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Srijan SenguptaEduRev Chemistry |
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Srijan Sengupta
EduRev Chemistry
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Discussed Questions
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Srijan Sengupta upvoted • Aug 08, 2018 |
The acidity of protons H in each of the following is:
- a)I > II > III
- b)II > III > I
- c)II > I > III
- d)III > I > II
Correct answer is option 'C'. Can you explain this answer?
The acidity of protons H in each of the following is:
a)
I > II > III
b)
II > III > I
c)
II > I > III
d)
III > I > II
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Dinabandhu Das answered |
Though vacant d orbital in P is good idea but we could also thought of another way. I think in case of molecule 1 nitrogen capture the negative charge after protonation i.e. delocalization of the -ve charge in aromatic polycyclic ring will be less but in case of molecule 2 P have less electronegativity and hence delocalization of -ve charge can occur more easily with the aromatic rings. and in cas... more
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Srijan Sengupta upvoted • Jul 21, 2018 |
Can you explain the answer of this question below:In which of the following molecules, the mesomeric effect does not operate?- A:
- B:
- C:
- D:
The answer is a.
In which of the following molecules, the mesomeric effect does not operate?
A:
B:
C:
D:
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Megha Swami answered |
Then why not c
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Srijan Sengupta upvoted • Jul 21, 2018 |
He was one of my best __________ and I felt his loss _________.- a)friend, keenly
- b)friends, keen
- c)friend, keener
- d)friends, keenly
Correct answer is option 'D'. Can you explain this answer?
He was one of my best __________ and I felt his loss _________.
a)
friend, keenly
b)
friends, keen
c)
friend, keener
d)
friends, keenly
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Mrinalini Sen answered |
The phrase “one of” implies that you are describing a single (singular) thing out of many (plural) things. So the correct statements is “one of my best friends,”.
After “one of” always use plural countable noun like – “One of the students”. It is quite logical and straight forward- When we say one of, we assume that there are more than two.
For the reaction, 
The forward reaction at constant temperature is favoured by
(I) Introducing an inert gas at constant volume
(II) Introducing chlorine gas at constant volume
(III) Introducing an inert gas at constant pressure
(IV) Increasing the volume of the container
(V) Introducing PCl5 at constant volume- a)II and III
- b)III and IV
- c)II and V
- d)III and V
Correct answer is option 'A'. Can you explain this answer?
For the reaction,
The forward reaction at constant temperature is favoured by
(I) Introducing an inert gas at constant volume
(II) Introducing chlorine gas at constant volume
(III) Introducing an inert gas at constant pressure
(IV) Increasing the volume of the container
(V) Introducing PCl5 at constant volume
(I) Introducing an inert gas at constant volume
(II) Introducing chlorine gas at constant volume
(III) Introducing an inert gas at constant pressure
(IV) Increasing the volume of the container
(V) Introducing PCl5 at constant volume
a)
II and III
b)
III and IV
c)
II and V
d)
III and V
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Srijan Sengupta answered • Jul 01, 2018 |
I can't understand why option a is correct. If Cl2 is added then backward rxn will be favoured.
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Srijan Sengupta upvoted • Jun 30, 2018 |
If the ionic radii of K+ and F– are nearly the same (i., e. 1.34 Å), then the atomic radii of K and F respectively are:- a)1.34 Å, 1.34 Å
- b)0.72 Å, 1.96 Å
- c)1.96 Å, 0.72 Å
- d)1.96 Å, 1.34 Å
Correct answer is option 'C'. Can you explain this answer?
If the ionic radii of K+ and F– are nearly the same (i., e. 1.34 Å), then the atomic radii of K and F respectively are:
a)
1.34 Å, 1.34 Å
b)
0.72 Å, 1.96 Å
c)
1.96 Å, 0.72 Å
d)
1.96 Å, 1.34 Å
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Kaavya Sengupta answered |
If the ionic radii of K+ and F– are nearly the same (i., e. 1.34 Å), then the atomic radii of K and F respectively are:
a)1.34 Å, 1.34 Å
b)0.72 Å, 1.96 Å
c)1.96 Å, 0.72 Å
d)1.96 Å, 1.96 Å
Correct answer is option 'C'. Can you explain this answer?
When magnesium burns, in air, compounds of magnesium formed are magnesium oxide and:- a)Mg3N2
- b)MgCO3
- c)Mg(NO3)2
- d)MgSO4
Correct answer is 'A'. Can you explain this answer?
When magnesium burns, in air, compounds of magnesium formed are magnesium oxide and:
a)
Mg3N2
b)
MgCO3
c)
Mg(NO3)2
d)
MgSO4
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Srijan Sengupta answered • Jun 30, 2018 |
This is due to high abundance of nitrogen in atmosphere.....also the lattice energy of Mg3N2 is highest than other compounds this is because of size matching and symmetry a highly stable lattice of Mg3N2 will be formed....but the other so42- or co32- or no32- these are all large anions so they cannot form stable lattice with small Mg2+
The correct order of the boiling points of the compounds is :- a)CH4 > SiH4 > SnH4 > GeH4
- b)SiH4 > CH4 > GeH4 > SnH4
- c)SnH4 > GeH4 > CH4 > SiH4
- d)SnH4 > GeH4 > SiH4 > CH4
Correct answer is option 'D'. Can you explain this answer?
The correct order of the boiling points of the compounds is :
a)
CH4 > SiH4 > SnH4 > GeH4
b)
SiH4 > CH4 > GeH4 > SnH4
c)
SnH4 > GeH4 > CH4 > SiH4
d)
SnH4 > GeH4 > SiH4 > CH4
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Srijan Sengupta answered • Jun 30, 2018 |
Down the group the size of the central atom increases and bulkiness increases.....so the polarisability of the molecule increases....so possibility of formation of instantaneous dipole increases which incraeses the magnitude of dispersive force or london force among the molecules.....so snh4 has highest boiling point and decreases as we move up the group
Oxidation number of Co in [Co(NO)(CO)3] is:- a)1
- b)2
- c)3
- d)–1
Correct answer is option 'D'. Can you explain this answer?
Oxidation number of Co in [Co(NO)(CO)3] is:
a)
1
b)
2
c)
3
d)
–1
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Srijan Sengupta answered • Jun 30, 2018 |
Here can be a confusion that whether NO exists as NO+ or NO- .....CO is a π acid ligand so it accepts electron density from metal centre and so due to presence of 3 CO the metal centre is in somewhat oxidised state ....so NO releases one electron and causes one electron reduction of metal centre and NO exists as NO+ in this complex.....so coordination no. of Co is -1
The first ionization potential in electron volts of nitrogen and oxygen atoms are respectively given by:a)14.6, 13.6b)13.6, 14.6c)13.6, 13.6d)14.6, 14.6The correct answer is option 'A'. Can you explain this answer?
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Srijan Sengupta answered • Jun 29, 2018 |
The first ip value of N is greater than O because in N breaking of half filled 2p configuration is required which is very difficult and this does not occur for O
Can you explain the answer of this question below:In which of the following molecules, the mesomeric effect does not operate?- A:
- B:
- C:
- D:
The answer is a.
In which of the following molecules, the mesomeric effect does not operate?
A:
B:
C:
D:
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Srijan Sengupta answered • Jun 29, 2018 |
In option a the N atom is sp3 hybridised, and it has no vacant orbital to accept electron cloud from Ph ring......also this N atom does not have any lone pair of electrons to take part in conjugation with Ph ring.....so mesomeric effect does not operate here
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Shivansh Srivastava answered |
In case of 3 lone pair of O and N both delocalise into benzene ring so it has maximum e density in case of 1 lone pair of O delocalise into benzene ring so it has second highest e density in case of 4 +I group attached to benzene ring so it has third highest e density because resonance > I effect in case of 2 pi bond of benzene delocalise into O so it has least e density
Predict the major product P in the following reaction:
... more
Predict the major product P in the following reaction:
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Srijan Sengupta answered • Jun 29, 2018 |
At first the compound given in option c will be produced.....after that water will be released on elimination of the newly formed OH group and a H from the adjacent C atom containing the other OH group (elimination of the old OH group is not preferred as on elimination of new OH group more stable carbocation intermediate formed due to +I effect of CMe3 group).....after that the compound tautomeris... more
Most stable resonating structure of the given carbocation is: 
... more
Most stable resonating structure of the given carbocation is:
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Srijan Sengupta answered • Jun 29, 2018 |
Because in option c all the atoms have their octets fulfilled which is not in the case with the other options
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