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Akshat SainiEduRev Chemistry |
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Akshat Saini
EduRev Chemistry
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Discussed Questions
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Akshat Saini upvoted • Feb 27, 2025 |
The absorption at λmax 279 nm (ε = 15) in the UV spectrum of acetone is due to:
- a)π-π* transition
- b)σ-σ* transition
- c)n-π* transition
- d)π-σ* transition
Correct answer is option 'C'. Can you explain this answer?
The absorption at λmax 279 nm (ε = 15) in the UV spectrum of acetone is due to:
a)
π-π* transition
b)
σ-σ* transition
c)
n-π* transition
d)
π-σ* transition
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Edurev.iitjam answered |
The type of transition is responsible for a band at λmax = 279 nm in absorption spectrum of acetone. In case of n → π* transitions, the polar solvents form hydrogen bonds with the ground state of polar molecules more readily than with their excited states. Therefore, in polar solvents the energies of electronic transitions are increased.
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Akshat Saini upvoted • Feb 11, 2025 |
Which of the following molecules, in pure form, is (are) unstable at room temperature:- a)
- b)
- c)
- d)
Correct answer is option 'B,C'. Can you explain this answer?
Which of the following molecules, in pure form, is (are) unstable at room temperature:
a)
b)
c)
d)
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Asf Institute answered |
Correct Answer :- b,c
Explanation : (B) Cyclobutadiene follows Huckel's criteria for anti-aromaticity [(4n)−π electrons], hence unstable.
(C) Follows Huckel's criteria for anti-aromaticity [(4n)−π electrons], hence, unstable.
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Akshat Saini upvoted • Feb 05, 2025 |
In radical chain polymerization, the quantity given by the rate of monomer depletion, divided by the rate of propagating radical formation is called:
- a)Kinetic chain length.
- b)Propagation efficiency.
- c)Propagation rate constant
- d)Polymerization time.
Correct answer is option 'A'. Can you explain this answer?
In radical chain polymerization, the quantity given by the rate of monomer depletion, divided by the rate of propagating radical formation is called:
a)
Kinetic chain length.
b)
Propagation efficiency.
c)
Propagation rate constant
d)
Polymerization time.
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Edurev.iitjam answered |
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Akshat Saini upvoted • Feb 01, 2025 |
The correct statement about the Cu–N bond distance in [Cu(NH3)6]2+ is:- a)All the bond distance are equal.
- b)The axial bonds are longer than the equatorial ones.
- c)The equatorial bonds are longer than the axial ones.
- d)All the bond distances are unequal.
Correct answer is option 'B'. Can you explain this answer?
The correct statement about the Cu–N bond distance in [Cu(NH3)6]2+ is:
a)
All the bond distance are equal.
b)
The axial bonds are longer than the equatorial ones.
c)
The equatorial bonds are longer than the axial ones.
d)
All the bond distances are unequal.
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Edurev.iitjam answered |
- In [Cu(NH3)6]2+, there are six NH3 ligands arranged in an octahedral geometry around the central Cu2+ ion.
- The bond distances are different due to the difference in the orientation of the ligands.
- There are two types of bond distances in this complex: axial and equatorial.
- Axial bonds: These are the bonds that are perpendicular to the plane of the equatorial bonds. There are two axial bonds in this complex.
- Equatorial bonds: These are the bonds that lie in the plane of the complex. There are four equatorial bonds in this complex.
- The repulsion between the lone pairs of electrons on the NH3 ligands causes the axial bonds to be longer than the equatorial bonds.
- Therefore, the correct statement is that the axial bonds are longer than the equatorial ones (option B is correct).
- The bond distances are different due to the difference in the orientation of the ligands.
- There are two types of bond distances in this complex: axial and equatorial.
- Axial bonds: These are the bonds that are perpendicular to the plane of the equatorial bonds. There are two axial bonds in this complex.
- Equatorial bonds: These are the bonds that lie in the plane of the complex. There are four equatorial bonds in this complex.
- The repulsion between the lone pairs of electrons on the NH3 ligands causes the axial bonds to be longer than the equatorial bonds.
- Therefore, the correct statement is that the axial bonds are longer than the equatorial ones (option B is correct).
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Akshat Saini upvoted • Jan 28, 2025 |
For the reaction in equilibrium, A 
B
Thus, K is- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
For the reaction in equilibrium, A B
Thus, K is
BThus, K is
a)
b)
c)
d)
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Sushil Kumar answered |
From the reaction
-d[A]/dt = d[B] /dt
⇒2.3 × 106 [A] = k [B]
as given in question [B] /[A] = 4 × 108
so [A] / [B] = 1/ 4 ×108
⇒ 2.3 × 106 . [A] /[B] = k
⇒ 2.3 × 106 / 4 × 108 = k
Or k = 5.8 × 10-3 /sec¹
-d[A]/dt = d[B] /dt
⇒2.3 × 106 [A] = k [B]
as given in question [B] /[A] = 4 × 108
so [A] / [B] = 1/ 4 ×108
⇒ 2.3 × 106 . [A] /[B] = k
⇒ 2.3 × 106 / 4 × 108 = k
Or k = 5.8 × 10-3 /sec¹
Choose the correct statement/s:- a)Be compounds are toxic because of ability of Be(II) ions to displace Mg(II) ions.
- b)NH4Cl when dissolved in water produce cold solution.
- c)Reaction of Sodium with water is exothermic. Rate of reaction can be lowered by making metal-amalgam.
- d)Dipole moment of NOCl is non-zero.
Correct answer is option 'A,B,C,D'. Can you explain this answer?
Choose the correct statement/s:
a)
Be compounds are toxic because of ability of Be(II) ions to displace Mg(II) ions.
b)
NH4Cl when dissolved in water produce cold solution.
c)
Reaction of Sodium with water is exothermic. Rate of reaction can be lowered by making metal-amalgam.
d)
Dipole moment of NOCl is non-zero.
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Akshat Saini answered • Jan 28, 2025 |
Statement A: Toxicity of Be Compounds
- Be compounds are indeed toxic, primarily because Be(II) ions can effectively displace Mg(II) ions in biological systems.
- This displacement disrupts essential physiological processes since magnesium is crucial for many enzymatic functions.
Statement B: NH4Cl Dissolution
- When NH4Cl is dissolved in water, it undergoes an en... more
- Be compounds are indeed toxic, primarily because Be(II) ions can effectively displace Mg(II) ions in biological systems.
- This displacement disrupts essential physiological processes since magnesium is crucial for many enzymatic functions.
Statement B: NH4Cl Dissolution
- When NH4Cl is dissolved in water, it undergoes an en... more
What is meant by a body diagonal in a crystal lattice? How to find the formula of crystal when one body diagonal is removed?
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Akshat Saini answered • Dec 25, 2024 |
Understanding Body Diagonal in a Crystal Lattice
A body diagonal in a crystal lattice refers to the diagonal line that connects two opposite corners of a three-dimensional unit cell. This line traverses through the interior of the cell, passing through the center. It is significant as it helps in determining the geometry and dimensions of the unit cell.
Importance of Body Diago... more
- Geometric Representation: The body diagonal provides insight into the spatial arrangement of atoms in a crystal structure.
- Coordination Number: It influences the coordination number, which is the number of nearest neighbors surrounding an atom.
Finding the Formula When One Body Diagonal is Removed
When one body diagonal is removed from a crystal structure, the resulting changes can be analyzed as follows:
- Identify the Original Structure: Recognize the original unit cell and its formula based on the atoms and their positions.
- Analyze the Impact of Removal: Evaluate how the removal of a body diagonal affects atomic connectivity and symmetry. This can result in a shift in coordination numbers and bond lengths.
- Recalculate the Unit Cell: With the new arrangement, recalculate the number of atoms per unit cell.
- Derive the New Formula: The new empirical formula can be derived by adjusting the count of each type of atom based on the modified lattice.
Example of Modification
- Cubic Structure: For a cubic crystal, removing one body diagonal may lead to a change in symmetry, potentially altering it to a less symmetric form, such as a tetragonal or orthorhombic structure.
- Resulting Formula: If the original formula was AB with a specific ratio, the new formula could evolve to a different stoichiometric ratio depending on the remaining atomic arrangements.
By understanding these principles, you can effectively analyze the changes in crystal structures resulting from the removal of a body diagonal.
A body diagonal in a crystal lattice refers to the diagonal line that connects two opposite corners of a three-dimensional unit cell. This line traverses through the interior of the cell, passing through the center. It is significant as it helps in determining the geometry and dimensions of the unit cell.
Importance of Body Diago... more
- Geometric Representation: The body diagonal provides insight into the spatial arrangement of atoms in a crystal structure.
- Coordination Number: It influences the coordination number, which is the number of nearest neighbors surrounding an atom.
Finding the Formula When One Body Diagonal is Removed
When one body diagonal is removed from a crystal structure, the resulting changes can be analyzed as follows:
- Identify the Original Structure: Recognize the original unit cell and its formula based on the atoms and their positions.
- Analyze the Impact of Removal: Evaluate how the removal of a body diagonal affects atomic connectivity and symmetry. This can result in a shift in coordination numbers and bond lengths.
- Recalculate the Unit Cell: With the new arrangement, recalculate the number of atoms per unit cell.
- Derive the New Formula: The new empirical formula can be derived by adjusting the count of each type of atom based on the modified lattice.
Example of Modification
- Cubic Structure: For a cubic crystal, removing one body diagonal may lead to a change in symmetry, potentially altering it to a less symmetric form, such as a tetragonal or orthorhombic structure.
- Resulting Formula: If the original formula was AB with a specific ratio, the new formula could evolve to a different stoichiometric ratio depending on the remaining atomic arrangements.
By understanding these principles, you can effectively analyze the changes in crystal structures resulting from the removal of a body diagonal.
What is the oxidation state of platinum in [PtCl6]2-- a)+ 2
- b)+ 4
- c)+ 6
- d)None of the above
Correct answer is option 'B'. Can you explain this answer?
What is the oxidation state of platinum in [PtCl6]2-
a)
+ 2
b)
+ 4
c)
+ 6
d)
None of the above
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Akshat Saini answered • Nov 09, 2024 |
Understanding the Oxidation State of Platinum in [PtCl6]2-
To determine the oxidation state of platinum in the complex ion [PtCl6]2-, we need to analyze the overall charge and the contributions from the chloride ions.
Step 1: Identifying the Overall Charge
- The complex ion [PtCl6]2- has an overall charge of -2.
Step 2: Charge Contribution from Chloride Ions... more
To determine the oxidation state of platinum in the complex ion [PtCl6]2-, we need to analyze the overall charge and the contributions from the chloride ions.
Step 1: Identifying the Overall Charge
- The complex ion [PtCl6]2- has an overall charge of -2.
Step 2: Charge Contribution from Chloride Ions... more
Ch3)2co is volatile liquid but (Ch3)2sio is not.. why?
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Akshat Saini answered • Sep 04, 2024 |
Introduction
The volatility of a liquid is influenced by its molecular structure and intermolecular forces. In this case, we compare the volatility of (CH₃)₂CO (acetone) and (CH₃)₂SiO (dimethylsiloxane).
Structure and Composition
- **(CH₃)₂CO (Acetone)**
- Acetone is a simple ketone with a carbonyl (C=O) functional group.
- The molecule has a relati... more
The volatility of a liquid is influenced by its molecular structure and intermolecular forces. In this case, we compare the volatility of (CH₃)₂CO (acetone) and (CH₃)₂SiO (dimethylsiloxane).
Structure and Composition
- **(CH₃)₂CO (Acetone)**
- Acetone is a simple ketone with a carbonyl (C=O) functional group.
- The molecule has a relati... more
Give an optically active coordination compound which is purely inorganic in narure?
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Akshat Saini answered • Jul 27, 2024 |
Optically Active Coordination Compound in Nature
Coordination compounds are molecules composed of a central metal atom or ion bonded to surrounding ligands. Optically active compounds are those that rotate the plane of polarized light. An example of an optically active coordination compound that is purely inorganic in nature is cis-dichlorobis(ethylenediamine)cobalt(III) chloride.
... more
Coordination compounds are molecules composed of a central metal atom or ion bonded to surrounding ligands. Optically active compounds are those that rotate the plane of polarized light. An example of an optically active coordination compound that is purely inorganic in nature is cis-dichlorobis(ethylenediamine)cobalt(III) chloride.
... more
?
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Akshat Saini answered • Jun 22, 2024 |
Document for Preparation of Amino Acids
Here is a detailed guide on the preparation of amino acids:
1. Synthesis of Amino Acids
- Amino acids can be synthesized through various methods such as Strecker synthesis, Gabriel synthesis, and Hofmann degradation.
- Strecker synthesis involves the reaction of an aldehyde or ketone with ammonia and cyanide ion to form an α-amino nitrile, which can then be hydrolyzed to yield an amino acid.
- Gabriel synthesis utilizes phthalimide, alkyl halide, and KOH to form an amino acid through a series of reactions.
- Hofmann degradation involves the degradation of an amide to yield an amine, which can then be converted to an amino acid.
2. Properties of Amino Acids
- Amino acids are organic compounds containing both an amino group and a carboxyl group.
- They are the building blocks of proteins and play crucial roles in various biological processes.
- Amino acids can exist in different forms such as L-amino acids and D-amino acids, depending on their stereochemistry.
3. Importance of Amino Acids in Bio-Molecules
- Amino acids are essential for the synthesis of proteins, enzymes, and hormones in living organisms.
- They are involved in the regulation of metabolism, immune function, and nutrient absorption.
- Deficiencies in amino acids can lead to various health issues and diseases.
4. Amino Acids in Organic Chemistry
- Amino acids exhibit various chemical properties such as acidity, basicity, and chirality.
- They can undergo reactions such as condensation, hydrolysis, and decarboxylation to form peptides and proteins.
- Amino acids are vital components of the nitrogen cycle and are crucial for the survival of all living organisms.
... more
The correct order of the ionic radii is:- a)In3+ > Sn4+ > Sr2+ > Rb+
- b)Sn4+ > In3+ > Sr2+ > Rb+
- c)Rb+ > In3+ > Sr2+ > Sn4+
- d)Rb+ > Sr2+ > In3+ > Sn4+
Correct answer is option 'D'. Can you explain this answer?
The correct order of the ionic radii is:
a)
In3+ > Sn4+ > Sr2+ > Rb+
b)
Sn4+ > In3+ > Sr2+ > Rb+
c)
Rb+ > In3+ > Sr2+ > Sn4+
d)
Rb+ > Sr2+ > In3+ > Sn4+
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Akshat Saini answered • May 21, 2024 |
Explanation:
1. Rb+:
- Rb+ has the largest ionic radius among the given ions because it has the lowest effective nuclear charge, leading to weaker attraction between the nucleus and the outermost electrons.
2. Sr2+:
- Sr2+ has a smaller ionic radius compared to Rb+ because it has a higher effective nuclear charge due to the additional positive ... more
1. Rb+:
- Rb+ has the largest ionic radius among the given ions because it has the lowest effective nuclear charge, leading to weaker attraction between the nucleus and the outermost electrons.
2. Sr2+:
- Sr2+ has a smaller ionic radius compared to Rb+ because it has a higher effective nuclear charge due to the additional positive ... more
Predict the value of ′x′ inCo2(CO)x andMnx(CO)10 respectively: ( follow EAN rule)- a)10, 2
- b)8,2
- c)6,3
- d)9,4
Correct answer is option 'B'. Can you explain this answer?
Predict the value of ′x′ inCo2(CO)x andMnx(CO)10 respectively: ( follow EAN rule)
a)
10, 2
b)
8,2
c)
6,3
d)
9,4
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Akshat Saini answered • Feb 12, 2024 |
It is not possible to predict the value without providing the specific variable or data being referred to. Please provide more information.
Ionization energies are always positive.- a)True
- b)False
Correct answer is option 'A'. Can you explain this answer?
Ionization energies are always positive.
a)
True
b)
False
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Akshat Saini answered • Feb 11, 2024 |
Explanation:
The ionization energy is the energy required to remove an electron from an atom or ion in the gaseous state. It is a measure of how tightly an electron is held by the nucleus of an atom. When an electron is removed from an atom, it requires energy to overcome the attractive force between the electron and the nucleus. Therefore, the ionization energy is always positiv... more
The ionization energy is the energy required to remove an electron from an atom or ion in the gaseous state. It is a measure of how tightly an electron is held by the nucleus of an atom. When an electron is removed from an atom, it requires energy to overcome the attractive force between the electron and the nucleus. Therefore, the ionization energy is always positiv... more
Brown ring test for nitrates depends upon:- a)The reduction of nitrate to nitric oxide
- b)Oxidation of nitric oxide to nitrogen dioxide
- c)Reduction of ferrous sulfate to iron
- d)Oxidizing action of sulfuric acid
Correct answer is option 'A'. Can you explain this answer?
Brown ring test for nitrates depends upon:
a)
The reduction of nitrate to nitric oxide
b)
Oxidation of nitric oxide to nitrogen dioxide
c)
Reduction of ferrous sulfate to iron
d)
Oxidizing action of sulfuric acid
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Akshat Saini answered • Jan 31, 2024 |
Introduction:
The Brown ring test is a test used to detect the presence of nitrates in a solution. It is based on the reaction between nitrates and ferrous ions. The test involves the formation of a brown ring at the junction of the two layers when a mixture of the test solution, sulfuric acid, and ferrous sulfate is carefully added to concentrated sulfuric acid. The presence of the br... more
The Brown ring test is a test used to detect the presence of nitrates in a solution. It is based on the reaction between nitrates and ferrous ions. The test involves the formation of a brown ring at the junction of the two layers when a mixture of the test solution, sulfuric acid, and ferrous sulfate is carefully added to concentrated sulfuric acid. The presence of the br... more
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Akshat Saini asked • Sep 29, 2023 |
What is the primary purpose of using voltammetry in chemical analysis?- a)To measure mass changes in chemical reactions.
- b)To determine the concentration of an analyte.
- c)To separate components of a mixture.
- d)To generate ions from the analyte.
Correct answer is option 'B'. Can you explain this answer?
a)
To measure mass changes in chemical reactions.
b)
To determine the concentration of an analyte.
c)
To separate components of a mixture.
d)
To generate ions from the analyte.
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Vivek Khatri answered |
Voltammetry is primarily used to determine the concentration of an analyte through electrochemical reactions. It measures the current response as a function of the applied potential, allowing for both qualitative and quantitative analysis of various chemical substances.
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Akshat Saini asked • Aug 17, 2023 |
Can I get the details of the process for the conducting institute to verify and validate the IIT JAM Chemistry answer key?
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Shivani Mehta answered |
Process for verifying and validating the IIT JAM Chemistry answer key
The process for verifying and validating the IIT JAM Chemistry answer key involves several steps to ensure accuracy and fairness. Here is a detailed explanation of the process:
1. Compilation of the answer key:
- After the completion of the IIT JAM Chemistry examination, the conducting in... more
The process for verifying and validating the IIT JAM Chemistry answer key involves several steps to ensure accuracy and fairness. Here is a detailed explanation of the process:
1. Compilation of the answer key:
- After the completion of the IIT JAM Chemistry examination, the conducting in... more
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Akshat Saini asked • Aug 17, 2023 |
How can I stay motivated and focused during my long-term IIT JAM Chemistry preparation?
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Shivani Mehta answered |
Staying Motivated and Focused during Long-term IIT JAM Chemistry Preparation
Preparing for the IIT JAM Chemistry exam requires a consistent and dedicated effort over a long period of time. Here are some strategies to stay motivated and focused during your long-term preparation:
1. Set Clear Goals:
- Define your long-term goal of cracking the IIT JAM Chemist... more
Preparing for the IIT JAM Chemistry exam requires a consistent and dedicated effort over a long period of time. Here are some strategies to stay motivated and focused during your long-term preparation:
1. Set Clear Goals:
- Define your long-term goal of cracking the IIT JAM Chemist... more
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Akshat Saini asked • Aug 14, 2023 |
Can I get the cutoff trend for IIT JAM Chemistry over the past few years?
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Sinjini Singh answered |
Cutoff Trend for IIT JAM Chemistry
The cutoff trend for IIT JAM Chemistry over the past few years can be analyzed to understand the minimum qualifying marks required to secure admission in the prestigious Indian Institutes of Technology (IITs) and other participating institutes. The cutoff marks are determined based on various factors such as the difficulty level of the exam, the... more
The cutoff trend for IIT JAM Chemistry over the past few years can be analyzed to understand the minimum qualifying marks required to secure admission in the prestigious Indian Institutes of Technology (IITs) and other participating institutes. The cutoff marks are determined based on various factors such as the difficulty level of the exam, the... more
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Akshat Saini asked • Aug 02, 2023 |
Are there any specific tips to improve my speed and accuracy in the IIT JAM Chemistry exam?
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Soumya Sharma answered |
Tips to Improve Speed and Accuracy in the IIT JAM Chemistry Exam
1. Understand the Exam Pattern:
- Familiarize yourself with the exam pattern, marking scheme, and syllabus.
- Analyze previous year question papers to identify the frequently asked topics.
- Focus on important topics and allocate your study time accordingly.
2. Develop a Study Plan:
... more|
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Akshat Saini asked • Aug 02, 2023 |
Can foreign nationals apply for the IIT JAM Chemistry exam?
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Soumya Sharma answered |
Can foreign nationals apply for the IIT JAM Chemistry exam?
Foreign nationals are eligible to apply for the IIT JAM (Joint Admission Test for M.Sc.) Chemistry exam. The IIT JAM is a national level entrance exam conducted by the Indian Institutes of Technology (IITs) for admission to postgraduate programs in various science and technology disciplines.
Foreign nationals ... more
Foreign nationals are eligible to apply for the IIT JAM (Joint Admission Test for M.Sc.) Chemistry exam. The IIT JAM is a national level entrance exam conducted by the Indian Institutes of Technology (IITs) for admission to postgraduate programs in various science and technology disciplines.
Foreign nationals ... more
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Akshat Saini asked • Dec 04, 2022 |
What will be the number of products (excluding stereoisomers) in the given reaction?
C6H5CHO + CH3-CHO + NaOH → Product- a)One
- b)Three
- c)Two
- d)Four
Correct answer is option 'C'. Can you explain this answer?
What will be the number of products (excluding stereoisomers) in the given reaction?
C6H5CHO + CH3-CHO + NaOH → Product
C6H5CHO + CH3-CHO + NaOH → Product
a)
One
b)
Three
c)
Two
d)
Four
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Vivek Khatri answered |
First product will be formed by cross aldol where nucleophile (–OH) will attack at different type or reactant molecule.
Second type of product will be formed aldol condensation where reaction will occur between same type of molecule.
Second type of product will be formed aldol condensation where reaction will occur between same type of molecule.
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Akshat Saini asked • Nov 30, 2022 |
The half-life of a given reaction is doubled if the initial concentration of the reactant is doubled. What is the order of the reaction?- a)0
- b)1
- c)2
- d)3
Correct answer is option 'A'. Can you explain this answer?
The half-life of a given reaction is doubled if the initial concentration of the reactant is doubled. What is the order of the reaction?
a)
0
b)
1
c)
2
d)
3
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Pioneer Academy answered |
Half-life (t1⁄2) is the time required for a quantity to reduce to half of its initial value. The half-life of a zero-order reaction is directly proportional to its initial concentration. They are related as:
t1/2 = [R]0/2k.
t1/2 = [R]0/2k.
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