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A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?
- a)33.33%
- b)25%
- c)66.66%
- d)50%
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A dishonest shopkeeper cheats at time of buying and selling the produc...
Given that he cheats 20% at time of buying
⇒ Goods bought = 1000(1 + 20/100)
⇒ 1200 g at price of 1000 g
Given that he cheats 10% at time of buying
⇒ Goods sold = 1000(1 – 10/100)
⇒ 900g at price of 1000 g
Since cost price = selling price
⇒ Profit percentage = goods left/goods sold × 100
⇒ [(1200 – 900)/900] × 100%
⇒ [300/900] × 100%
⇒ [1/3] × 100%
⇒ 33.33%
∴ Profit percentage = 33.33%
Most Upvoted Answer
A dishonest shopkeeper cheats at time of buying and selling the produc...
Given:
- The shopkeeper cheats by weighing 20% more at the time of buying
- The shopkeeper cheats by weighing 10% less at the time of selling
To find: Total profit percentage
Solution:
Let us assume that the shopkeeper buys an item for Rs. 100 and sells it for Rs. x
At the time of buying:
- The shopkeeper weighs 20% more, so he pays for 120 grams instead of 100 grams (100 grams is the actual weight of the item)
- Cost price per gram = Rs. 100/120 = Rs. 0.83
At the time of selling:
- The shopkeeper weighs 10% less, so he sells 90 grams instead of 100 grams (100 grams is the actual weight of the item)
- Selling price per gram = Rs. x/90
Profit percentage = ((Selling price - Cost price) / Cost price) * 100
Substituting the values, we get:
Profit percentage = (((x/90) - 0.83) / 0.83) * 100
Simplifying the above expression, we get:
Profit percentage = ((10x - 747) / 747) * 100
For the shopkeeper to make a profit, the selling price must be greater than the cost price, i.e. x > 100
To maximize the profit percentage, we need to find the value of x that gives the highest profit percentage.
By taking the derivative of the profit percentage expression with respect to x and equating it to 0, we get:
10x - 747 = 0
x = 74.7
Therefore, the selling price should be Rs. 74.7 for the shopkeeper to make the maximum profit.
Substituting this value of x in the profit percentage expression, we get:
Profit percentage = ((10*74.7 - 747) / 747) * 100 = 33.33%
Therefore, the total profit percentage for the shopkeeper is 33.33%.
Answer: Option A (33.33%)
- The shopkeeper cheats by weighing 20% more at the time of buying
- The shopkeeper cheats by weighing 10% less at the time of selling
To find: Total profit percentage
Solution:
Let us assume that the shopkeeper buys an item for Rs. 100 and sells it for Rs. x
At the time of buying:
- The shopkeeper weighs 20% more, so he pays for 120 grams instead of 100 grams (100 grams is the actual weight of the item)
- Cost price per gram = Rs. 100/120 = Rs. 0.83
At the time of selling:
- The shopkeeper weighs 10% less, so he sells 90 grams instead of 100 grams (100 grams is the actual weight of the item)
- Selling price per gram = Rs. x/90
Profit percentage = ((Selling price - Cost price) / Cost price) * 100
Substituting the values, we get:
Profit percentage = (((x/90) - 0.83) / 0.83) * 100
Simplifying the above expression, we get:
Profit percentage = ((10x - 747) / 747) * 100
For the shopkeeper to make a profit, the selling price must be greater than the cost price, i.e. x > 100
To maximize the profit percentage, we need to find the value of x that gives the highest profit percentage.
By taking the derivative of the profit percentage expression with respect to x and equating it to 0, we get:
10x - 747 = 0
x = 74.7
Therefore, the selling price should be Rs. 74.7 for the shopkeeper to make the maximum profit.
Substituting this value of x in the profit percentage expression, we get:
Profit percentage = ((10*74.7 - 747) / 747) * 100 = 33.33%
Therefore, the total profit percentage for the shopkeeper is 33.33%.
Answer: Option A (33.33%)
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A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?a)33.33%b)25%c)66.66%d)50%Correct answer is option 'A'. Can you explain this answer? for Railways 2025 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?a)33.33%b)25%c)66.66%d)50%Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Railways 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?a)33.33%b)25%c)66.66%d)50%Correct answer is option 'A'. Can you explain this answer?.
A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?a)33.33%b)25%c)66.66%d)50%Correct answer is option 'A'. Can you explain this answer? for Railways 2025 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?a)33.33%b)25%c)66.66%d)50%Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Railways 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dishonest shopkeeper cheats at time of buying and selling the products. He weights 20% more at time of buying and 10% less at time of selling. What is his total profit?a)33.33%b)25%c)66.66%d)50%Correct answer is option 'A'. Can you explain this answer?.
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