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On a circular table, A and B are moving on the circumference. Man A runs behind man B to catch him A runs with constant angular speed ω1 with respect to table and B runs at constant tangential speed v2 with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation between A and B is 30°, then A catches B after : (Radius of table is 3 m).
- a)0.5 sec, if ω1 = 4π/3 rad/s and v2 = 6.28 m/s
- b)A can not catch B within 0.5 sec ω1 = π/6 rad/s and v2 = 6.28 m/s
- c)0.5 sec, if ω1 = 4π/3 rad/s and v2 = 3.14 m/s
- d)0.5 sec, if ω1 = 5π/6 rad/s and v2 = 3.14 m/s
Correct answer is option 'B,D'. Can you explain this answer?
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On a circular table,AandBare moving on the circumference. ManAruns beh...
The correct answers are: 0.5 sec, if
A can not catch B within 0.5 sec 
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On a circular table,AandBare moving on the circumference. ManAruns beh...
If A runs behind B to catch him, it means that A is trying to reach the same point on the circumference of the circular table where B is currently located.
Since A runs with a constant angular speed, it means that A covers the same angle in the same amount of time regardless of their position on the circle. This implies that A moves faster when B is farther away and slower when B is closer.
If B is moving at a constant speed on the circumference, it means that B covers the same distance in the same amount of time regardless of their position on the circle.
Therefore, if A runs behind B to catch him, A needs to cover the same distance as B in the same amount of time. In order to do this, A needs to adjust their speed according to the distance between A and B. A will run faster when B is farther away and slower when B is closer.
In summary, A runs with a constant angular speed but varies their linear speed to catch up with B on the circular table.
Since A runs with a constant angular speed, it means that A covers the same angle in the same amount of time regardless of their position on the circle. This implies that A moves faster when B is farther away and slower when B is closer.
If B is moving at a constant speed on the circumference, it means that B covers the same distance in the same amount of time regardless of their position on the circle.
Therefore, if A runs behind B to catch him, A needs to cover the same distance as B in the same amount of time. In order to do this, A needs to adjust their speed according to the distance between A and B. A will run faster when B is farther away and slower when B is closer.
In summary, A runs with a constant angular speed but varies their linear speed to catch up with B on the circular table.
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On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer?.
On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer?.
Solutions for On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
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Here you can find the meaning of On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer?, a detailed solution for On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? has been provided alongside types of On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice On a circular table,AandBare moving on the circumference. ManAruns behind manBto catch himAruns with constant angular speedω1with respect to table andBruns at constant tangential speedv2with respect to ground. If it is found that the table rotates 30° in the opposite direction in every one second and the initial angular separation betweenAandBis 30°, thenAcatchesBafter : (Radius of table is 3m).a)0.5sec, ifω1 = 4π/3rad/sand v2 = 6.28 m/sb)A can not catchBwithin 0.5 secω1 =π/6rad/sand v2 = 6.28 m/sc)0.5sec, ifω1 = 4π/3rad/sand v2 = 3.14 m/sd)0.5sec, ifω1 = 5π/6rad/sand v2 = 3.14 m/sCorrect answer is option 'B,D'. Can you explain this answer? tests, examples and also practice Physics tests.
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