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Vaishnavi VermaEduRev Mathematics |
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Vaishnavi Verma
EduRev Mathematics
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Discussed Questions
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Vaishnavi Verma upvoted • 2 weeks ago |
By taking (a, 0) as the fixed point, the intrinsic equation of the astroid x2/3 + y2/3 = a2/3 is given by:- a)
- b)
- c)
- d)
Correct answer is option 'D'. Can you explain this answer?
By taking (a, 0) as the fixed point, the intrinsic equation of the astroid x2/3 + y2/3 = a2/3 is given by:
a)
b)
c)
d)
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Veda Institute answered |
The equation of the given curve is
Then
Since, (a, 0) is taken as a fixed point, therefore s increases as θ increases.
Hence
..(i)
Then
Since, (a, 0) is taken as a fixed point, therefore s increases as θ increases.
Hence
..(i)
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Vaishnavi Verma upvoted • 4 weeks ago |
Let T :R3---> R3: be a linear transformation defined by T(x, y, z) = (2x, 2x - 5y, 2y + z). Then T-1 is- a)
- b)
- c)
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
Let T :R3---> R3: be a linear transformation defined by T(x, y, z) = (2x, 2x - 5y, 2y + z). Then T-1 is
a)
b)
c)
d)
None of these
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Veda Institute answered |
Let T be a linear transformation defined by T(x, y, z) = (2x, 2x -5y,2y + z)
We need to find T-1
Let (x, y, z) ∈ ker T,
Then T(x,y,z) = (0,0,0)
Using definition of T, we get
(2x, 2x - 5y, 2y + z) - (0, 0, 0) Implies, 2x = 0, 2x- 5y = 0 and 2y + z = 0
Solving for x, y and z, we get
x = 0, y = 0 and z =0
Hence, ker T = {(0, 0, 0)}
and thus T is one-one.
Since R3 is a three dimensional (finite dimensional) vector space and T is a linear transformation from R3 to R3.
Hence, T is onto.
Therefore, T-1 exist.
Let (a, b, c) be the image of (x, y, z) under T-1 then T-1(x, y, z) = (a, b, c) Implies, T(a, b, c) = (x,y, z)
Using the definition of linear transformation T,
we get
(2a, 2a - 5b, 2b + c) = (x, y, z) Comparing the components of the co-ordinates,
we get 2a= x ,2a-5b = y and 2b + c = z
Solving for a, b and c we get,
Therefore
We need to find T-1
Let (x, y, z) ∈ ker T,
Then T(x,y,z) = (0,0,0)
Using definition of T, we get
(2x, 2x - 5y, 2y + z) - (0, 0, 0) Implies, 2x = 0, 2x- 5y = 0 and 2y + z = 0
Solving for x, y and z, we get
x = 0, y = 0 and z =0
Hence, ker T = {(0, 0, 0)}
and thus T is one-one.
Since R3 is a three dimensional (finite dimensional) vector space and T is a linear transformation from R3 to R3.
Hence, T is onto.
Therefore, T-1 exist.
Let (a, b, c) be the image of (x, y, z) under T-1 then T-1(x, y, z) = (a, b, c) Implies, T(a, b, c) = (x,y, z)
Using the definition of linear transformation T,
we get
(2a, 2a - 5b, 2b + c) = (x, y, z) Comparing the components of the co-ordinates,
we get 2a= x ,2a-5b = y and 2b + c = z
Solving for a, b and c we get,
Therefore
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Vaishnavi Verma upvoted • Feb 11, 2025 |
Consider the differential equation y" + 4y = 8cos2x , with y(0) = 0 and 
then y( π ) is equal to _________ .
Correct answer is '0'. Can you explain this answer?
Consider the differential equation y" + 4y = 8cos2x , with y(0) = 0 and then y( π ) is equal to _________ .
then y( π ) is equal to _________ .|
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Veda Institute answered |
We have
(D2 +4) y = 8 cos 2x
A . E.
⇒ y(x) = C1 cos 2x + C2 sin 2x + 2x sin 2x
y(0) = 0 ⇒ C1 = 0
y'(0) = 0 ⇒ 2C2 = 0 ⇒ C2 = 0
⇒ y(x) = 2x sin 2x
⇒ 
and y (π) = 0
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Vaishnavi Verma upvoted • Feb 06, 2025 |
The area of a quadrilateral, whose vertices are given by (x1, y1), (x2, y2), (x3, y3) and (x4, y4) respectively, is- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
The area of a quadrilateral, whose vertices are given by (x1, y1), (x2, y2), (x3, y3) and (x4, y4) respectively, is
a)
b)
c)
d)
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Veda Institute answered |
Comments on the Area of a Δand a quadrilateral
The above formula for the area of a triangle or a quadrilateral and are easy to remember.
Write the coordinates as shown below:
Note that the first written coordinate is repeated in the last. Multiply diagonally along arrows. Attach a positive sign if the arrow goes from left to right and a negative sign if the arrow goes from right to left.
The above formula for the area of a triangle or a quadrilateral and are easy to remember.
Write the coordinates as shown below:
Note that the first written coordinate is repeated in the last. Multiply diagonally along arrows. Attach a positive sign if the arrow goes from left to right and a negative sign if the arrow goes from right to left.
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Vaishnavi Verma upvoted • Jan 30, 2025 |
The value of 
where F = (x2 - y2)i + xyj and curve C is the arc of curve y = x3 from (0, 0) to (2, 8) is.... (Correction upto two decimal places)
Correct answer is '39.238'. Can you explain this answer?
The value of where F = (x2 - y2)i + xyj and curve C is the arc of curve y = x3 from (0, 0) to (2, 8) is.... (Correction upto two decimal places)
where F = (x2 - y2)i + xyj and curve C is the arc of curve y = x3 from (0, 0) to (2, 8) is.... (Correction upto two decimal places)|
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Veda Institute answered |
The curve C is the curve y=x3 from (0,0) to (2,8) Let x = t, Then y = t3. if 
is the position vector of any point (x,y) on c, then
is the position vector of any point (x,y) on c, then 
Also interms of t , 
At the point (0,0), t = x=0. At the point (2,8), t=2.
The solution eurves of the given differential equation xdx - dy = 0 are given by a family of- a)Parabolas
- b)Hyperbolas
- c)Circles
- d)Ellipses
Correct answer is option 'A'. Can you explain this answer?
The solution eurves of the given differential equation xdx - dy = 0 are given by a family of
a)
Parabolas
b)
Hyperbolas
c)
Circles
d)
Ellipses
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Vaishnavi Verma answered • Jan 11, 2025 |
Understanding the Differential Equation
The given differential equation is xdx - dy = 0. This can be rewritten as:
- dy = xdx
By rearranging this, we have:
- dy = xdx
This indicates a relationship between x and y.
Finding the General Solution
To solve the equation, we can integrate both sides:
- ∫ dy = ∫ xdx
This yields:
- y = (1/2)x... more
The given differential equation is xdx - dy = 0. This can be rewritten as:
- dy = xdx
By rearranging this, we have:
- dy = xdx
This indicates a relationship between x and y.
Finding the General Solution
To solve the equation, we can integrate both sides:
- ∫ dy = ∫ xdx
This yields:
- y = (1/2)x... more
Even numbers are formed with three digits such that if 5 is one of the digit then 7 is the next digit. The number of such numbers is (repetition is allowed).- a)360
- b)365
- c)325
- d)none
Correct answer is option 'B'. Can you explain this answer?
Even numbers are formed with three digits such that if 5 is one of the digit then 7 is the next digit. The number of such numbers is (repetition is allowed).
a)
360
b)
365
c)
325
d)
none
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Vaishnavi Verma answered • Sep 30, 2024 |
Understanding the Problem
To find the number of three-digit even numbers under the given conditions, we need to consider the following:
1. Three-Digit Even Numbers: The last digit must be even (0, 2, 4, 6, or 8).
2. Condition with Digit 5: If 5 appears in the number, then the next digit must be 7.
Analyzing the Digits
- Hundreds Place: Th... more
To find the number of three-digit even numbers under the given conditions, we need to consider the following:
1. Three-Digit Even Numbers: The last digit must be even (0, 2, 4, 6, or 8).
2. Condition with Digit 5: If 5 appears in the number, then the next digit must be 7.
Analyzing the Digits
- Hundreds Place: Th... more
The equation of the straight line passing through (4, 5) and parallel to the line 2x - 3y = 5 is given by- a)2 x - 3 y = 7
- b)2 x - 3 y = -7
- c)3 x - 2 y = 7
- d)3 x - 2 y = -7
Correct answer is option 'B'. Can you explain this answer?
The equation of the straight line passing through (4, 5) and parallel to the line 2x - 3y = 5 is given by
a)
2 x - 3 y = 7
b)
2 x - 3 y = -7
c)
3 x - 2 y = 7
d)
3 x - 2 y = -7
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Vaishnavi Verma answered • Jun 26, 2024 |
Given Information:
- Point (4, 5) passes through the line
- The line is parallel to 2x - 3y = 5
Explanation:
Finding the Gradient:
- To find the gradient of the given line 2x - 3y = 5, rearrange it into the slope-intercept form, y = mx + c.
- 2x - 3y = 5
- -3y = -2x + 5
- y = (2/3)x - 5/3
- The gradient of this line is... more
- Point (4, 5) passes through the line
- The line is parallel to 2x - 3y = 5
Explanation:
Finding the Gradient:
- To find the gradient of the given line 2x - 3y = 5, rearrange it into the slope-intercept form, y = mx + c.
- 2x - 3y = 5
- -3y = -2x + 5
- y = (2/3)x - 5/3
- The gradient of this line is... more
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Vaishnavi Verma asked • Jun 21, 2024 |
The Solution of 
is- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
The Solution of is
isa)
b)
c)
d)
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Veda Institute answered |
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Vaishnavi Verma asked • Jun 14, 2024 |
Let A be an n-by-n matrix with coefficients in F, having rows{a1, ..., an). Then which one of the statement is true for the matrix A?- a) A’ be a matrix obtained from A by an elementary row operation (interchanging two rows). Then D(A’) = –D(A)
- b) A’ be a matrix obtained from A by an elementary row operation (replacing the row ai by ai + λaj , with λ ∈ F, i ≠ j). Then D(A’) = D(A)
- c) A’ be a matrix obtained from A by an elementary row operation (replacing ai by µaj , for µ ≠ 0 in F). Then D(A’) = µD(A).
- d) All the three options are correct.
Correct answer is option 'D'. Can you explain this answer?
Let A be an n-by-n matrix with coefficients in F, having rows{a1, ..., an). Then which one of the statement is true for the matrix A?
a)
A’ be a matrix obtained from A by an elementary row operation (interchanging two rows). Then D(A’) = –D(A)
b)
A’ be a matrix obtained from A by an elementary row operation (replacing the row ai by ai + λaj , with λ ∈ F, i ≠ j). Then D(A’) = D(A)
c)
A’ be a matrix obtained from A by an elementary row operation (replacing ai by µaj , for µ ≠ 0 in F). Then D(A’) = µD(A).
d)
All the three options are correct.
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Veda Institute answered |
By a well known result we know that if A be an n × n matrix with coefficients in F, having rows {a1, a2, ....., an }, then the following statements are true.
(a) if A’ be a matrix obtained from A by an elementary row operation (interchanging two rows). Then
D(A’) = – D(A)
(b) if A’ be a matrix obtained from a by an elementary row operation (replacing the row ai by λaj , with λ ∈ F, i ≠ j). Then
D(A’) = D(A)
(c) if A’ be a matrix obtained from A by an elementary row operation (replacing ai by µai , for µ ≠ 0 in F). Then
D(A’) = µD(A)
i.e. all the three options are correct.
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Vaishnavi Verma asked • Jun 06, 2024 |
Which of the following statement is not true?- a)finite union of open sets is open
- b)finite intersection of open sets is open
- c)arbitrary union of open sets is open
- d)arbitrary intersection of open sets is open
Correct answer is option 'D'. Can you explain this answer?
Which of the following statement is not true?
a)
finite union of open sets is open
b)
finite intersection of open sets is open
c)
arbitrary union of open sets is open
d)
arbitrary intersection of open sets is open
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Veda Institute answered |
Let us consider An = 
then An is open for each n ∈ ℕ. But
is not open.If each of the pairs of straight lines x2 - 2pxy - y2 = 0 and x2 - 2qxy- y2 = 0 bisects the angles between the other pair, then- a)pq=1
- b)pq=-1
- c)p2=-q2
- d)p2q2 = -1
Correct answer is option 'B'. Can you explain this answer?
If each of the pairs of straight lines x2 - 2pxy - y2 = 0 and x2 - 2qxy- y2 = 0 bisects the angles between the other pair, then
a)
pq=1
b)
pq=-1
c)
p2=-q2
d)
p2q2 = -1
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Vaishnavi Verma answered • Mar 19, 2024 |
Explanation:
Given equations:
The given pair of equations are x^2 - 2pxy - y^2 = 0 and x^2 - 2qxy - y^2 = 0.
Angle bisectors:
To bisect the angles between the pair of lines, the lines themselves must be the angle bisectors of the other pair.
Applying the condition:
By applying the angle bisector condition to the given pairs of lines, we get:
For x^2 - 2pxy - y^2 = 0:
(1)^2 = (-2p)^2 - 1*(-1) => 1 = 4p^2 + 1 => 4p^2 = 0 => p^2 = 1/4
For x^2 - 2qxy - y^2 = 0:
(1)^2 = (-2q)^2 - 1*(-1) => 1 = 4q^2 + 1 => 4q^2 = 0 => q^2 = 1/4
Comparing p^2 and q^2:
From the above calculations, we can see that p^2 = q^2 = 1/4. Therefore, pq = (1/2)(1/2) = 1/4.
Conclusion:
Hence, the correct answer is pq = 1, which is represented by option 'B'.
?
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Vaishnavi Verma answered • Jan 24, 2024 |
IIT JAM Mathematics is a highly competitive exam conducted by the Indian Institutes of Technology (IITs) for admission to their M.Sc. programs in Mathematics. To prepare for this exam, it is important to have access to solved question papers and past year papers. These papers provide valuable insights into the exam pattern, types of questions asked, and help in identifying important topics.
<... more
<... more
Find the volume of the solid which is in the first octant bounded by the cylinder x^2+y^2=a^2 and y^2+z^2=a^2?
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Vaishnavi Verma answered • Dec 24, 2023 |
Problem:
Find the volume of the solid which is in the first octant bounded by the cylinder x^2 y^2=a^2 and y^2 z^2=a^2
Solution:
To find the volume of the solid bounded by the given surfaces, we need to set up a triple integral in Cartesian coordinates.
Step 1: Identifying the Boundaries
In the first octant, the boundaries for x, y, and z a... more
Find the volume of the solid which is in the first octant bounded by the cylinder x^2 y^2=a^2 and y^2 z^2=a^2
Solution:
To find the volume of the solid bounded by the given surfaces, we need to set up a triple integral in Cartesian coordinates.
Step 1: Identifying the Boundaries
In the first octant, the boundaries for x, y, and z a... more
Please delete my account.If not possible,then atleast stop sending me ur marketing mails.Dont send messages or calls to my number also.I am not at all interested in your courses.pls for the love of god?
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Vaishnavi Verma answered • Nov 30, 2023 |
Request to Delete Account and Stop Marketing Communication
I understand that you would like to delete your account and stop receiving marketing emails from us. I apologize for any inconvenience caused and assure you that we will comply with your request. Please find below the details on how we can proceed with your request:
Account Deletion:
To delete your ... more
I understand that you would like to delete your account and stop receiving marketing emails from us. I apologize for any inconvenience caused and assure you that we will comply with your request. Please find below the details on how we can proceed with your request:
Account Deletion:
To delete your ... more
Let v be the vector space of 2x2 matrices over R and let. M=[1 2;3 4] Let T be the linear operator on V defined by T(A)=MA. Then the trace of T is?
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Vaishnavi Verma answered • Nov 06, 2023 |
Trace of a Linear Operator
The trace of a linear operator is defined as the sum of the diagonal elements of the matrix representation of the operator. In this case, we are given a linear operator T on the vector space V of 2x2 matrices over the real numbers.
Matrix Representation of T
To find the matrix representation of T, we need to determine how T ... more
The trace of a linear operator is defined as the sum of the diagonal elements of the matrix representation of the operator. In this case, we are given a linear operator T on the vector space V of 2x2 matrices over the real numbers.
Matrix Representation of T
To find the matrix representation of T, we need to determine how T ... more
If inn(G) denote the inner automophism on G and Dn denote the dihedral group of order 2n.choose the correct option a) inn(D6) contains only two element of order three b) inn(D6) contains only two element of order 6 C) inn(D4)... more
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Vaishnavi Verma answered • Oct 25, 2023 |
Inner Automorphisms and Dihedral Groups
Definition: An automorphism of a group G is an isomorphism from G to itself. The set of all automorphisms of G, denoted Aut(G), forms a group under composition of functions.
Definition: An inner automorphism of a group G is an automorphism of the form φ_g(x) = gxg^(-1), where g is an element of G. The set of all inn... more
Definition: An automorphism of a group G is an isomorphism from G to itself. The set of all automorphisms of G, denoted Aut(G), forms a group under composition of functions.
Definition: An inner automorphism of a group G is an automorphism of the form φ_g(x) = gxg^(-1), where g is an element of G. The set of all inn... more
What is the probability that an urn containing 5 balls contains only white balls if the first two balls drawn from it was found to be white- a)1/20
- b)1/10
- c)1/2
- d)1/4
Correct answer is option 'C'. Can you explain this answer?
What is the probability that an urn containing 5 balls contains only white balls if the first two balls drawn from it was found to be white
a)
1/20
b)
1/10
c)
1/2
d)
1/4
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Vaishnavi Verma answered • Sep 29, 2023 |
To solve this problem, we can use the concept of conditional probability. Let's break down the problem step by step.
Step 1: Determine the total number of possible outcomes
The urn contains 5 balls, and each ball can either be white or not white (let's assume there are no other colors). Since there are two possibilities for each ball, the total number of possible outcomes is 2^5 = ... more
Step 1: Determine the total number of possible outcomes
The urn contains 5 balls, and each ball can either be white or not white (let's assume there are no other colors). Since there are two possibilities for each ball, the total number of possible outcomes is 2^5 = ... more
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Vaishnavi Verma asked • Sep 29, 2023 |
If a fair coin is tossed four times. What is the probability that two heads and two tails will result?- a)3/8
- b)1/2
- c)5/8
- d)3/4
Correct answer is option 'A'. Can you explain this answer?
If a fair coin is tossed four times. What is the probability that two heads and two tails will result?
a)
3/8
b)
1/2
c)
5/8
d)
3/4
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Veda Institute answered |
Here P(H) = P(T) = 1/2
It's a Bernoulli's trials.
∴ Required probability
It's a Bernoulli's trials.
∴ Required probability
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Vaishnavi Verma asked • Aug 17, 2023 |
Can I choose the specialization within the M.Sc. Physics program at the time of admission?
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Naina Rana answered |
Choosing a Specialization within the M.Sc. Physics Program at the Time of Admission
Introduction:
When applying for an M.Sc. Physics program, students often wonder if they can choose a specialization at the time of admission. The answer to this question may vary depending on the university or institution offering the program. However, in many cases, students do have the opti... more
Introduction:
When applying for an M.Sc. Physics program, students often wonder if they can choose a specialization at the time of admission. The answer to this question may vary depending on the university or institution offering the program. However, in many cases, students do have the opti... more
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Vaishnavi Verma asked • Aug 14, 2023 |
Can I get the answer key for the IIT JAM Mathematics in the form of a PDF or a downloadable file?
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Oishi Bajaj answered |
Answer:
Introduction:
The IIT JAM (Joint Admission Test for M.Sc.) is a national level exam conducted by the Indian Institutes of Technology (IITs) for admission to various postgraduate courses in science and technology. The Mathematics paper of IIT JAM consists of multiple-choice questions and is conducted for a duration of 3 hours.
Answer key for IIT J... more
The answer key for the IIT JAM Mathematics paper is a crucial resource for candidates to assess their performance in the exam and calculate their probable scores. It helps candidates to analyze their strengths and weaknesses and identify areas where they need improvement.
Availability:
The answer key for the IIT JAM Mathematics paper is usually released by various coaching institutes and educational platforms after the completion of the exam. It is commonly made available in the form of a PDF or downloadable file on their respective websites.
Benefits of answer key:
The answer key provides candidates with the correct answers to the questions asked in the exam. It allows them to compare their answers with the provided solutions and calculate their probable scores. Some of the benefits of using the answer key are:
1. Self-assessment: Candidates can evaluate their performance and gauge their level of preparation by matching their answers with the correct solutions.
2. Time management: The answer key helps candidates in analyzing the time they have spent on each question and identifying areas where they need to improve their speed.
3. Understanding mistakes: By comparing their answers with the correct solutions, candidates can identify and understand their mistakes. This helps them avoid similar mistakes in future exams.
4. Predicting rank: Using the answer key, candidates can estimate their probable rank based on their calculated scores. This gives them an idea about their chances of getting admission to their desired postgraduate courses.
Downloading the answer key:
To download the answer key for the IIT JAM Mathematics paper, you can follow these steps:
1. Visit the website of a reputed coaching institute or educational platform that provides the answer key for IIT JAM Mathematics.
2. Look for the section or link related to the answer key for the Mathematics paper.
3. Click on the link or download button to access the answer key.
4. The answer key will either open as a PDF file in your browser or will be downloaded to your device.
5. You can then save the PDF file or open it to view the correct answers to the questions asked in the exam.
Note: It is important to rely on trusted and reputable sources for the answer key to ensure accuracy and reliability of the solutions provided.
Conclusion:
The answer key for the IIT JAM Mathematics paper is a valuable resource for candidates to evaluate their performance and calculate their probable scores. It can be downloaded in the form of a PDF or downloadable file from the websites of reputed coaching institutes and educational platforms. By using the answer key effectively, candidates can assess their preparation, identify their mistakes, and improve their chances of getting admission to their desired postgraduate courses.
Introduction:
The IIT JAM (Joint Admission Test for M.Sc.) is a national level exam conducted by the Indian Institutes of Technology (IITs) for admission to various postgraduate courses in science and technology. The Mathematics paper of IIT JAM consists of multiple-choice questions and is conducted for a duration of 3 hours.
Answer key for IIT J... more
The answer key for the IIT JAM Mathematics paper is a crucial resource for candidates to assess their performance in the exam and calculate their probable scores. It helps candidates to analyze their strengths and weaknesses and identify areas where they need improvement.
Availability:
The answer key for the IIT JAM Mathematics paper is usually released by various coaching institutes and educational platforms after the completion of the exam. It is commonly made available in the form of a PDF or downloadable file on their respective websites.
Benefits of answer key:
The answer key provides candidates with the correct answers to the questions asked in the exam. It allows them to compare their answers with the provided solutions and calculate their probable scores. Some of the benefits of using the answer key are:
1. Self-assessment: Candidates can evaluate their performance and gauge their level of preparation by matching their answers with the correct solutions.
2. Time management: The answer key helps candidates in analyzing the time they have spent on each question and identifying areas where they need to improve their speed.
3. Understanding mistakes: By comparing their answers with the correct solutions, candidates can identify and understand their mistakes. This helps them avoid similar mistakes in future exams.
4. Predicting rank: Using the answer key, candidates can estimate their probable rank based on their calculated scores. This gives them an idea about their chances of getting admission to their desired postgraduate courses.
Downloading the answer key:
To download the answer key for the IIT JAM Mathematics paper, you can follow these steps:
1. Visit the website of a reputed coaching institute or educational platform that provides the answer key for IIT JAM Mathematics.
2. Look for the section or link related to the answer key for the Mathematics paper.
3. Click on the link or download button to access the answer key.
4. The answer key will either open as a PDF file in your browser or will be downloaded to your device.
5. You can then save the PDF file or open it to view the correct answers to the questions asked in the exam.
Note: It is important to rely on trusted and reputable sources for the answer key to ensure accuracy and reliability of the solutions provided.
Conclusion:
The answer key for the IIT JAM Mathematics paper is a valuable resource for candidates to evaluate their performance and calculate their probable scores. It can be downloaded in the form of a PDF or downloadable file from the websites of reputed coaching institutes and educational platforms. By using the answer key effectively, candidates can assess their preparation, identify their mistakes, and improve their chances of getting admission to their desired postgraduate courses.
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Vaishnavi Verma asked • Aug 07, 2023 |
Are there any books that focus on the most common mistakes made by candidates in the IIT JAM Mathematics Exam and how to avoid them?
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Radha Mehta answered |
There are several books available that focus on the most common mistakes made by candidates in the IIT JAM Mathematics Exam and provide guidance on how to avoid them. These books aim to help aspiring candidates understand the exam pattern, identify common pitfalls, and provide strategies to overcome them. Here are some popular books that you can consider:
1. "IIT JAM Mathematics Solved ... more
1. "IIT JAM Mathematics Solved ... more
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Vaishnavi Verma asked • Aug 02, 2023 |
What are the best techniques for memorizing formulas and theorems for the IIT JAM Mathematics Exam?
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Nakul Bajaj answered |
Techniques for Memorizing Formulas and Theorems for the IIT JAM Mathematics Exam
Create a Structured Study Plan
- Divide the syllabus into smaller sections and allocate specific time for each topic.
- Prioritize the formulas and theorems based on their importance and frequency of occurrence in previous exams.
Understand the Concepts
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