All Exams >
Class 10 >
Weekly Tests for Class 10 Preparation >
All Questions
All questions of October Week 4 for Class 10 Exam
A circle can pass through
- a)2 collinear points
- b)3 collinear points
- c)4 collinear points
- d)4 collinear points
Correct answer is option 'A'. Can you explain this answer?
A circle can pass through
a)
2 collinear points
b)
3 collinear points
c)
4 collinear points
d)
4 collinear points
|
Krishna Iyer answered |
The answer can be 2 collinear points as well. We have three collinear points. Join one point to the other two points and then draw the perpendicular bisector for both the lines
Join the perpendicular bisectors. The point is the centre of the circle. And a circle can be formed then. Also two points can form a circle as the two points joines becomes a diameter.
Join the perpendicular bisectors. The point is the centre of the circle. And a circle can be formed then. Also two points can form a circle as the two points joines becomes a diameter.
Option D : The number of circles which can pass through three given non-collinear points is exactly one.
So, A is the correct Option
In fig., two circles with centres A and B touch each other externally at k. The length of PQ (in cm) is
- a)24 cm
- b)20 cm
- c)27 cm
- d)18 cm
Correct answer is option 'C'. Can you explain this answer?
In fig., two circles with centres A and B touch each other externally at k. The length of PQ (in cm) is
a)
24 cm
b)
20 cm
c)
27 cm
d)
18 cm
|
Vikas Kumar answered |
Constructions - join AS and join BT.
Case 1 (triangle ASP)
We know, ∠ASP = 900 (radius is perpendicular to tangent at point of contact)
So, in triangle ASP,
AP2 = PS2 + AS2
=> 132 = 122 + AS2
=> 169 = 144 + AS2
+> AS2 = 169 - 144 = 25
=> AS = √25 = 5cm
Since AS is radius, AP = Ak = 5 cm.
Case 2 (triangle BTQ)
We know, ∠BTQ = 900 (radius is perpendicular to tangent at point of contact)
So, in triangle BTQ,
BQ2 = QT2 + BT2
= 52 = 32 + BT2
=> 25 = 9 + BT2
=> BT2 = 25 - 9 = 9
=> BT = √16 = 4cm
Since BT is radius, BT = Bk 4cm
Now, PQ = AP + Ak + Bk + BQ
=> PQ = 13 + 5 + 4 + 5
=> PQ = 27 cm
A tangent PA is drawn from an external point P to a circle of radius 3√2 cm such that the distance of the point P from O is 6 cm as shown figure. The value of ∠APO is
- a)30°
- b)60°
- c)45°
- d)75°
Correct answer is option 'C'. Can you explain this answer?
A tangent PA is drawn from an external point P to a circle of radius 3√2 cm such that the distance of the point P from O is 6 cm as shown figure. The value of ∠APO is
a)
30°
b)
60°
c)
45°
d)
75°
|
Sushil Kumar answered |
The correct answer is c
In right angled triangle, OAP
sin of angle APO = AO/OP = 1/root2
sin 45 = 1/root2
angle APO = 45 degree
A circle may have…….- a)2 tangent
- b)1 tangent
- c)Infinite tangents
- d)No tangent
Correct answer is option 'C'. Can you explain this answer?
A circle may have…….
a)
2 tangent
b)
1 tangent
c)
Infinite tangents
d)
No tangent
|
|
Vedashree V answered |
Because a tangent intersect only one point on circle so it can form infinite tangents
If figure 1, O is the centre of a circle, PQ is a chord and PT is the tangent at P. If ∠POQ = 70o, then ∠TPQ is equal to
- a)45°
- b)5°
- c)35°
- d)70°
Correct answer is 'C'. Can you explain this answer?
If figure 1, O is the centre of a circle, PQ is a chord and PT is the tangent at P. If ∠POQ = 70o, then ∠TPQ is equal to
a)
45°
b)
5°
c)
35°
d)
70°
|
Ananya Das answered |
POQ is an isosceles triangle because of 2 radii as sides. So by angle sum property, 2*angle OPQ=180-70=110
Angle OPQ=55°
Since Angle TPO is a right angle , because PT is a tangent,
Angle OPQ+Angle TPQ=90
Angle TPQ=90° - 55° = 35°
Angle OPQ=55°
Since Angle TPO is a right angle , because PT is a tangent,
Angle OPQ+Angle TPQ=90
Angle TPQ=90° - 55° = 35°
The length of the tangent drawn from a point 8 cm away from the centre of a circle, of radius 6 cm, is :- a)10 cm
- b)5 cm
- c)√7 cm
- d)2√7 cm
Correct answer is option 'D'. Can you explain this answer?
The length of the tangent drawn from a point 8 cm away from the centre of a circle, of radius 6 cm, is :
a)
10 cm
b)
5 cm
c)
√7 cm
d)
2√7 cm
|
Dronacharya Institute answered |
Since tangent is perpendicular to radius, the triangle so formed is a right angled triangle,
So using Pythagoras Theorem,
Line joining centre and And the point outside the circle is hypotenuse and tangent and radius are the two sides
H2=P2+B2
64=P2+36
P=
So using Pythagoras Theorem,
Line joining centre and And the point outside the circle is hypotenuse and tangent and radius are the two sides
H2=P2+B2
64=P2+36
P=
Which local govt works at district level ?- a)Panchayat samiti
- b)Village panchayat
- c)Zila Parishad
- d)None of the mention above
Correct answer is option 'C'. Can you explain this answer?
Which local govt works at district level ?
a)
Panchayat samiti
b)
Village panchayat
c)
Zila Parishad
d)
None of the mention above
|
|
Kiran Mehta answered |
Zilla Parishad is located at the apex of the Panchayat system at the district level. It consists of the Chairman of the Panchayat Samities as ex-officio Members, M.L.As, M.P.s of the area. Representatives of women, scheduled castes and tribes and backward class are co-opted as members.
How many tangents can be drawn to a circle from a point in its interior?- a)One
- b)Two
- c)infinite
- d)None
Correct answer is option 'D'. Can you explain this answer?
How many tangents can be drawn to a circle from a point in its interior?
a)
One
b)
Two
c)
infinite
d)
None
|
Shiva Tiwari answered |
Tangent can only be drawn from outside.and from a point outside the circle only two tangent can be drawn
From a point A, the length of a tangent to a circle is 8cm and distance of A from the circle is 10cm. The length of the diameter of the circle is
- a)6 cm
- b)12 cm
- c)16 cm
- d)14 cm
Correct answer is option 'B'. Can you explain this answer?
From a point A, the length of a tangent to a circle is 8cm and distance of A from the circle is 10cm. The length of the diameter of the circle is
a)
6 cm
b)
12 cm
c)
16 cm
d)
14 cm
|
|
Himaja Ammu answered |
Angle APO=90[radius is always perpendicular to the tangent)]
now by Pythagoras theorem AO^2=AP^2+OP^2
10^2=8^2+OP^2
OP^2=36
OP=6cm
here OP is nothing but the radius of circle
we know diameter is twice the radius...so
diameter=(2×6)=12 cm
now by Pythagoras theorem AO^2=AP^2+OP^2
10^2=8^2+OP^2
OP^2=36
OP=6cm
here OP is nothing but the radius of circle
we know diameter is twice the radius...so
diameter=(2×6)=12 cm
Number of tangents, that can be drawn to a circle, parallel to a given chord is- a)3
- b)Zero
- c)Infinite
- d)2
Correct answer is option 'D'. Can you explain this answer?
Number of tangents, that can be drawn to a circle, parallel to a given chord is
a)
3
b)
Zero
c)
Infinite
d)
2
|
Gaurav Kumar answered |
There are only two tangents that can be drawn parallel to a given chord. That is the tangents are drawn on either side of the chord so that both are parallel to the chord.
The tangents drawn at the ends of a diameter of a circle are:- a)intersecting at a point inside the circle
- b)perpendicular
- c)intersecting at the centre of the circle
- d)parallel
Correct answer is option 'D'. Can you explain this answer?
The tangents drawn at the ends of a diameter of a circle are:
a)
intersecting at a point inside the circle
b)
perpendicular
c)
intersecting at the centre of the circle
d)
parallel
|
Rahul Kapoor answered |
Here AB is a diameter of the circle with centre O, two tangents PQ and RS drawn at points A and B respectively.
Radius will be perpendicular to these tangents.
Thus, OA ⊥ RS and OB ⊥ PQ
∠OAR = ∠OAS = ∠OBP = ∠OBQ = 90degree
Therefore,
∠OAR = ∠OBQ (Alternate interior angles)
∠OAS = ∠OBP (Alternate interior angles)
Since alternate interior angles are equal, lines PQ and RS will be parallel.
What is the government at Block level called ?- a)Gram Sabha
- b)Gram Panchyat
- c)Panchayat Samiti
- d)Nayay Panchyat
Correct answer is option 'C'. Can you explain this answer?
What is the government at Block level called ?
a)
Gram Sabha
b)
Gram Panchyat
c)
Panchayat Samiti
d)
Nayay Panchyat
|
|
Kiran Mehta answered |
A Panchayat Samiti (block panchayat) is a local government body at the tehsil level. This body works for the villages of the tehsil that together are called a "development block". The Panchayat Samiti is the link between the Gram Panchayat and the district administration.
By what name local govt at urban area called?A) Municipality B) Municipal corporation C) Panchayat samiti- a)Only A is true
- b)Only B is true
- c)Both B and C are true
- d)Both A and B are true
Correct answer is option 'D'. Can you explain this answer?
By what name local govt at urban area called?
A) Municipality B) Municipal corporation C) Panchayat samiti
a)
Only A is true
b)
Only B is true
c)
Both B and C are true
d)
Both A and B are true
|
Bhavana Sen answered |
The urban area don't have local governments they have muncipality to manage the city in hindi nagar palika.
In the figure, the pair of tangents AP and AQ, drawn from an external point A to a circle with centre O, are perpendicular to each other and length of each tangent is 4 cm, then the radius of the circle is
- a)10 cm
- b)4 cm
- c)7.5 cm
- d)2.5 cm
Correct answer is option 'B'. Can you explain this answer?
In the figure, the pair of tangents AP and AQ, drawn from an external point A to a circle with centre O, are perpendicular to each other and length of each tangent is 4 cm, then the radius of the circle is
a)
10 cm
b)
4 cm
c)
7.5 cm
d)
2.5 cm
|
|
Arun Yadav answered |
Join OA.
Triangles OPA and OQA are congruent.
⇒∠PAO = ∠QAO = 45o
Tangent and radius are perpendicular at the point of contact.
∠OPA = 90o
⇒∠OAP = ∠AOP = 45o
⇒OP = AP = 4cm
So the radius of the circle is 4 cm.
The angle between two tangents drawn from an external point to a circle is 110°. The angle subtended at the centre by the segments joining the points of contact to the centre of circle is:- a)70°
- b)90°
- c)55°
- d)110°
Correct answer is option 'A'. Can you explain this answer?
The angle between two tangents drawn from an external point to a circle is 110°. The angle subtended at the centre by the segments joining the points of contact to the centre of circle is:
a)
70°
b)
90°
c)
55°
d)
110°
|
Divisha mehta answered |
Degrees.
This is a common result in geometry, known as the "angle between tangents theorem." It states that the angle between two tangents drawn from an external point to a circle is equal to the measure of the arc they intercept on the circle.
In this case, we know that the two tangents intersect an arc of measure 110 degrees on the circle. Therefore, the angle between the tangents is also 110 degrees.
This is a common result in geometry, known as the "angle between tangents theorem." It states that the angle between two tangents drawn from an external point to a circle is equal to the measure of the arc they intercept on the circle.
In this case, we know that the two tangents intersect an arc of measure 110 degrees on the circle. Therefore, the angle between the tangents is also 110 degrees.
A line that intersects a circle in exactly one point is called a- a)Diameter
- b)Tangent
- c)Radius
- d)Chord
Correct answer is option 'B'. Can you explain this answer?
A line that intersects a circle in exactly one point is called a
a)
Diameter
b)
Tangent
c)
Radius
d)
Chord
|
|
Aditya Kumar answered |
A TANGENT IS THE ONLY LINE WHICH INTERSECT CIRCLE AT ONLY ONE POINT.
A line that intersects a circle in two distinct points is called a- a)Tangent
- b)Chord
- c)Diameter
- d)Secant
Correct answer is option 'D'. Can you explain this answer?
A line that intersects a circle in two distinct points is called a
a)
Tangent
b)
Chord
c)
Diameter
d)
Secant
|
|
Krishna Iyer answered |
A chord is the actual line segment determined by these two points, that is, the interval on the secant whose ends are at these positions But a secant of a curve is a line that intersects the curve at a minimum of two distinct points. The difference is that the secant is not just limited to the circle it extends further.
A light ray strikes a plane mirror at an angle of incidence of 35°. What is the angle of reflection?- a)35°
- b)55°
- c)90°
- d)70°
Correct answer is option 'A'. Can you explain this answer?
a)
35°
b)
55°
c)
90°
d)
70°
|
EduRev Class 10 answered |
According to the Law of Reflection, the angle of incidence is always equal to the angle of reflection. Therefore, if a light ray strikes a plane mirror at an angle of incidence of 35°, the angle of reflection will also be 35°.
What happens to the number of images formed as the angle between two mirrors decreases in multiple reflections?- a)The number of images decreases
- b)The number of images remains the same
- c)The number of images increases
- d)The number of images becomes infinite
Correct answer is option 'C'. Can you explain this answer?
a)
The number of images decreases
b)
The number of images remains the same
c)
The number of images increases
d)
The number of images becomes infinite
|
Nk Classes answered |
As the angle between two mirrors decreases, the number of images formed increases. This is because a smaller angle results in more reflections within the mirror setup, leading to a higher number of images being visible.
What happens to the image formed by a spherical mirror when the mirror's curvature changes?- a)The image size remains constant
- b)The image position changes
- c)The image shape changes
- d)The image becomes blurry
Correct answer is option 'B'. Can you explain this answer?
a)
The image size remains constant
b)
The image position changes
c)
The image shape changes
d)
The image becomes blurry
|
Kds Coaching answered |
When the curvature of a spherical mirror changes, the position of the image also changes. This is because the curvature affects how light is focused, which in turn alters where the image is formed.
An object is placed 5 cm in front of a plane mirror. Calculate the distance between the object and its image formed by the mirror.- a)5 cm
- b)10 cm
- c)15 cm
- d)20 cm
Correct answer is option 'B'. Can you explain this answer?
An object is placed 5 cm in front of a plane mirror. Calculate the distance between the object and its image formed by the mirror.
a)
5 cm
b)
10 cm
c)
15 cm
d)
20 cm
|
|
Kds Coaching answered |
When an object is placed in front of a plane mirror:
The image appears to be the same distance behind the mirror as the object is in front of it.
If the object is 5 cm in front of the mirror, the image will be 5 cm behind the mirror.
The total distance between the object and its image is the sum of these two distances.
Thus, the total distance is 5 cm (object to mirror) + 5 cm (mirror to image) = 10 cm.
Therefore, the correct answer is:
B: 10 cm
The image appears to be the same distance behind the mirror as the object is in front of it.
If the object is 5 cm in front of the mirror, the image will be 5 cm behind the mirror.
The total distance between the object and its image is the sum of these two distances.
Thus, the total distance is 5 cm (object to mirror) + 5 cm (mirror to image) = 10 cm.
Therefore, the correct answer is:
B: 10 cm
Who is the chairperson of Municipal Corporation?- a)Block development officer
- b)Mayor
- c)Sarpanch
- d)Member of Lok Sabha
Correct answer is option 'B'. Can you explain this answer?
Who is the chairperson of Municipal Corporation?
a)
Block development officer
b)
Mayor
c)
Sarpanch
d)
Member of Lok Sabha
|
|
Anjali Kapoor answered |
The Mayor is the head of the municipal corporation, but the role is largely ceremonial as executive powers are vested in the municipal commissioner. The office of the Mayor combines a functional role of chairing the Corporation meeting as well as ceremonial role associated with being the First Citizen of the city.
What is the distance between two parallel tangents of a circle of the radius 4 cm?- a)8 cm
- b)4 cm
- c)2 cm
- d)6 cm
Correct answer is option 'A'. Can you explain this answer?
What is the distance between two parallel tangents of a circle of the radius 4 cm?
a)
8 cm
b)
4 cm
c)
2 cm
d)
6 cm
|
|
El Cerebro answered |
Let O is the centre of the circle. l and m are two parallel tangents of the circle.
Radius of the circle = 4cm
Distance between two parallel tangents
= AB
= OA + OB
= 4cm + 4cm
= 8cm
Thus, distance between the parallel tangents land m is 8cm.
Radius of the circle = 4cm
Distance between two parallel tangents
= AB
= OA + OB
= 4cm + 4cm
= 8cm
Thus, distance between the parallel tangents land m is 8cm.
The length of tangent drawn from an external point P to a circle, with centre O, is 8 cm. If the radius of the circle is 6 cm, then the length of OP (in cm) is:- a)10 cm
- b)2√7 cm
- c)10.5 cm
- d)4√7 cm
Correct answer is option 'A'. Can you explain this answer?
The length of tangent drawn from an external point P to a circle, with centre O, is 8 cm. If the radius of the circle is 6 cm, then the length of OP (in cm) is:
a)
10 cm
b)
2√7 cm
c)
10.5 cm
d)
4√7 cm
|
Pardeep Singh answered |
By Pythagoras theorm
H²=B²+P²
H² =8²+6²
H=√100
H=10
H²=B²+P²
H² =8²+6²
H=√100
H=10
What type of image is formed by a plane mirror?- a)Real and inverted
- b)Virtual and erect
- c)Real and erect
- d)Virtual and inverted
Correct answer is option 'B'. Can you explain this answer?
a)
Real and inverted
b)
Virtual and erect
c)
Real and erect
d)
Virtual and inverted
|
|
Kds Coaching answered |
A plane mirror always forms a virtual and erect image. The size of the image is equal to the size of the object, and the image is as far behind the mirror as the object is in front of it. Additionally, the image formed is laterally inverted.
A tangent to a circle is a line that intersects the circle in- a)Exactly one point
- b)2 points
- c)3 points
- d)4 points
Correct answer is option 'A'. Can you explain this answer?
A tangent to a circle is a line that intersects the circle in
a)
Exactly one point
b)
2 points
c)
3 points
d)
4 points
|
Hariteja Patnala answered |
A line that intersects a circle in exactly one point is called a tangent and the point where the intersection occurs is called the point of tangency. The tangent is always perpendicular to the radius drawn to the point of tangency
In the figure, if from an external point T, TP and TQ are two tangents to a circle with centre O so that POQ = 110°, then, PTQ is:
- a)80°
- b)60°
- c)70°
- d)90°
Correct answer is option 'C'. Can you explain this answer?
In the figure, if from an external point T, TP and TQ are two tangents to a circle with centre O so that POQ = 110°, then, PTQ is:
a)
80°
b)
60°
c)
70°
d)
90°
|
|
Drishti Rana answered |
Correct answer is 70 degree.
as in fig.the angles P and Q are 90 degrees and angle POQ is 110 degree , so angle T + P + O + Q = 360.degree (angles sum property of quadrilateral)..
Then angle T + 90 + 110 + 90 = 360, so angle PTQ = 70 degree ...
as in fig.the angles P and Q are 90 degrees and angle POQ is 110 degree , so angle T + P + O + Q = 360.degree (angles sum property of quadrilateral)..
Then angle T + 90 + 110 + 90 = 360, so angle PTQ = 70 degree ...
Number of tangents from a point lying inside the circle is- a)Two
- b)One
- c)Infinitely many
- d)None
Correct answer is option 'D'. Can you explain this answer?
Number of tangents from a point lying inside the circle is
a)
Two
b)
One
c)
Infinitely many
d)
None
|
|
Lucifer Morning Star answered |
Tangent is a line that touches the circle at exactly one point, never entering inside the circle. So, there is no tangent to a circle passing through a point lying inside the circle.
so obviously Correct answer is option D
so obviously Correct answer is option D
The distance between two parallel tangents to a circle of radius 5 cm is- a)5cm
- b)8cm
- c)10cm
- d)9cm
Correct answer is option 'C'. Can you explain this answer?
The distance between two parallel tangents to a circle of radius 5 cm is
a)
5cm
b)
8cm
c)
10cm
d)
9cm
|
|
Abhish answered |
Two parallel tangents will lie on the diameter
since radius is 5 cm
diameter = 10 cm
hence distance between both the tangents will be 10 cm
since radius is 5 cm
diameter = 10 cm
hence distance between both the tangents will be 10 cm
Reflection of Light:
(i) The angle of incidence is always equal to the angle of reflection.
(ii) The reflected ray is the ray that bounces back after striking a surface.
(iii) The incident ray is the ray that gets absorbed by a polished surface.
(iv) The normal is a line perpendicular to the reflecting surface.
The correct statements are:- a)(i) and (ii)
- b)(iii) and (iv)
- c)(i), (ii) and (iv)
- d)(i) and (iv)
Correct answer is option 'C'. Can you explain this answer?
Reflection of Light:
(i) The angle of incidence is always equal to the angle of reflection.
(ii) The reflected ray is the ray that bounces back after striking a surface.
(iii) The incident ray is the ray that gets absorbed by a polished surface.
(iv) The normal is a line perpendicular to the reflecting surface.
The correct statements are:
(i) The angle of incidence is always equal to the angle of reflection.
(ii) The reflected ray is the ray that bounces back after striking a surface.
(iii) The incident ray is the ray that gets absorbed by a polished surface.
(iv) The normal is a line perpendicular to the reflecting surface.
The correct statements are:
a)
(i) and (ii)
b)
(iii) and (iv)
c)
(i), (ii) and (iv)
d)
(i) and (iv)
|
Get Idea answered |
- Statement (i) is correct as per the Law of Reflection that states the angle of incidence is always equal to the angle of reflection.
- Statement (ii) is correct because the reflected ray is indeed the ray that bounces back after striking the surface.
- Statement (iii) is incorrect because the incident ray is the ray of light that falls on the surface, not the one that gets absorbed.
- Statement (iv) is correct as the normal is defined as a line perpendicular to the reflecting surface. Thus, the correct statements are (i), (ii) and (iv).
Chapter doubts & questions for October Week 4 - Weekly Tests for Class 10 Preparation 2025 is part of Class 10 exam preparation. The chapters have been prepared according to the Class 10 exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Class 10 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of October Week 4 - Weekly Tests for Class 10 Preparation in English & Hindi are available as part of Class 10 exam.
Download more important topics, notes, lectures and mock test series for Class 10 Exam by signing up for free.
Weekly Tests for Class 10 Preparation
23 docs|109 tests
|
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily