Mechanical Engineering Exam > Mechanical Engineering Videos > SFD and BMD for Simply Supported Beam with UDL Load- SFD & BMD Tutorial 5, Strength of Materials
SFD and BMD for Simply Supported Beam with UDL Load- SFD & BMD Tutorial 5, Strength of Materials Video Lecture - Mechanical Engineering
FAQs on SFD and BMD for Simply Supported Beam with UDL Load- SFD & BMD Tutorial 5, Strength of Materials Video Lecture - Mechanical Engineering
| 1. What is SFD and BMD in the context of a simply supported beam with UDL load? |  |
Ans. SFD stands for Shear Force Diagram and BMD stands for Bending Moment Diagram. In the context of a simply supported beam with a Uniformly Distributed Load (UDL), the SFD shows the variation of the shear force along the length of the beam, while the BMD shows the variation of the bending moment along the length of the beam.
| 2. How do you determine the SFD and BMD of a simply supported beam with UDL load? | |
Ans. To determine the SFD and BMD of a simply supported beam with a UDL load, you need to follow these steps:
1. Calculate the reaction forces at the supports.
2. Cut the beam at a specific section and consider the left or right portion of the beam.
3. Calculate the shear force at that section by considering the external forces acting on the beam.
4. Draw the SFD by plotting the shear force values along the length of the beam.
5. Calculate the bending moment at that section by considering the external forces and moments acting on the beam.
6. Draw the BMD by plotting the bending moment values along the length of the beam.
| 3. What are the key features of a Shear Force Diagram (SFD)? | |
Ans. The key features of a Shear Force Diagram (SFD) for a simply supported beam with a UDL load are:
1. The SFD starts at zero at one end of the beam and ends at zero at the other end.
2. The SFD is a graphical representation of the variation of shear force along the length of the beam.
3. The SFD changes its direction at the points where the load or support conditions change.
4. The magnitude of the shear force at any section of the beam can be determined from the SFD.
| 4. What are the key features of a Bending Moment Diagram (BMD)? | |
Ans. The key features of a Bending Moment Diagram (BMD) for a simply supported beam with a UDL load are:
1. The BMD starts and ends at zero at the ends of the beam.
2. The BMD is a graphical representation of the variation of bending moment along the length of the beam.
3. The BMD changes its slope at the points where the load or support conditions change.
4. The magnitude of the bending moment at any section of the beam can be determined from the BMD.
| 5. Why are SFD and BMD important in the analysis of a simply supported beam with UDL load? | |
Ans. SFD and BMD are important in the analysis of a simply supported beam with a UDL load because they provide valuable information regarding the internal forces and moments acting on the beam. By examining the SFD, we can determine the magnitude and direction of the shear force at any section of the beam, which is crucial for designing appropriate supports and connections. Similarly, the BMD helps us understand the variation of the bending moment along the beam, which is essential for selecting the appropriate beam size and shape to ensure structural stability and safety. Overall, SFD and BMD play a vital role in the analysis and design of structural components in strength of materials.
Text Transcript from Video
hello my dear the social Kumar same
again I am back with another question
and this is a question for simply
supported beam simply supported beam and
here I have taken this question
UDL so this is one of the important
question for university examination
point of view as well as completely
examination point of view how to solve
question when you are giving point load
as well as UDL load in simply supported
beam this is important this is really
most important for any examination point
of view well I am from India and I
usually have seen caution in this topic
around 20 bucks and for a single
question and that I have seen few
University they are setting question
like this only for 20 bucks so this is
really important so let me share with
you how you can solve this type of
question and you will come to know and
you can do the same if will keep
watching so keep watching and keep
listen to me carefully what I am talking
in this video to solve this question so
let me first extend these lines that's
why I can draw shear force and
bending-moment diagrams for this
question so I am taking this is as a
reference line this as a reference line
and Here I am going to draw shear force
diagram so first of all I have to find
out reaction force here let me take
reaction force a and here let me take
mix and force B so total force acting on
this beam is equal to total reaction
force that's why we can write our a plus
RB is equal to total load so this is 30
this is 20 because this is you dear this
is that means 5 kilo Newton per meter so
total load acting on this because of
this UDL will be 5 into 4 so 30 plus 20
plus 20 so total load would be how much
50 plus 20 of 50 plus 20
70 kilo Newton so this is important
now let me total load acting on this
beam 70 kilo Newton
so total reaction force would be 70 kilo
Newton to balance this beam so let me
find out how much load how much Dickson
force is acting here and how much
Dickson force is acting here so let me
let me ship or let me let me assume that
assume that our a is fixed I am assuming
here our a is fixed so if I will assume
RA is fixed next what will happen we can
write equation that I am just writing
here only so RB into total length of
this beam that is 10 meter 4 plus 4 plus
2 is equal to 10 meter is equal to 20
into total distance from here to here so
20 into 6 plus 30 into 2 so how much
would be this 120 plus 60 180 and total
acting load I mean also we have a UDL
load so bending moment because of this
load would be 5 into 4 into because this
load to be acting here so 4 by 2 4 by 2
distance plus 2 so total would be 180
plus 20 into 480 so total bending moment
here would be 2 60 kilonewton meter so
RB is equal to 260 by 10 to 60 by 10 is
equal to how much twenty six kilo Newton
so total reaction force would be here 26
kilo Newton if 20 RB is equal to 26 then
our a is equal to 44 simply I have just
said did I have just do one thing 17
minus 26 17 minus 26 is equal to 44 kilo
Newtons so this is would be 44 kilo
Newton now I have to do
force diagram so here what I have to do
here we have 26 reaction force that
means this will be 26 because this is
negative here 26 kilonewton now here we
have again adding here 20 that means 2
minus six remaining minus 6 remaining so
and here we are we are having UDL so
that's why 25 into 4 5 into 4 20 minus 6
would be how much 14 so this would be
like this this is 14 and 14 plus 30 44
and this it seemed it are kilonewton
it's also kilo Newton now what we have
to do to check it is it right or wrong
just add minus 26 plus 26 is equal to
zero that means this is right here 44
plus minus 44 that means this is right
so we have to check it whether it is
right or wrong now on the basis of this
sfd diagram I can draw bending moment
diagram so let me share with you how you
can draw bending moment diagram so here
is that this is for bending moment
diagram so there is a problem let me so
how there's a problem with my camera
okay no problem I can show you how we
can draw a bending moment diagram for
this portion so this is bending moment
diagram now here we have to find out
area of this this one and area of this
one area of this one area of this one
now first I have to find out the
distance covering here so what to do
total load is acting here it is humming
now sorry for the disturbance okay no
problem now let us come to the back to
the question first we have to find out
the distance here we are covering and so
14 kilo Newton okay so 14 kilo Newton
and here how much distance we can we'll
cover that's why it will it will get
hyunjun from here that means six plus
six so how much distance it will go over
to get six kilo Newton so 5 into 1 point
2 is equal to 6 so this is 1.2 and this
is remaining how much total is 4 so this
would be how much this would be how much
to 0.8 because 4 minus 1.2 is equal to
how much to point weight so this is like
this you can easily find out now I can
do quite easy so one another basic
concept you need to follow what is that
let me show you let me share with you so
what is that this bending moment diagram
you need to start from where you have
make it fixed where I have fixed let R
is fixed this is fixed this side is
fixed this one is fixed I have as iam so
I have to start drawing bending moment
diagram from this side only so how much
how to find out area of this maybe you
have watched my previous videos to draw
bending moment diagram we need to find
out area so how much area of this 4444
is height so this is 44 this is 44 and
the length of this is I mean this length
of this beam is 2 so how much would be a
value 44 into 288 we need to find out
area of this triangle so when rectangle
this is rectangle and so what will be
here and one more thing if this is
straight line we have to make it
inclined so this is 88 kilonewton meter
8 8 kilo Newton meter now another thing
we need to find out triangle the area of
this triangle that is 14 into 2 point
into 1 point 2 this value is 19 point
six so nineteen point six plus 88 is
equal to how much is equal to10 seven
point six so this would be a let me draw
line here this digit this is inclined
that's why it will become parabolic
so this is one-zero 7.6 now this is
positive that's why I have added with
this this is in negative that's why I
have to minus this I mean we have to
find out area of this triangle so 1.2
into 6 into 1 by 2 is equal to how much
I have to get 3.6 because this is 3 so 3
point 6 so this is minus 3.6 would be
how much 1 0 4 kilo Newton meter
remember the unit for bending moment
diagram is always this is the universal
constant that is kilo Newton meter now
you know 60 we need to find out area of
this rectangle that is 26 is height and
4 is this is Len so 26 into four how
much 1 0 4 so 1 0 4 this is negative
this is positive so negative plus
positive 1 0 4 plus and minus 1 0 4
degree zero so bending them it will be a
0 so this is the way how you can find
out what how you can draw bending moment
diagram for this problems for simply
supported beam we in the case of UDL
well I hope you got it how to solve
questions related to it and thanks for
watching and if you got any question in
this topic let me know our definitely
share with you how to solve question
well thanks for watching what - see you
again in my next video
buh-bye
again I am back with another question
and this is a question for simply
supported beam simply supported beam and
here I have taken this question
UDL so this is one of the important
question for university examination
point of view as well as completely
examination point of view how to solve
question when you are giving point load
as well as UDL load in simply supported
beam this is important this is really
most important for any examination point
of view well I am from India and I
usually have seen caution in this topic
around 20 bucks and for a single
question and that I have seen few
University they are setting question
like this only for 20 bucks so this is
really important so let me share with
you how you can solve this type of
question and you will come to know and
you can do the same if will keep
watching so keep watching and keep
listen to me carefully what I am talking
in this video to solve this question so
let me first extend these lines that's
why I can draw shear force and
bending-moment diagrams for this
question so I am taking this is as a
reference line this as a reference line
and Here I am going to draw shear force
diagram so first of all I have to find
out reaction force here let me take
reaction force a and here let me take
mix and force B so total force acting on
this beam is equal to total reaction
force that's why we can write our a plus
RB is equal to total load so this is 30
this is 20 because this is you dear this
is that means 5 kilo Newton per meter so
total load acting on this because of
this UDL will be 5 into 4 so 30 plus 20
plus 20 so total load would be how much
50 plus 20 of 50 plus 20
70 kilo Newton so this is important
now let me total load acting on this
beam 70 kilo Newton
so total reaction force would be 70 kilo
Newton to balance this beam so let me
find out how much load how much Dickson
force is acting here and how much
Dickson force is acting here so let me
let me ship or let me let me assume that
assume that our a is fixed I am assuming
here our a is fixed so if I will assume
RA is fixed next what will happen we can
write equation that I am just writing
here only so RB into total length of
this beam that is 10 meter 4 plus 4 plus
2 is equal to 10 meter is equal to 20
into total distance from here to here so
20 into 6 plus 30 into 2 so how much
would be this 120 plus 60 180 and total
acting load I mean also we have a UDL
load so bending moment because of this
load would be 5 into 4 into because this
load to be acting here so 4 by 2 4 by 2
distance plus 2 so total would be 180
plus 20 into 480 so total bending moment
here would be 2 60 kilonewton meter so
RB is equal to 260 by 10 to 60 by 10 is
equal to how much twenty six kilo Newton
so total reaction force would be here 26
kilo Newton if 20 RB is equal to 26 then
our a is equal to 44 simply I have just
said did I have just do one thing 17
minus 26 17 minus 26 is equal to 44 kilo
Newtons so this is would be 44 kilo
Newton now I have to do
force diagram so here what I have to do
here we have 26 reaction force that
means this will be 26 because this is
negative here 26 kilonewton now here we
have again adding here 20 that means 2
minus six remaining minus 6 remaining so
and here we are we are having UDL so
that's why 25 into 4 5 into 4 20 minus 6
would be how much 14 so this would be
like this this is 14 and 14 plus 30 44
and this it seemed it are kilonewton
it's also kilo Newton now what we have
to do to check it is it right or wrong
just add minus 26 plus 26 is equal to
zero that means this is right here 44
plus minus 44 that means this is right
so we have to check it whether it is
right or wrong now on the basis of this
sfd diagram I can draw bending moment
diagram so let me share with you how you
can draw bending moment diagram so here
is that this is for bending moment
diagram so there is a problem let me so
how there's a problem with my camera
okay no problem I can show you how we
can draw a bending moment diagram for
this portion so this is bending moment
diagram now here we have to find out
area of this this one and area of this
one area of this one area of this one
now first I have to find out the
distance covering here so what to do
total load is acting here it is humming
now sorry for the disturbance okay no
problem now let us come to the back to
the question first we have to find out
the distance here we are covering and so
14 kilo Newton okay so 14 kilo Newton
and here how much distance we can we'll
cover that's why it will it will get
hyunjun from here that means six plus
six so how much distance it will go over
to get six kilo Newton so 5 into 1 point
2 is equal to 6 so this is 1.2 and this
is remaining how much total is 4 so this
would be how much this would be how much
to 0.8 because 4 minus 1.2 is equal to
how much to point weight so this is like
this you can easily find out now I can
do quite easy so one another basic
concept you need to follow what is that
let me show you let me share with you so
what is that this bending moment diagram
you need to start from where you have
make it fixed where I have fixed let R
is fixed this is fixed this side is
fixed this one is fixed I have as iam so
I have to start drawing bending moment
diagram from this side only so how much
how to find out area of this maybe you
have watched my previous videos to draw
bending moment diagram we need to find
out area so how much area of this 4444
is height so this is 44 this is 44 and
the length of this is I mean this length
of this beam is 2 so how much would be a
value 44 into 288 we need to find out
area of this triangle so when rectangle
this is rectangle and so what will be
here and one more thing if this is
straight line we have to make it
inclined so this is 88 kilonewton meter
8 8 kilo Newton meter now another thing
we need to find out triangle the area of
this triangle that is 14 into 2 point
into 1 point 2 this value is 19 point
six so nineteen point six plus 88 is
equal to how much is equal to10 seven
point six so this would be a let me draw
line here this digit this is inclined
that's why it will become parabolic
so this is one-zero 7.6 now this is
positive that's why I have added with
this this is in negative that's why I
have to minus this I mean we have to
find out area of this triangle so 1.2
into 6 into 1 by 2 is equal to how much
I have to get 3.6 because this is 3 so 3
point 6 so this is minus 3.6 would be
how much 1 0 4 kilo Newton meter
remember the unit for bending moment
diagram is always this is the universal
constant that is kilo Newton meter now
you know 60 we need to find out area of
this rectangle that is 26 is height and
4 is this is Len so 26 into four how
much 1 0 4 so 1 0 4 this is negative
this is positive so negative plus
positive 1 0 4 plus and minus 1 0 4
degree zero so bending them it will be a
0 so this is the way how you can find
out what how you can draw bending moment
diagram for this problems for simply
supported beam we in the case of UDL
well I hope you got it how to solve
questions related to it and thanks for
watching and if you got any question in
this topic let me know our definitely
share with you how to solve question
well thanks for watching what - see you
again in my next video
buh-bye
About this Video
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Oct 08, 2025
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