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Rani EthapeMathematics student |
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Rani Ethape
EduRev Mathematics
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Currently preparing for
 | Mathematics |
 | Software Development |
 | Bank Exams |
 | SSC CHSL |
 | Class 6 |
| Sanskrit |
Top Scoring Tests by Rani
Indeterminate Form MCQ - 1 | 10/10 |
Sequences And Series Of Real Numbers -3 | 80/80 |
Linear Transform MCQ - 1 | 30/30 |
Linear Transform MCQ - 2 | 29/30 |
Matrix MCQ - 2 | 29/30 |
Matrix MCQ - 4 | 27/30 |
Sequences And Series Of Real Numbers -8 | 66/76 |
Matrix MCQ - 1 | 15/20 |
Sequences And Series Of Real Numbers -10 | 55/80 |
Sequences And Series Of Real Numbers -6 | 50/80 |
Discussed Questions
Let 
and 
be two linear transformation. Then which of the following can be true?- a)A and B are one one
- b)A is one one and B is not one one
- c)A is onto and B is one one
- d)A and B both are onto
Correct answer is option 'C'. Can you explain this answer?
Let and be two linear transformation. Then which of the following can be true?
and be two linear transformation. Then which of the following can be true?a)
A and B are one one
b)
A is one one and B is not one one
c)
A is onto and B is one one
d)
A and B both are onto
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Rani Ethape answered • Jan 22, 2025 |
In A every element of Range have pre image in Domain (onto)
and in B Domain has a unique image in Range (one one)
and in B Domain has a unique image in Range (one one)
Choose the correct matching from a, b. c and d for the transformation T1, T2 and T3 as defined in group I with the statements given in group II
- a)P - 3, Q - 2, R - 1
- b)P - 1, Q - 2, R - 3
- c)P - 3, Q - 1, R - 2
- d)P - 1, Q - 3, R - 2
Correct answer is option 'C'. Can you explain this answer?
Choose the correct matching from a, b. c and d for the transformation T1, T2 and T3 as defined in group I with the statements given in group II
a)
P - 3, Q - 2, R - 1
b)
P - 1, Q - 2, R - 3
c)
P - 3, Q - 1, R - 2
d)
P - 1, Q - 3, R - 2
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Rani Ethape answered • Jan 22, 2025 |
P : T1 =(x,x,0) ,y is an unknown , y is independent (Rank 1)
Q: Nullity is 0 and Range is 2 clearly (x, y= dim 2) [Rank 2]
R: because of x+1 this not LT
Q: Nullity is 0 and Range is 2 clearly (x, y= dim 2) [Rank 2]
R: because of x+1 this not LT
Let 
be linear transformation such that T ° S is the identity map of 
Then- a)S ° T is the identity map of IR4.
- b)S ° T is one one but not onto
- c)S ° T is onto but not one one
- d)S ° T is neither one one not onto
Correct answer is option 'D'. Can you explain this answer?
Let be linear transformation such that T ° S is the identity map of Then
be linear transformation such that T ° S is the identity map of Thena)
S ° T is the identity map of IR4.
b)
S ° T is one one but not onto
c)
S ° T is onto but not one one
d)
S ° T is neither one one not onto
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Rani Ethape answered • Jan 22, 2025 |
D
because In T R4 to R3 one element doesn't have a unique image in R3 (not one -one)
also where in S R4 don't have unique pre image in R3 not onto
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Rani Ethape upvoted • Jan 21, 2025 |
Let V be the space of twice differentiable functions of 
satisfying f" - 2f' + f = 0. Define 
by T(f) = (f'(0), f(0)).Then T is- a)one one and onto
- b)one one but not onto
- c)onto but not one one
- d)neither one one nor onto
Correct answer is option 'A'. Can you explain this answer?
Let V be the space of twice differentiable functions of satisfying f" - 2f' + f = 0. Define by T(f) = (f'(0), f(0)).Then T is
satisfying f" - 2f' + f = 0. Define by T(f) = (f'(0), f(0)).Then T isa)
one one and onto
b)
one one but not onto
c)
onto but not one one
d)
neither one one nor onto
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Suvojit Nayek answered |
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Rani Ethape upvoted • Jan 20, 2025 |
Consider the basis S = {v1, v2, v3} for 
where v1 = (1,1,1) and v2 = (1,1,0), v3 = (1,0,0) and let 
be a linear transformation such that T(v1) = (1,0), T (v2) = (2, -1), T (v3) = (4, 3). Then T (2, - 3, 5) is- a)(- 1, 5)
- b)(3,4)
- c)(0,0)
- d)(9,23)
Correct answer is option 'D'. Can you explain this answer?
Consider the basis S = {v1, v2, v3} for where v1 = (1,1,1) and v2 = (1,1,0), v3 = (1,0,0) and let be a linear transformation such that T(v1) = (1,0), T (v2) = (2, -1), T (v3) = (4, 3). Then T (2, - 3, 5) is
where v1 = (1,1,1) and v2 = (1,1,0), v3 = (1,0,0) and let be a linear transformation such that T(v1) = (1,0), T (v2) = (2, -1), T (v3) = (4, 3). Then T (2, - 3, 5) isa)
(- 1, 5)
b)
(3,4)
c)
(0,0)
d)
(9,23)
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Vishal Thakur answered |
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Rani Ethape upvoted • Jan 20, 2025 |
Let T:R2 -> R2 be the transformation T(x1,x2) = (x1,0). The null space (or kernel) N(T) of T is- a)(x1,0) : x1 is real
- b)1
- c)(0,1)
- d)(0,x2) : x2 is real
Correct answer is option 'D'. Can you explain this answer?
Let T:R2 -> R2 be the transformation T(x1,x2) = (x1,0). The null space (or kernel) N(T) of T is
a)
(x1,0) : x1 is real
b)
1
c)
(0,1)
d)
(0,x2) : x2 is real
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Aman Singh answered |
B/z for every x belong kernel T iff T (x) =0 now putting (x1,0) we ge x1=0while x2 can not be defined so d is correct
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Rani Ethape asked • Nov 07, 2024 |
Is there complex analysis in IIT jam mathematics?
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Krithika Chavan answered |
Understanding Complex Analysis in IIT JAM Mathematics
The IIT JAM (Joint Admission Test for M.Sc.) is an entrance examination conducted for admission to various postgraduate programs in physics, chemistry, mathematics, and more at IITs and other institutes. Complex analysis is a vital area of study in the mathematics syllabus.
Complex Analysis Overview
Complex analysis... more
The IIT JAM (Joint Admission Test for M.Sc.) is an entrance examination conducted for admission to various postgraduate programs in physics, chemistry, mathematics, and more at IITs and other institutes. Complex analysis is a vital area of study in the mathematics syllabus.
Complex Analysis Overview
Complex analysis... more
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