JEE Exam > JEE Videos > Physics for JEE Main & Advanced > Orbital & Escape Velocity - 1
Orbital & Escape Velocity - 1 Video Lecture | Physics for JEE Main & Advanced
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FAQs on Orbital & Escape Velocity - 1 Video Lecture - Physics for JEE Main & Advanced
| 1. What is the definition of orbital velocity? |  |
Ans. Orbital velocity is the minimum velocity required for an object to maintain a stable orbit around a celestial body, such as a planet or a moon. It is the speed at which the centripetal force due to gravity is balanced by the object's inertia.
| 2. How is escape velocity different from orbital velocity? | |
Ans. Escape velocity is the minimum velocity required for an object to completely escape the gravitational pull of a celestial body. It is greater than the orbital velocity because it needs to overcome the gravitational attraction and reach an infinite distance from the body.
| 3. How is orbital velocity calculated? | |
Ans. The orbital velocity of an object can be calculated using the formula: V = sqrt(G * M / R), where V is the orbital velocity, G is the gravitational constant, M is the mass of the celestial body, and R is the distance from the center of the body to the object.
| 4. Can an object have multiple orbital velocities? | |
Ans. No, an object can have only one orbital velocity for a specific distance from a celestial body. The orbital velocity depends on the mass of the celestial body and the distance from its center. Changing either of these parameters will result in a different orbital velocity.
| 5. What factors affect the escape velocity of a celestial body? | |
Ans. The escape velocity of a celestial body is determined by its mass and radius. A larger mass or a smaller radius will result in a higher escape velocity. The escape velocity is independent of the mass or size of the escaping object.
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Nov 22, 2024 Last updated |
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