub the bare ends of the
connecting wires with sandpaper so that
bright shining copper metal is seen
remove the plug from the one-way key
K
connect tightly the key to the ammeter
rheostat of 10 ohm only known resistors
a and B of resistance 1 ohm and 2 ohm in
parallel with the help of connecting
wires to the dry-cell
connect the voltmeter in parallel to the
combination of resistors a and B in
parallel
make sure that positive and negative
terminals of voltmeter and ammeter are
connected properly if there is a zero
error in ammeter and voltmeter corrected
by adjusting the adjustment screw
insert the plot key and check that Walt
meter and ammeter show deflection
adjust the slider of the rheostat such
that the a meter shows deflection of
0.15 ampere
read the value of the potential
difference from the wall tweeter
again adjust the slider of the rheostat
such that the ammeter shows a current of
0.30 ampere
read and record the values of potential
difference and the current
repeat the experiment four times more of
the current value of 0.45 ampere
0.60 ampere
you
0.75 ampere
you
and 0.90 ampere in each case read and
record the potential difference
calculate mean equivalent resistance of
the resistors mean equivalent resistance
of resistors a and B connected in
parallel equals total number of
resistance in each case upon number of
cases
conclusion the mean resistance of
resistors a and B in parallel is less
than the individual resistance of
resistors E and B