All Exams >
JEE >
Weekly Tests for JEE Preparation >
All Questions
All questions of June Week 4 for JEE Exam
and A2 + aA + b = O, then the values of a and b are:
Two cells of 1.25 V and 0.75V are connected in parallel. The effective voltage will be- a)0.5 V
- b)2.00 V
- c)1.25 V
- d)0.75 V
Correct answer is option 'A'. Can you explain this answer?
Two cells of 1.25 V and 0.75V are connected in parallel. The effective voltage will be
a)
0.5 V
b)
2.00 V
c)
1.25 V
d)
0.75 V
|
Anjana Sharma answered |
When two cells are conneted in parallel , then
Effective Voltage,V = V1 − V2 = 1.25 − 0.75 = 0.5 V
At any junction, the sum of the currents entering the junction is equal to the sum of _______- a)potential around any closed loop
- b)voltages across the junction
- c)all the currents in the circuit
- d)currents leaving the junction
Correct answer is option 'D'. Can you explain this answer?
At any junction, the sum of the currents entering the junction is equal to the sum of _______
a)
potential around any closed loop
b)
voltages across the junction
c)
all the currents in the circuit
d)
currents leaving the junction
|
Om Kumar answered |
The correct answer is option 'D': currents leaving the junction.
Explanation:
At any junction in an electrical circuit, the sum of the currents entering the junction is equal to the sum of the currents leaving the junction. This is based on the principle of conservation of charge.
When current flows through a junction, it must split into multiple paths. The total amount of charge entering the junction must be equal to the total amount of charge leaving the junction. This is because charge cannot be created or destroyed, it can only flow through the circuit.
To better understand this concept, consider a simple circuit with three branches connected to a junction. Let's label the currents entering the junction as I1, I2, and I3, and the currents leaving the junction as I4, I5, and I6.
The principle of conservation of charge states that the total amount of charge entering the junction must be equal to the total amount of charge leaving the junction. Mathematically, this can be expressed as:
I1 + I2 + I3 = I4 + I5 + I6
This equation shows that the sum of the currents entering the junction (I1 + I2 + I3) is equal to the sum of the currents leaving the junction (I4 + I5 + I6).
This principle is a consequence of Kirchhoff's current law (KCL), which states that the algebraic sum of currents at any junction in an electrical circuit is zero. This means that the sum of currents entering the junction is equal to the sum of currents leaving the junction.
In summary, at any junction in an electrical circuit, the sum of the currents entering the junction is equal to the sum of the currents leaving the junction. This principle is based on the conservation of charge and is a consequence of Kirchhoff's current law.
Explanation:
At any junction in an electrical circuit, the sum of the currents entering the junction is equal to the sum of the currents leaving the junction. This is based on the principle of conservation of charge.
When current flows through a junction, it must split into multiple paths. The total amount of charge entering the junction must be equal to the total amount of charge leaving the junction. This is because charge cannot be created or destroyed, it can only flow through the circuit.
To better understand this concept, consider a simple circuit with three branches connected to a junction. Let's label the currents entering the junction as I1, I2, and I3, and the currents leaving the junction as I4, I5, and I6.
The principle of conservation of charge states that the total amount of charge entering the junction must be equal to the total amount of charge leaving the junction. Mathematically, this can be expressed as:
I1 + I2 + I3 = I4 + I5 + I6
This equation shows that the sum of the currents entering the junction (I1 + I2 + I3) is equal to the sum of the currents leaving the junction (I4 + I5 + I6).
This principle is a consequence of Kirchhoff's current law (KCL), which states that the algebraic sum of currents at any junction in an electrical circuit is zero. This means that the sum of currents entering the junction is equal to the sum of currents leaving the junction.
In summary, at any junction in an electrical circuit, the sum of the currents entering the junction is equal to the sum of the currents leaving the junction. This principle is based on the conservation of charge and is a consequence of Kirchhoff's current law.
The Wheatstone bridge Principle is deduced using- a)Gauss’s Law
- b)Kirchhoff’s Laws
- c)Coulomb’s Law
- d)Newton’s Laws
Correct answer is option 'B'. Can you explain this answer?
The Wheatstone bridge Principle is deduced using
a)
Gauss’s Law
b)
Kirchhoff’s Laws
c)
Coulomb’s Law
d)
Newton’s Laws
|
|
Anjana Sharma answered |
PRINCIPLE: Wheatstone bridge principle states that when the bridge is balanced, the product of the resistance of the opposite arms are equal. The files that I had attached in which I had derived Wheatstone bridge equation using Kirchhoff law is useful to you.
Can you explain the answer of this question below:The ______ of changes in potential around any closed loop involving resistors and cells in a loop is zero.- A:product
- B:algebraic sum
- C:difference
- D:sum of absolute values
The answer is b.
The ______ of changes in potential around any closed loop involving resistors and cells in a loop is zero.
A:
product
B:
algebraic sum
C:
difference
D:
sum of absolute values
|
Lavanya Menon answered |
In accordance with Kirchhoff’s second law i.e. Kirchhoff’s voltage law (KVL), the algebraic sum of all the potential differences in a closed electric circuit or closed loop that contains one or more cells and resistors is always equal to zero.
This law is popularly called the law of conservation of voltage.
This law is popularly called the law of conservation of voltage.
The cofactor of 5 in 
- a)3
- b)29
- c)-3
- d)5
Correct answer is option 'C'. Can you explain this answer?
The cofactor of 5 in
a)
3
b)
29
c)
-3
d)
5
|
Sai Kulkarni answered |
A21 = {(0, -1) (3,4)}
⇒ (0 - (-3)) = 3
A21 = (-1)(2+1) (3)
= -3
⇒ (0 - (-3)) = 3
A21 = (-1)(2+1) (3)
= -3
If A = 
, and |3A| = k|A|, then the value of k is- a)27
- b)1
- c)25
- d)4
Correct answer is option 'A'. Can you explain this answer?
If A = , and |3A| = k|A|, then the value of k is
, and |3A| = k|A|, then the value of k isa)
27
b)
1
c)
25
d)
4
|
Vikas Kapoor answered |
|kA| = kn|A|
|3A| = (3)n |A|
= 27|A| = k|A|
k = 27
|3A| = (3)n |A|
= 27|A| = k|A|
k = 27
The cofactor of an element 9 of the determinant 
is :- a)48
- b)– 48
- c)27
- d)46
Correct answer is option 'B'. Can you explain this answer?
The cofactor of an element 9 of the determinant is :
is :a)
48
b)
– 48
c)
27
d)
46
|
Sushil Kumar answered |
Co factor of element 9 will be {(6 * 8) -(-5 * 0)}
= 48
= 48
If 
, then the relation between x and y is- a)y = -3x
- b)x = 3y
- c)x = -3y
- d)y = 3x
Correct answer is option 'D'. Can you explain this answer?
If , then the relation between x and y is
, then the relation between x and y isa)
y = -3x
b)
x = 3y
c)
x = -3y
d)
y = 3x
|
Poonam Reddy answered |
½{(0,0,1) (1,3,1) (x,y,1)} = 0
{(0,0,1) (1,3,1) (x,y,1)} = 0/(½)
{(0,0,1) (1,3,1) (x,y,1)} = 0
0(3-y) -0(1-x) +1(y-3x) = 0
=> y - 3x = 0
=> y = 3x
{(0,0,1) (1,3,1) (x,y,1)} = 0/(½)
{(0,0,1) (1,3,1) (x,y,1)} = 0
0(3-y) -0(1-x) +1(y-3x) = 0
=> y - 3x = 0
=> y = 3x
Given N resistors each of resistance R are first combined to get minimum possible resistance and then combined to get maximum possible resistance. The ratio of the minimum to maximum resistance is- a)N
- b)N2
- c)1/N2
- d)1/N
Correct answer is option 'C'. Can you explain this answer?
Given N resistors each of resistance R are first combined to get minimum possible resistance and then combined to get maximum possible resistance. The ratio of the minimum to maximum resistance is
a)
N
b)
N2
c)
1/N2
d)
1/N
|
Nishtha Bose answered |
They are connected in series to get maximum in this case resistance would be nr
and to get minimun resistance they are connected in parallel :. resistance in this case is n/r
:. ratio between minimum and maximum resistance is n/r/nr = 1/r^2
Inverse of a matrix A exists, if- a)| A | = 0
- b)Matrix A is non-singular
- c)Matrix A is singular
- d)AT = A
Correct answer is option 'B'. Can you explain this answer?
Inverse of a matrix A exists, if
a)
| A | = 0
b)
Matrix A is non-singular
c)
Matrix A is singular
d)
AT = A
|
Jayant Mishra answered |
If the determinant of the matrix is zero, then it will not have an inverse; the matrix is then said to be singular. Only non-singular matrices have inverses. Find the inverse of the Matrix A is non-singular
The minor Mij of an element aij of a determinant is defined as the value of the determinant obtained after deleting the- a)jth row of the determinant
- b)ith column and jth row of the determinant
- c)ith row and jth column of the determinant
- d)ith row of the determinant
Correct answer is option 'C'. Can you explain this answer?
The minor Mij of an element aij of a determinant is defined as the value of the determinant obtained after deleting the
a)
jth row of the determinant
b)
ith column and jth row of the determinant
c)
ith row and jth column of the determinant
d)
ith row of the determinant
|
Amrita Sen answered |
A minor, Mij, of the element aij is the determinant of the matrix obtained by deleting the ith row and jth column.
, then adj A is:
If 
and Aij are cofactors of aij, then- a)Δ = a11A11 + a21A22 + a31A33
- b)Δ = a11A31 + a12A32 + a13A33
- c)Δ = a11A11 + a12A12 + a13A13
- d)Δ = a11A11 + a22A22 + a33A33
Correct answer is option 'C'. Can you explain this answer?
If and Aij are cofactors of aij, then
and Aij are cofactors of aij, thena)
Δ = a11A11 + a21A22 + a31A33
b)
Δ = a11A31 + a12A32 + a13A33
c)
Δ = a11A11 + a12A12 + a13A13
d)
Δ = a11A11 + a22A22 + a33A33
|
Muskaan Mishra answered |
Δ = Sum of products of element of row(or column) with their corresponding co-factors.
Δ = a11 A11 + a21 A21 + a31 A31
Δ = a11 A11 + a21 A21 + a31 A31
of the reaction to be completed?
hours
further
hours.The hypothetical reaction 
follows the following mechanism 
, 
The order of the overall reaction is- a)0
- b)1
- c)2
- d)
Correct answer is option 'D'. Can you explain this answer?
The hypothetical reaction follows the following mechanism , The order of the overall reaction is
follows the following mechanism , The order of the overall reaction isa)
0
b)
1
c)
2
d)
|
Manish Aggarwal answered |
;
(Fast);
(Slow)Rate law
put value of 
from Ist reaction since 
is intermediate
Rate law equation 
Order 
Find the value of 
- a)-1
- b)1
- c)2
- d)0
Correct answer is option 'D'. Can you explain this answer?
Find the value of
a)
-1
b)
1
c)
2
d)
0
|
Aarya Rane answered |
Correct Answer :- d
Explanation:- 3(6-6) -2(6-9) +3(4-6)
= 3(0) + 6 - 6
= 0
, rate constant is 
. If we start with 
of A then conc. of 
and B after 10 minuter are respectively.
Chapter doubts & questions for June Week 4 - Weekly Tests for JEE Preparation 2025 is part of JEE exam preparation. The chapters have been prepared according to the JEE exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of June Week 4 - Weekly Tests for JEE Preparation in English & Hindi are available as part of JEE exam.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily