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Monika YadavEduRev Chemistry |
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Monika Yadav
EduRev Chemistry
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Discussed Questions
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Monika Yadav upvoted • Feb 07, 2019 |
Favorable sites for protonation in following compound is/are:
- a)a*, b*, c*
- b)c*, d*
- c)b*, c*, d*
- d)a*, e*, b*
Correct answer is option 'C'. Can you explain this answer?
Favorable sites for protonation in following compound is/are:
a)
a*, b*, c*
b)
c*, d*
c)
b*, c*, d*
d)
a*, e*, b*
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Bhoomika Sharma answered |
If there is a pie bond just near an atom having lone pair, it's lone pair is localised and will not take part in resonance and hence they will be available for donation or Protonation.
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Monika Yadav upvoted • Jan 24, 2019 |
The electronic configurat ion of four elements are:
(I) [Kr]5s1
(II) [Rn]5f146d17s2
(III) [Ar]3d104s24s5
(IV) [Ar]3d64s2Consider the following statements:
(i) I shows variable oxidation state
(ii) II is a d-block element
(iii) The compound formed between I and III is covalent
(iv) IV shows single oxidation stateWhich statement is True(T) or Galse (F):... more
The electronic configurat ion of four elements are:
(I) [Kr]5s1
(II) [Rn]5f146d17s2
(III) [Ar]3d104s24s5
(IV) [Ar]3d64s2
(I) [Kr]5s1
(II) [Rn]5f146d17s2
(III) [Ar]3d104s24s5
(IV) [Ar]3d64s2
Consider the following statements:
(i) I shows variable oxidation state
(ii) II is a d-block element
(iii) The compound formed between I and III is covalent
(iv) IV shows single oxidation state
(i) I shows variable oxidation state
(ii) II is a d-block element
(iii) The compound formed between I and III is covalent
(iv) IV shows single oxidation state
Which statement is True(T) or Galse (F):
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Celin Kingsty answered |
1-1 it shows only +2 oxidation state
2-2 is an f block element
3-the bond formed is ionic because 1 is s block and ot is rb and 3 is a halide
4-it is a d block element showing multiple oxidation states
For the reaction:
the equilibrium constant at 2000 K and 1.0 bar is 5.25. When the pressure is increased by 8-fold, the equilibrium constant: - a)Increases by a factor of 1.86
- b)Decreases by a factor of 1.86
- c)Remains same
- d)Increases by factor of 8
Correct answer is option 'C'. Can you explain this answer?
For the reaction: the equilibrium constant at 2000 K and 1.0 bar is 5.25. When the pressure is increased by 8-fold, the equilibrium constant:
the equilibrium constant at 2000 K and 1.0 bar is 5.25. When the pressure is increased by 8-fold, the equilibrium constant: a)
Increases by a factor of 1.86
b)
Decreases by a factor of 1.86
c)
Remains same
d)
Increases by factor of 8
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Monika Yadav answered • Jan 24, 2019 |
Correct answer is 'c' .
because Keq is only affected by temperature and stoichiometry of reaction. not affected by other factors.
because Keq is only affected by temperature and stoichiometry of reaction. not affected by other factors.
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Monika Yadav upvoted • Jan 22, 2019 |
For the gas phase reaction.
Carried out in a vessel, the equilibrium concentration of C2H4 can be increased by
(I) Increasing the temperature
(II) Decreasing the pressure
(III) Removing some H2
(IV) Adding some C2H6- a)Only I and II
- b)Only III
- c)Only IV
- d)All are correct
Correct answer is option 'D'. Can you explain this answer?
For the gas phase reaction.
Carried out in a vessel, the equilibrium concentration of C2H4 can be increased by
(I) Increasing the temperature
(II) Decreasing the pressure
(III) Removing some H2
(IV) Adding some C2H6
(I) Increasing the temperature
(II) Decreasing the pressure
(III) Removing some H2
(IV) Adding some C2H6
a)
Only I and II
b)
Only III
c)
Only IV
d)
All are correct
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Prachi Dwivedi answered |
Question related to le-chatlier principle,always need to counterpart effect 1)rxn exothermic more heat on product side.On increasing temperature rxn go on that side where less heat i.e backward ,hence c2h4 increases
2) pressure reltd to no.of moles on decreaseing pressure rxn go on that side where pressure high i.e no.of moles high i.e backward again C2H4 rxn increase
3)H2 removal,rxn on... more
2) pressure reltd to no.of moles on decreaseing pressure rxn go on that side where pressure high i.e no.of moles high i.e backward again C2H4 rxn increase
3)H2 removal,rxn on... more
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Monika Yadav upvoted • Dec 06, 2018 |
T1/2 of a first order reaction is 60 minutes.the % left after 240 minute is?
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Priya answered |
1\16
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