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Adeyeye DasolaEduRev Mathematics |
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Adeyeye Dasola
EduRev Mathematics
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Discussed Questions
Let 
Then- a)A is row equivalent to B only, when α = 2, β = 3 and γ = 4
- b)A is row equivalent to B only, when α ≠ 0, β ≠ 0 and γ = 0
- c)A is not row equivalent to B
- d)A is row equivalent to B for all values of α, β, γ
Correct answer is option 'A'. Can you explain this answer?
Let Then
Thena)
A is row equivalent to B only, when α = 2, β = 3 and γ = 4
b)
A is row equivalent to B only, when α ≠ 0, β ≠ 0 and γ = 0
c)
A is not row equivalent to B
d)
A is row equivalent to B for all values of α, β, γ
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Adeyeye Dasola answered • Sep 23, 2024 |
A
unit matrix|
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Adeyeye Dasola upvoted • Sep 23, 2024 |
If the eigen values of a square matrix be 1, - 2 and 3, then the eigen values of the matrix 3A are- a)1, - 2, 3
- b)3, - 6, 9
- c)1/3, - 2/3, 1
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
If the eigen values of a square matrix be 1, - 2 and 3, then the eigen values of the matrix 3A are
a)
1, - 2, 3
b)
3, - 6, 9
c)
1/3, - 2/3, 1
d)
none of these
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Tarun Singh answered |
Eigenvalues of a matrix and scalar multiplication
Given matrix A has eigenvalues 1, -2, and 3
We need to find the eigenvalues of the matrix 3A
To find the eigenvalues of 3A, we need to use the following formula:
If λ is an eigenvalue of A, then kλ is an eigenvalue of kA, where k is a scalar.
Therefore, the eigenvalues of 3A will be:
... more
Given matrix A has eigenvalues 1, -2, and 3
We need to find the eigenvalues of the matrix 3A
To find the eigenvalues of 3A, we need to use the following formula:
If λ is an eigenvalue of A, then kλ is an eigenvalue of kA, where k is a scalar.
Therefore, the eigenvalues of 3A will be:
... more
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Adeyeye Dasola upvoted • Sep 23, 2024 |
If a matrix A is such that 3 A3 + 2 A2 + 5 A + I = 0, then A-1 is equal to- a)- (3 A2 + 2 A + 5I)
- b)3 A2 + 2 A + 5I
- c)- 3 A2 - 2 A - 5
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
If a matrix A is such that 3 A3 + 2 A2 + 5 A + I = 0, then A-1 is equal to
a)
- (3 A2 + 2 A + 5I)
b)
3 A2 + 2 A + 5I
c)
- 3 A2 - 2 A - 5
d)
none of these
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Vikram Kapoor answered |
3A3 + 2A2 + 5A + I = 0
3A3 + 2A2 + 5A + AA−1 = 0
A−1 = −3A2 − 2A − 5
3A3 + 2A2 + 5A + AA−1 = 0
A−1 = −3A2 − 2A − 5
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