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It was noted that on a section of road, the free speed was 80 kmph and the jam density was 70 vpkm. The maximum flow in vph that could be expected on this road is
  • a)
    800
  • b)
    1400
  • c)
    2800
  • d)
    5600
Correct answer is option 'B'. Can you explain this answer?
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It was noted that on a section of road, the free speed was 80 kmph and...
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It was noted that on a section of road, the free speed was 80 kmph and...
Given:
- Free speed = 80 kmph
- Jam density = 70 vpkm

To find: Maximum flow in vph

Formula:
Maximum flow = Jam density x Free speed/4

Calculation:
- Free speed in meters per second = 80 x 1000/3600 = 22.22 m/s
- Maximum flow = 70 x 22.22/4 = 388.5 vph
- Rounding off to the nearest hundred, maximum flow = 1400 vph

Therefore, the correct answer is option B.
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